Engineering Mathematics 3
FIRST ORDER DIFFERETIAL EQUATIOS
Linear Equation Using Integrating Factor Grade 50% off the total score within the first week after due date. Zero score after the first week. Name : Group: Subject: Topic: Date Due: Date of Submission:
Section A (rhs = 0) Question 1.4.1 Solve y' - 5y = 0 .
− 5x
y⋅ e
Ans: Question 1.4.2 1 Q=0 . Solve Q' + 20
1 20
=k
x
Ans:
y⋅ e
Ans:
y⋅ exp− t +
=k
Question 1.4.3 dy + ( t − 1) ⋅ y = 0 . Solve dt
1 2 ⋅t = K 2
Section B (rhs is nonzero) Question 1.4.4 Solve y' − 3y = 6 at y(1) = 0. Ans:
y⋅ exp( −3⋅ x) = − 2⋅ exp( −3⋅ x) + 2⋅ exp( − 3)
Ans:
v⋅ exp( 25⋅ t) = .3920⋅ exp( 25.⋅ t) + 56.13
Question 1.4.5 Solve v' + 25⋅ v = 9.8 at v(0.1) = 5.
Question 1.4.6 3 Q=2 . Solve Q' + 100 − t
Q
Ans:
( 100 − t) 20094em3 Exercise 14.mcd
Copyright 2008 - 2009
1 3
= ( 100 − t)
2
+k
1/3
Engineering Mathematics 3
Question 1.4.7 2 Q=4 . Solve Q' + 10 + 2t 2
Q⋅ ( 10 + 2⋅ t) = 40⋅ t + 4⋅ t + k
Ans: Question 1.4.8 dy 3 − 2y = x ⋅ cos( 4x) . Solve x⋅ dx Remark: De is not in the linear standard form. Conversion is necessary. Ans
Question 1.4.9 2 2 4 Solve x' − x = t . t 3
y=
1 2 ⋅ sin( 4⋅ x) + k ⋅ x 4
; x(t): x is a function of t.
x = 54⋅
Ans
1 13 ⋅ t + k 1053 t
Question 1.4.10 2 2 Solve y' − y = x − 1 x
at y(1) = 1.
y = x +
Ans
Question 1.4.11 Solve I' + 10I = 10
8
1 x
2
− 1 ⋅ x
at I(0) = 0.
Question 1.4.12 dy 7 3 = x − 4x ⋅ y. Solve dx
Remark: De is not in the standard linear form. Conversion is necessary. Ans
y=
1 4
(
4
( ) − exp( x ) + 4⋅ k) ⋅ exp( −x ) 4
4
⋅ x ⋅ exp x
4
Question 1.4.13 dy 3 = cos( x) − y⋅ tan( x) . Solve dx
Remark: Convert to linear form. Ans:
20094em3 Exercise 14.mcd
y=
1 2
2
⋅ cos( x) ⋅ sin( x) +
Copyright 2008 - 2009
1 2
⋅ cos( x) ⋅ x + cos( x) ⋅ k
2/3
Engineering Mathematics 3
Question 1.4.14 dy 2 − x⋅ y = 1 . Solve x + 1 dx
(
)
1
(
2
y = x + k⋅ x + 1
Ans:
)
2
Section C (Bernoullian De)
Question 1.4.15 4
Solve y' + 2⋅ x⋅ y + x⋅ y = 0. −1
1
Ans:
3
y
=
2
( ) 2
+ exp 3⋅ x ⋅ k
Question 1.4.16 2
Solve y' + y = y ( cos( x) − sin( x) ) . ( − exp( − x) ⋅ sin( x) + k)
1
Ans:
y
=
exp( − x)
Question 1.4.17 Solve y' + x⋅ y = 6⋅ x⋅ y at y(0) = 0. 1
Ans:
20094em3 Exercise 14.mcd
Copyright 2008 - 2009
y
2
= 6+
1
1 2 exp ⋅ x 4
⋅k
3/3