Eksponen Dan Logaritma
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Mr. Ged
Eksponen dan Logaritma
ac = b
a
⇔
log b = c
Syarat :
Rumus-rumus Eksponen 1.
a 0 = 1 (a ≠ 0)
2.
a m . a n = a m+n
3.
a . b m = ( a . b) m
4. 5.
( a m ) n = a m.n
6.
a−m =
m
> 0 dan
2.
b
>0
a
≠1
Rumus-rumus Logaritma a
log a = 1
a
log1 = 0
a
log b + a log c = a log b . c
a
log b − a log c = a log
a
log b . b log c = a log c
1. 2. 3.
m
4. 5.
1 am
6.
n
am = am / n
7.
m
a .m b = m a.b
8.
7.
9.
a
m
am m− n a : a = n =a a
8.
1.
m n
a
a = a1/ m.n
(a)
=b
a
log bn = n . a log b
a
log b =
a
9.
a
10.
log b
an
log b n
n
log b log a
log b =
n
log b =
b
1 log a
“bila ada kemauan pasti ada seribu jalan, tetapi bila tidak ada kemauan pasti ada seribu alasan”
b c
Eksponen dan Logaritma
ac = b
a
⇔
log b = c
Syarat :
Rumus-rumus Eksponen 1.
a 0 = 1 (a ≠ 0)
2.
a m . a n = a m+n
3.
a . b m = ( a . b) m
4. 5.
( a m ) n = a m.n
6.
a−m =
m
> 0 dan
2.
b
>0
a
≠1
Rumus-rumus Logaritma a
log a = 1
a
log1 = 0
a
log b + a log c = a log b . c
a
log b − a log c = a log
a
log b . b log c = a log c
1. 2. 3.
m
4. 5.
1 am
6.
n
am = am / n
7.
m
a .m b = m a.b
8.
7.
9.
a
m
am m− n a : a = n =a a
8.
1.
m n
a
a = a1/ m.n
(a)
=b
a
log bn = n . a log b
a
log b =
a
9.
a
10.
log b
an
log b n
n
log b log a
log b =
n
log b =
b
1 log a
“bila ada kemauan pasti ada seribu jalan, tetapi bila tidak ada kemauan pasti ada seribu alasan”
b c
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