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1) A surveying student had recorded the following after repeated pacing: First distance = 100 m No. of paces: 142,145,143,146.5 Second distance =? No. of paces: 893.5,896,891.5,897 Find the second distance in meters.

2) A student recorded the following number of paces after walking a distance of 50 m repeatedly as 71.5, 72.0, 70.0, and 69.5. He wanted to measure the distance between two points C and D. He recorded the following number of paces from C to B or back as 465, 468, 463 and 460. What is the distance from C to D?

3) A line was measured to have 5 tallies, 6 marking pins, and 63.5 links. How long is the line?

4) A line was measured with a 50 m tape. There were 2 tallies and 3 pins, and the distance from the last pin and the end of the line was 2.25m. Find the length of the line in meters.

5) Using a 50 m tape that is 0.002 m too long, the measured distance from A to B is 160.42 m. what is the correct distance from A to B?

7) The distance from D to E, as measured, is 165.2 m. If the 50 m tape used is 0.01 m too short. What is the correct distance in meters?

6) The sides of a square lot having an area of 2.25 hectares were measured using a 100 m tape that was 0.004 m too short. Compute the error in the area in sq.m.

8) A steel tape is 100 m long at a standard pull of 65 N. Compute the pull correction in mm, if during measurement the applied pull is 40 N. The tape has a cross sectional area of 3.18 mm2 and a modulus of elasticity E = 200 GPa.

9) The correct distance between points E and F is 213.5 m. If a 100 m tape that is 0.025 m too long is used to measure EF. What will be the measured distance in meters?

11) A line was measured to be 412 n using a 30-m tape, which is of standard length at a temperature of 20 °C. During measurement, the temperature was 52 °C. If the coefficient of thermal expansion of the tape material is 0.0000116 m/m °C. Calculate the correct length of the line.

10) When the temperature was 3°C, the distance from E to F was measured using a steel tape that has a standard length at 20°C with a coefficient of thermal expansion of 0.0000116/°C . If the correct distance from E to F is 836.5 m, what is the measured distance in meters?

12) Using a 25-m tape, a square lot was measured and found to have an area of 1 hectare. If the total error in area is 4.004 square meter short, what is the error in each tape length?

13) A baseline measure 25 km at elevation 520 m. If the average of curvature is 6400 km, compute the sea level distance.

15) The length intercepted on the stadia rod is 3.6 m and the line of sight makes an angle of 3°15’ with the horizontal. Find the distance, in meters, from the center of the instrument to the rod, if the stadia constant is 0.3 m and the stadia interval factor is 100.

14) With the transit at point A and the line of sight horizontal, the stadia intercept at B was found to be 1.94 m. If the stadia constant is 0.3 and AB – 194.2 m, find the stadia interval factor.

16) With the transit at point A and line of sight horizontal, the stadia intercept at B is 0.6 m. If the stadia interval factor is 99.96 and the stadia constant is 0.3, find the distance AB.

17) The length intercepted on the stadia rod is 1.8 m and the line of sight makes an angle of 4°30’ with the horizontal. Find the horizontal distance, in meters, from the center of the instrument to the rod, if the stadia constant is 0.3 m and the stadia interval factor is 100. (M02 M 25)

19) The following were taken during a differential leveling. What is the difference in elevation between 𝐵𝑀1 and 𝐵𝑀2 ? (M96 M 24) Station

BS

𝐵𝑀1

7.11

1

8.83

2

11.72 1.11

𝐵𝑀2

18) Using the following notes, what is the elevation of 𝐵𝑀12 ? (N95 M 22) Station

BS

FS

𝐵𝑀12

4.64

1

5.80

5.06

2

2.25

5.02

𝐵𝑀13

6.02

5.85

3

8.96

4.94

4

8.06

3.22

5

9.45

3.71

6 𝐵𝑀14

12.32 2.02 1.98

Elev. 209.65

FS

Elev. 751.05

1.24

10.21

20) Based on the following leveling notes, find the elevation of Sta 5 in meters. (M97 M 8) Station 1 2 3 4 5

BS 8.26 9.98 12.87 8.65 5.32

FS

Elev. 458.45 m

2.39 2.26 11.36

21) Determine the difference between the elevations of Sta 6 and Sta 5, in meters, using the following notes: (N97 M 15) Station BS FS Elev. 1 4.90 463.8 m 2 6.06 5.32 3 2.51 5.28 4 6.28 6.11 5 9.22 4.60 6 3.48

22) To make a peg adjustment, the following notes were taken: Wye level at 1 Wye level at 2 Rod reading at P 0.75 1.906 Rod reading at Q 2.766 3.798 Point 1 is on the line PQ and midway between P and Q. Point 2 is on the same line as P and Q but not between them. Point 2 is 25 m from P and 230 m from Q. With the wye level at point 2, what is the rod reading at P for a level sight? (N94 M 26)

23) With the use of an engineer’s level, the reading on a rod 80 m away was found to be 2.82 m. The bubble was leveled through 5 spaces on the level tube and the rod reading increased to 2.884 m. What is the radius of curvature of the level tube if one space on the tube is 0.6 mm long? (N02 M 24)

24) Point A is between points B and C. The distances of B and C from point A are 1000 m and 2000 m, respectively. Measured from point A, the angle of elevation of point B is 18°30’, while that of point C is ϴ. The difference in the elevations of B and C IS 44.4 m, with C being the lower than B. Considering the effects of curvature and refraction, the value of ϴ is nearest to: (M95 M 26)

26) Point A is between points B and C. The distances of B and C from point A are 1000 m and 2000 m, respectively. Measured from point A, the angle of elevation of point B is 18°30’, while that of pint C is 8°15’. Find the difference in the elevations of B and C. Consider the effects of curvature and refraction. (N00 M 2)

25) The top of a tower signal at B 2000 m from A away was sighted through a transit with recorded vertical angle of 2°30’. The height of the mast is 12 m and the HI of the transit above the point where it is set is 1.10 m. The elevation of the point under the transit A is 133.3 m. Compute the elevation of the base of the signal B. (N96 M 26)

27) Find the area of a piece of land with an irregular boundary as follows: Station 0+000 0+010 0+020 0+030 0+040

Offset Distance (m) 5.59 3.38 2.30 3.96 4.80

The stations are on straight –line boundary. Find the area of the land in m2 by Trapezoidal Rule. (M96 M 2)

28) The forward azimuth of a line is known to be 52°. What is its back azimuth? (N99 M 26)

30) If the polar distance of a star is 2°30’, what is its declination? (M94 M 26)

29) Lot ABCDEFA is a closed traverse in the form of a regular hexagon with each side equal to 100 m. The bearing of AB is N25°E. What is the bearing of CD? (M03 M 26)

31) A line has a magnetic bearing of S40o30’E when the declination was 1o30’E. What is the true bearing of the line if a local attraction is 3o30’ to the east of the vicinity?

32) To determine the area of a triangular lot ABC, a surveyor set-up a transit at point P inside the lot and recorded the following bearing and distance of each corners of the lot from P. Corner Bearing from P Distance from P A N47o32’W 36.25 m o B N68 52’E 48.32m C Due South 65.25m Determine the area of the lot in sq. m.

34) A closed traverse has the ff. data: Course Bearing Distance (m) 1-2 N9.27oE 58.70 o 2-3 S88.43 E 27.30 3-4 N86.78oE 35.2 4-5 S5.30oE 35.00 5-1 What is the bearing of line 5-1?

33) A closed traverse has the ff. data: Course Bearing Distance (m) o 1-2 N9.27 E 58.70 2-3 S88.43oE 27.30 3-4 4-5 S5.30oE 35.00 o 5-1 S72.07 W 78.96 What is the length of course 3-4?

35) A closed traverse has the ff. data: Course Bearing Distance (m) o AB S15 36’W 24.22 BC S69o11’E 15.92 o CD S57 58’E DA S80o43’W Find the distance DA in meters.

36) From the given date of a closed traverse, compute the bearing of line 3-4. Line Bearing Distance (m) 1-2 N58oE 80 2-3 Due N 50 3-4 4-1 S36.74oE 89.8

37) A closed traverse has the ff. data: Line Distance (m) Bearing AB 64.86 N72o10’E BC 107.72 S48o13’E CD 44.37 S35o30’W DE 137.84 EA 12.83 Find the bearing of line DE.

38) A closed traverse has the ff. data: Line Bearing Distance (m) AB 44.47 BC 137.84 CD N1o45’E 12.83 DE N72o10’E 64.86 o EA S48 13’E 107.72 Find the bearing of line AB.

39) A closed traverse has the ff. data: Line Bearing Distance (m) AB 60.0 BC 72.69 CD S17o20’E 44.83 DE S70o36’W 56.45 o EA N74 30’W 50.0 Find the bearing of line BC.

40) A closed traverse has the ff. data: Line Bearing Distance (m) AB N86.78oE 35.20 o BC S5.30 E 35.00 CD S72.07oW 78.95 DE N9.27oE 58.70 EA Find the length of side EA.

41) A closed triangular traverse has the following data: Line Bearing Distance (m) AB N60° E 1000 BC Due South CA N 60° W An area of 280 000 square meter is cut-off starting from corner A to point F on line BC. What is the length of line AF? (N03 M 29)

42) A closed traverse has the following data: Line Distance Bearing AB 895 S70° 29’ E BC 315 S 26°28’E CD 875 S65°33’W DE 410 N 45°31’W EA 650 N10°00’E Determine the correct bearing of line EA using the transit rule. (M97 M 19)

43) A closed traverse has the following data: Line Distance Bearing AB 895 S 70°29’E BC 315 S 26°28’E CD 875 S 65°33’W DE 410 N 45°31’W EA 650 N 10°00’E Find the corrected bearing of line CD by transit rule. (N98 M 12)

44) A closed traverse has the following data: Line Latitude 1-2 +9.15 2-3 -8.41 3-4 -24.15 4-5 +6.21 5-1 +17.10 Using the transit rule, determine the corrected latitude of line 3-4. (N99 M 27).

45) The observed interior angles of a triangle and their corresponding number of observations are as follows: Corner

Angle

No. of observations 1 39° 3 2 65° 4 3 75° 2 Determine the corrected angle at corner 1. (M99 M 29)

46) The observed interior angles of a triangular piece of land ABC are as follows: A= 35°14’37”, B=96°30’09” and C=48°15’05”. The most probable value of angle B is nearest to: (M00 M 23)

47) The observed interior angle of a triangle and their corresponding number of observations are as follows: Corner 1 2 3

Angle 41° 65° 75°

No. of observations 5 6 2

48) The following interior angles of a triangular traverse were measured with the same precision. Find the most probable value of angle A in degrees. Corner 1 2 3

Angle 41° 77° 63°

No. of observations 5 6 2

49) The horizontal axis of the transit was inclined at 4’ with the horizontal due to non-adjustment. The first sight had a vertical angle of 50°, the next has -30°. Determine the error in the measured horizontal angle.

51) The area bounded by the waterline of a reservoir and the contours at an interval of 2 m are as follows: A1 = 10,250 m2 , A2 = 8,350 m2 , A3 = 7750 m2 , A4 = 6900 m2 , A5 = 5,250 m2 . Calculate the volume of the reservoir by endarea-method. (M99 M 24)

52) In a hydrographic survey, a staff gage reading of 8.15 m was observed at the instant the depth of the sounding was 17.6 m. The zero mark of the staff gage is at elevation 148.2 m. Find the elevation of the point where the sounding was made. (M01 M21)

53) Given the following areas bounded by the waterline of a lake and the contours 1,2,3,4, and 5. Each contour is 2 m interval. A1 = 6,150 m2 A4 = 4,140 m2 A2 = 5,010 m2 A5 = 3,150 m2 2 A3 = 4,650 m Determine the volume of water in the lake. (N02 M 26)

54) If conversed sin θ is 0.134, find the value θ. (M94 M 10)

55) If versed sin θ is 0.148, find the value θ. (M94 M 10)

56) The tangents of a simple curve have bearings N75 °12 ‘E and S78 °36 ‘E, respectively. What is the central angle of te curve? (N94 M 28)

57) A 3-degree curve has an angle of intersection of 24°. What is the length of the long chord in meters? Use chord basis. (M95 M 7)

59) A 3-degree curve has an external distance of 8.53 m. What is the central angle? Use chord basis. (M96 M 18)

58) What is the angle of intersection of the two tangents of a simple curve if their bearings are N75 °12 ‘E and S78 °36 ‘E, respectively? (N95 M 23)

60) Find the radius of a simple curve having a degree of curve of 5° using chord basis. (N96 M 18)

61) A circular curve has the following data: Azimuth of back tangent = 205 degrees Azimuth of forward tangent = 262 degrees Middle ordinate, M = 5.8m Find the length of the tangent, in meters. (M97 M 28)

62) From point A on a simple curve, the perpendicular distance to the tangent, at point Q, is 64 m. the tangent passes through the PC. The distance from Q to PC is 260 m. find the radius of the curve, in meters. (M98 M 4)

63) From PC, the deflection angles of two intermediate points A and B of a simple curve are 3°15’ and 8°15’, respectively. The distance between A and B is 40 m long. Find the Length of the curve from the pc to B, in meters. (N98 M 1)

64) A 4- degree simple curve has an angle of intersection of 24°. Find the length of the long chord. Use arc basis. (M99 M 20)

65) From point on a simple curve, the perpendicular distance to the tangent, at point Q, is 64 m. The tangent passes through PC. The distance from Q to PC is 260 m. Find the length of the curve from PC to A, in meters (M00 M 20)

67) The offset distance from PC to PT of a simple curve is 8 m. If the angle of intersection of the curve is 20°, what is the radius of the curve?(M01 M 13)

66) From a point A on a simple curve, the perpendicular distance to the tangent at point Q is x. The tangent passes through PC is station 20+150. If the radius of the curve is 800 m, Find x. (N00 M 18)

68) Determine the central angle of a 350-m simple curve if the nearest distance from the curve to the point of intersection of the tangents is 18 m.(N01 M 1)

69) The tangent of a simple curve from PI to PC has a bearing of N65°E and the other tangent from PI to PT has a bearing of N55°W. At a point 150 m from pc along the tangent through PC, the right angle offset to point F on the curve is 6.2 m. find the radius of the curve. (N02 M 23)

70) What is the central angle in degrees of the curve whose radius is 200 m and the distance of the midpoint of the curve to the PI is 14.20m?(M03 M 28)