Bab 7 Balok Miring 2.ppt

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Balok dengan beban Momen

A Av

B MB

X x

Bv

LL

Dx

Av

Bv

-

M A v   B (ke bawah ) L ΣMA=0

Bidang D Mx

-Bv . L + MB=0

Bidang M

ΣMB=0 Av . L + MB=0

MB

M Bv  B ( ke atas ) L

Tinjauan titik x ( 0  x  L ) MX = A v . x

Persamaan garis lurus miring

dMx Dx=------ = Av . x dx

X x

Av

Persamaan garis lurus mendatar

P = 20 kN

q = 10 kN/m datar B

300

C Bv Q=10.8

A Av

4m

2m

2m

33,3 20

40 x 20

66,7 20

q = 10 kN/m

P = 20 kN

B C

Bv

300 A Av

4m D=0

20

x N=0

2m

2m

q = 10 kN/m

P = 20 kN

B C

Bv

300 A Av

4m

2m

2m MB

M B

M

MA

X

M

C

x

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