Engineering Mathematics 3
FIRST ORDER DIFFERETIAL EQUATIOS
Exactness Method Grade 50% off the total score within the first week after due date. Zero score after the first week. Name : Group: Subject: Topic: Date Due: Date of Submission:
Question 1.3.1
(
2
Question 1.3.8
)
(
Solve 2x⋅ y⋅ dx + 1 + x dy = 0
)
3
Solve 2t + 3y dt + ( 3t + y − 1) ⋅ dy = 0.
2
Ans: K = x ⋅ y + y
Ans: K =
1 4 1 2 ⋅ t + 3⋅ t⋅ y − y + ⋅ y 2 2
Question 1.3.2 Solve ( x + sin( y) ) ⋅ dx + ( x⋅ cos( y) − 2y) ⋅ dy = 0. 1 2 2 ⋅ x + sin( y) ⋅ x − y 2
Ans: K =
Question 1.3.3
(
2
)
Solve ( 2x⋅ y + x) ⋅ dx + x + y ⋅ dy = 0. 1 2 1 3 ⋅x + ⋅y 2 2
2
Ans: K = x ⋅ y +
Question 1.3.4
(
3
)
(
2 2
)
Solve y + 2⋅ x⋅ y dx + 1 + 3⋅ x ⋅ y + x ⋅ dy = 0 . 2 3
Ans: K = x⋅ y + x ⋅ y + y
Question 1.3.9
(
x⋅ y
Solve y⋅ e
x⋅ y
dx + x⋅ e
)
2
Solve t − y dt − t⋅ dy = 0 .
Question 1.3.5 dy = 0.
Ans: K = exp( x⋅ y)
Question 1.3.6
Ans: K =
1 3 ⋅ t − t⋅ y 3
Question 1.3.10
(
3t
)
3t
Solve y⋅ dx + x⋅ dy = 0.
Solve 3⋅ e ⋅ y − 2t dt + e dy = 0
Ans: K = x⋅ y
Ans: exp( 3⋅ t) ⋅ y − t
2
Question 1.3.7 Solve ( y⋅ sin( x) + x⋅ y⋅ cos( x) ) dx + ( x⋅ sin( x) + 1) dy = 0. Ans: K = − cos( x) ⋅ y + ( cos( x) + x⋅ sin( x) ) ⋅ y + y
20094em3 Exercise 13.mcd
Copyright 2008 - 2009
1/1