Analisis Numerico Debr 1.docx
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ANÁLISIS NUMÉRICO EJERCICIO 2 metnewton1 Reemplazando R=3, V= 30m3 Tenemos la siguiente ecuación π𝑥 3 − 9πx 2 + 90 = 0 derivando obtenemos 3π𝑥 2 − 18πx = 0 Valor inicial V= Ah h=V/A 𝐴 = π𝑅 2 𝐴 = π ∗ 32
ℎ=
30 28,27
= 1,06103m
Al ver la gráfica de los errores podemos ver que converge cuadráticamente.
Y que la raíz x= h para este caso es x=h= 2,0269 m
EJERCICO 1
ℎ=
30 28,27
= 1,06103m
Al ver la gráfica de los errores podemos ver que converge cuadráticamente.
Y que la raíz x= h para este caso es x=h= 2,0269 m
EJERCICO 1
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