Tugas Rekpon
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nim D B C gamma b
7 1.7 1.7 160 18
pi gamma sat Nc Nq N gam
qu = cNc mat = Jarak muka air tanah dr fondasi z = krn mat > kedalaman B+D 4 > qu
= = =
20 20.81 17.7 7.4 5
+ 4m
p0Nq
>
2.3
+
1.7
3.4
cNc
>>>>>
g / gam
0,5gBNg
diitung dr dasar fondasi diitung dr permukaan tanah
+ 160 2832
gam D Nq 17.7 +
+
0,5 gam BN 1.7 18 226.44
7.4
3134.94 z g'
gcor
qu
z qu
0.5 < = = =
gsat
= = =
g'
= = = =
cNc
dasar pondasi = = = =
1.7 20.81 11
+ 11 + 13.05882353 + 160 2832 3113.94
cNc
+ 160 2832 3105.19
z D1 D2
0.5m di atas dasar pondasi 1.2 0.5
qu
=
Nc
c
mat dibawah pondasi gw 9.81
z/B (gb-g') 0.2941176471
gam D Nq 17.7 +
+
gam D Nq 17.7 +
+
+
7
1.7 226.44
0,5 gam BN 18
0,5gam'BN 18 7.4
1.7 226.44
Nq
7.4
(
gam'
= = = =
160 2832 2832 3079.29
z
tepat pada permukaan tanah
qu
= = = =
mat qs
mat qs
mat qs
mat qs
Nc
17.7 + + +
c 160 2832 3017.13
+ 17.7 + +
4m dari permukaan tanah = 1/F
( 0.33 ( 0.33 ( 0.33 1034.78 1065.38
0,5 m dibawah pondasi = 1/F ( = 0.33 ( = 0.33 ( = 0.33 = 1027.78 = 1058.38 tepat di dasar pondasi = 1/F = = = = =
( 0.33 ( 0.33 ( 0.33 1024.86 1055.46
F= qu
7.4 ( 7.4 200.54
Nq
11
gam' 7.4 138.38
D 11
1.7
3 3134.94 3134.94 -
gb
3113.94 3113.94 -
gb
3105.19 3105.19 -
gb
3079.29 3079.29 -
gb
D 18 30.6
1.7
3104.34
qu
D 18 30.6
1.7
3083.34
qu
D 18 30.6
1.7
3074.59
0,5m atas permukaan tanah = 1/F ( qu = 0.33 ( = 0.33 ( = 0.33 3052.19 = 1017.3966667 = 1044.50
D1 18 21.6
1.2
Chart Title 4.5 4
mat qs
tepat dipermukaan tanah = 1/F ( qu = 0.33 ( = 0.33 ( = 0.33 2998.43 = 999.47666667 = 1018.176667
m.a.t (dari permukaan tanah)(m) 4 m dibawah muka tanah 0,5 m dibawah dasar pondasi tepat pada dasar pondasi
qu 4 2.2 1.7 1.2 0
Chart Title 3017.13 3017.13 -
D 11 18.7
4 3.5
1.7
3 2.5 2
qs 3134.94 3113.94 3105.19 3079.29 2998.43
g'
4.5
1065.3800 1058.3800 1055.4633 1044.4967 1018.1767
1.5 1 0.5
0 2980.00 3000.00 3020.00 3040.00 3060.00 3080.0
Chart Titl
4 0
4.5 4 3.5 3 2.5 2 1.5 1 0.5 0 1010.0000
1020.0000
1030.0000
1040.0000
= �
<<<<<
soal B z phi c' Nc' Nq' Ng' phi' qu +
0.5 76.5
18
1.7
5
+
0.5 13.05882 55.5
1.7
5
1.7
5
+
D2
0.5 46.75
+
11
gam b
D1
)
+
0.5 gam'
=
4> 20 0.67 160 11.8 3.9 1.7 arc tg 2/3
= = = =
c'Nc
B
Ngam
106.7 1258.667 1393.307
0.5 +
18
1.2 )
+ + +
27.1
+ + +
0.5 gam' 0.5 46.75
) ) )
+ + + + +
gb
) ) )
+ + + + +
gb
) ) )
+ + + + +
gb
-
g'
D2
B 11
1.7
5
5
D 1.7
D 18 30.6 30.6 30.6
1.7
D 18 30.6 30.6 30.6
Chart Title
11
Ngam 1.7
18 30.6 30.6 30.6
11 5.5
0.5 46.75 46.75
) 0.5 ) )
1.7
+ + + + +
gb
D1 18 21.6 27.1 27.1
+ 1.2 + + + +
g'
D2 11 5.5
0.5
Chart Title ) ) )
+ + + + +
g'
D 11 18.7 18.7 18.7
1.7
3020.00 3040.00 3060.00 3080.00 3100.00 3120.00 3140.00 3160.00
20.0000
Chart Title
1030.0000
1040.0000
1050.0000
1060.0000
1070.0000
1.7 106.7
tg 20 +
= Df gb Nq' + 11.8 +
kN/m2
13.64
1.7 119.34
0,5 gb Ng' 18
3.9 +
0.5 15.3
18
1.7
7 1.7 1.7 160 18
pi gamma sat Nc Nq N gam
qu = cNc mat = Jarak muka air tanah dr fondasi z = krn mat > kedalaman B+D 4 > qu
= = =
20 20.81 17.7 7.4 5
+ 4m
p0Nq
>
2.3
+
1.7
3.4
cNc
>>>>>
g / gam
0,5gBNg
diitung dr dasar fondasi diitung dr permukaan tanah
+ 160 2832
gam D Nq 17.7 +
+
0,5 gam BN 1.7 18 226.44
7.4
3134.94 z g'
gcor
qu
z qu
0.5 < = = =
gsat
= = =
g'
= = = =
cNc
dasar pondasi = = = =
1.7 20.81 11
+ 11 + 13.05882353 + 160 2832 3113.94
cNc
+ 160 2832 3105.19
z D1 D2
0.5m di atas dasar pondasi 1.2 0.5
qu
=
Nc
c
mat dibawah pondasi gw 9.81
z/B (gb-g') 0.2941176471
gam D Nq 17.7 +
+
gam D Nq 17.7 +
+
+
7
1.7 226.44
0,5 gam BN 18
0,5gam'BN 18 7.4
1.7 226.44
Nq
7.4
(
gam'
= = = =
160 2832 2832 3079.29
z
tepat pada permukaan tanah
qu
= = = =
mat qs
mat qs
mat qs
mat qs
Nc
17.7 + + +
c 160 2832 3017.13
+ 17.7 + +
4m dari permukaan tanah = 1/F
( 0.33 ( 0.33 ( 0.33 1034.78 1065.38
0,5 m dibawah pondasi = 1/F ( = 0.33 ( = 0.33 ( = 0.33 = 1027.78 = 1058.38 tepat di dasar pondasi = 1/F = = = = =
( 0.33 ( 0.33 ( 0.33 1024.86 1055.46
F= qu
7.4 ( 7.4 200.54
Nq
11
gam' 7.4 138.38
D 11
1.7
3 3134.94 3134.94 -
gb
3113.94 3113.94 -
gb
3105.19 3105.19 -
gb
3079.29 3079.29 -
gb
D 18 30.6
1.7
3104.34
qu
D 18 30.6
1.7
3083.34
qu
D 18 30.6
1.7
3074.59
0,5m atas permukaan tanah = 1/F ( qu = 0.33 ( = 0.33 ( = 0.33 3052.19 = 1017.3966667 = 1044.50
D1 18 21.6
1.2
Chart Title 4.5 4
mat qs
tepat dipermukaan tanah = 1/F ( qu = 0.33 ( = 0.33 ( = 0.33 2998.43 = 999.47666667 = 1018.176667
m.a.t (dari permukaan tanah)(m) 4 m dibawah muka tanah 0,5 m dibawah dasar pondasi tepat pada dasar pondasi
qu 4 2.2 1.7 1.2 0
Chart Title 3017.13 3017.13 -
D 11 18.7
4 3.5
1.7
3 2.5 2
qs 3134.94 3113.94 3105.19 3079.29 2998.43
g'
4.5
1065.3800 1058.3800 1055.4633 1044.4967 1018.1767
1.5 1 0.5
0 2980.00 3000.00 3020.00 3040.00 3060.00 3080.0
Chart Titl
4 0
4.5 4 3.5 3 2.5 2 1.5 1 0.5 0 1010.0000
1020.0000
1030.0000
1040.0000
= �
<<<<<
soal B z phi c' Nc' Nq' Ng' phi' qu +
0.5 76.5
18
1.7
5
+
0.5 13.05882 55.5
1.7
5
1.7
5
+
D2
0.5 46.75
+
11
gam b
D1
)
+
0.5 gam'
=
4> 20 0.67 160 11.8 3.9 1.7 arc tg 2/3
= = = =
c'Nc
B
Ngam
106.7 1258.667 1393.307
0.5 +
18
1.2 )
+ + +
27.1
+ + +
0.5 gam' 0.5 46.75
) ) )
+ + + + +
gb
) ) )
+ + + + +
gb
) ) )
+ + + + +
gb
-
g'
D2
B 11
1.7
5
5
D 1.7
D 18 30.6 30.6 30.6
1.7
D 18 30.6 30.6 30.6
Chart Title
11
Ngam 1.7
18 30.6 30.6 30.6
11 5.5
0.5 46.75 46.75
) 0.5 ) )
1.7
+ + + + +
gb
D1 18 21.6 27.1 27.1
+ 1.2 + + + +
g'
D2 11 5.5
0.5
Chart Title ) ) )
+ + + + +
g'
D 11 18.7 18.7 18.7
1.7
3020.00 3040.00 3060.00 3080.00 3100.00 3120.00 3140.00 3160.00
20.0000
Chart Title
1030.0000
1040.0000
1050.0000
1060.0000
1070.0000
1.7 106.7
tg 20 +
= Df gb Nq' + 11.8 +
kN/m2
13.64
1.7 119.34
0,5 gb Ng' 18
3.9 +
0.5 15.3
18
1.7
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