Tugas4 Mik106 Aljabar Linier.docx

TUGAS4 MIK106 ALJABAR LINIER AGUNG PRATAMA (NIM: 20170310028)

Diketahui matriks: 3 1 2 𝐴 = [1 −2 −9] 4 3 1 Tentukan: a. Minor b. Kofaktor c. Adjoin JAWAB a. Minor DIKALI

−2 −9 M11 = | |  -2 – (-27) = 25 3 1 1 −9 M12 = | |  1 – (-36) = 37 4 1 1 −2 M13 = | |  3 – (-8) = 11 4 3 1 3 M21 = | |  1 – 6 = -5 2 1 3 M22 = | 4

2 |  3 – 8 = -5 1

3 M23 = | 4

1 |9–4=5 3

1 2 M31 = | |  -9 – (-4) = -5 −2 −9 3 2 M32 = | |  -27 – 3 = -30 1 −9 3 1 M33 = | |  -6 – 1 = -7 1 −2

b. Kofaktor C11 = + |

−2 −9 |  + (-2 – (-27)) = 25 3 1

1 C12 = - | 4 C13 = + |

−9 |  - (1 – (-36)) = -37 1

1 −2 |  + (3 – (-8)) = 11 4 3

1 C21 = - | 2

3 |  - (1 – 6) = 5 1

3 C22 = + | 4

2 |  + (3 – 8) = -5 1

C23 = - |

3 1 |  - (9 – 4) = -5 4 3

C31 = + |

1 2 |  + (-9 – (-4)) = -5 −2 −9

3 C32 = - | 1 C33 = + |

2 |  - (-27 – 3) = 30 −9

3 1 |  + (-6 – 1) = -7 1 −2

Maka, Matriks Kofaktornya : 25 −37 11 C=| 5 −5 −5| −5 30 −7

c. Adjoin 25 5 −5 CT = |−37 −5 30 | 11 −5 −7