Soal Absorsi No2(jawab).xlsx

amonia awal amonia akhir Gas total in air bebas amonia= Gas bersih(tanpa amonia)/G= Gas bersih(tanpa amonia)/G= Gas bersih(tanpa amonia)/G=

3.52% 1.29% 1540 75 1485.792 42062.77152 PV/RT 3.8515815094 75

Air bebas amonia/L= PV/RT

4.1666666667 amonia(G awal)

1534.62848 0.1405220451

amonia(G akhir) amonia(G akhir)

542.609752608 0.0496854015

X Y Xawal Y awal

mol amonia/mol air mol amonia/mol gas bersih

Yakhir Xakhir

mol amonia sisa(1,29%)/mol gas bersih= mol amonia yg terabsorsi/mol air bersih= mol yg ter absorsi=

0 0.0364842454

maka X akhir=

T= ft^3/jam lb/jam ft^3/jam l/jam mol/jam mol/jam gram/jam mol/jam mol/jam

68 F rho air 43597.4 l/jam 1.2019230769 ft^3/jam

1lb

1538.0918784 l/jam mol/jam l/jam mol/jam

29%)/mol gas bersih= absorsi/mol air bersih= mol awal-mol akhir amonia pada gas

0.0129 0.0908366436

0.0218007945 mol/jam

293 Kelvin 62.4 lb/ft^3 1 ft^3= Tekanan= 1 R= 0.082 0.45 kg 0.00045 g

28.31 L atm