KELOMPOK 9 SUSUNAN : 1. Muhammad Al Fath Pradipta Siwi 2. Anggita Dwitaningrum 3. Wiratni 4. Faishal Farras Atha
1.
(B100180070) (B100180076) (B100180112) (B100180118)
a. β«(πππ + ππ) dx 4
=
8
π₯8 +
3
π₯8 +
3
1
=
2
π₯2 + C
2 2
π₯2 + C
b. β«(πππ + ππ) dx 8
π₯4 +
1
= 2π₯ 4 +
1
=
4
2 2
π₯2 + C π₯2 + C
c. β«(ππ + ππ) dx = =
2.
1 5 1 5
π₯5 +
4 2
π₯2 + C
π₯ 5 + 2π₯ 2 + C
π
a. β«π (ππ + π) dx 3
3
= β«1 π₯ 4 dx + β«1 3 dx =
1 5
π₯ 5 ]13 + 3π₯ ]13
1
1
5
5
= ( (3)5 β =( =
243 5
242 5
β
+6
= 49, 6
1 5
(1)5 ) + (3(3) β 3 (1))
) + (9-3)
π
b. β«π (πππ + π) dx 5
5
= β«4 2π₯ 3 dx + β«4 5 dx 5
2
5
= π₯ 4 ]4 + 5π₯ ]4 4
1
1
2
2
= ( (5)4 β = (
625 2
β
256 2
(4)4 ) + (5(5) β 5 (4))
) + (25-20)
= (184, 5 + 5) = 189,5
π
c. β«π (πππ + π) dx 5
5
= β«2 2π₯ 3 dx + β«2 + 4 dx 5
2
5
= π₯ 4 ]2 +4π₯ ]2 4
1
1
2
2
= ( (5)4 β = (
625 2
β
16 2
(2)4 ) + (4(5) β 4(2))
) + (20-8)
= (304,5 + 12) = 316,5
3. π· β‘ π πβ‘
15 β 3π
= π
πβ3
=
βπ = β3 β π π β1 π =3+π π·=π 15 β 3π = 3 + π 12 = 4π 3 = π β ππ π = 3 β π = 15 β 3π = 15 β 3(3) = 6 β ππ
π
πΆπ = β«0 π π(π₯) ππ₯ β ππ β ππ 3
= β«0 (15 β 3π )ππ₯ β 3 β 6 3
3
= β«0 15 ππ₯ β β«0 3π ππ₯ β 18 3 = 15 π ] β 0
3 2
3 π₯ 2 ] β 18 0 3
3
2
2
= (15(3) β 15(0)) β ( (3)2 β = 45 β 13,5 = 31,5 ππ
ππ = ππ β ππ β β«0 π (π₯) ππ₯ 3
= 3 β 6 β β«0 3 + π₯ ππ₯ 3
3
= 18 β β«0 3 ππ₯ + β«0 π₯ ππ₯
(0)2 ) β 18
3 = 18 β 3π₯] + 0
3 π₯2] 2 0 1
1
1
2
2
= 18 β (3(3) β 3 (0)) + ( (3)2 β
(0)2 )
= 18 β (9 + 4, 5) = 18 + 4,5 = 13,5
4. π = 15 β 3π₯
ππππ
π=6 ππ
6 = 15 β 3π₯
ππ₯
= β3
π₯=3 ππ₯ ππ
=β
1 3
β9 = β3π₯ 3=π₯ Besarnya elastisitas permintaan akan barang ini adalah: π
Harga :
π
β
ππ₯ ππ
6
= ββ 3
1 3
6
2
9
3
=β ββ
besarnya elastisitas akan barang ini adalah bila p : 6 dp dx
x:2
= 1 =>
harga
:
dx dp
p x 6
.
= 1
dx dp
: .1 3
:
6 3