Taller No 5

  • April 2020
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TALLER No. 5 1)

y 2 −8 x −4 =0

2 x + y −10 =0 2 x + y =10 2 x =10 − y

(−4 )2 x

8 x = y 2 −4

(−4 )

=10 −y

8 x =−4

y 2 −4 =8 x −8 x = −40 +4 y 8 x = −4

+y 2 0

+y2

−44 +4 y + y 2

y 2 +4 y −44 a =1 b =4 c =−44 y = y =

2 x =10 − y

−b ± b 2 −4 ac 2a −4 ± 4

10 − y x= 2 10 −4,9 x= 2 5,1 x= 2 x =2,55

−4(1)(−44 ) 2(1)

2

−4 ± 16 −4(−44 ) 2 −4 ± 16 +176 = 2 −4 +13,8 9,8 = = 2 2 =4,9 −4 −13,8 −17,8 = = 2 2 =−8,9

y = y y y y y

10 −y x = 2 X Y 4 2 3 4 2 6 1 8

x =

X 1.5 4 7.5 12

y 2 −4 8 Y 4 6 8 10

Punto de equilibrio

X 2.55

Y 4.9

10 9 8 7 6

Column C Column G

10 9 8 7 Column C

6

Column G

5 4 3 2 1

1.5

2

2.5

3

3.5

4

Column C Column G

4

Column C Column G

2)

x 2 +5 x −y +1 =0

2 x 2 + y −9 =0

y = x 2 +5 x +1

− y =2 x 2 −9

y = x 2 +5 x +1 − y =2 x 2

−9

3 x 2 +5 x −8

3 x 2 +5 y −8 (3 x +8)( x −1) 3 x 2 +5 x −8

a =3 b =5 c =−8 y = x 2 +5 x +1

y =12 +5(1) +1 y =1 +5 +1 y =7

3 x +8 =0 x +1 =0 3 x =−8 −8 x = 3 x =1

y = x 2 +5 x +1 X 0.5 1 5 7 10

160 150 140

Y 3.75 7 51 85 151

− y =2 x 2 −9 y =

X 0.5 1 5 7 10

2 x −9 −1

Punto de equilibrio

2

Y 8.5 7 -41 -81 -191

X 1

Y 7

160 150 140 130 120 110 100 90 80

C

70 60 50 40 30 20 10 0 0.5

1

1.5

2

2.5

3

3.5

4

4.5

5

5.5

6

6.5

7

7.5

8

8.5

9

9.5

10

9

Column C

9.5

10

3)

y 2 + y + x −20

2 y 2 −x −3 y −4

−x = y 2 + y −20

x = 2 y 2 −3 y −4

x = 2 y 2 −3 y −4 −x = y 2 +

y −20

3 y 2 −2 y −24 a =3 b =2 c = −24 y = y =

−b ±

b 2 −4ac 2a

−( −2 ) ±

x x x x

2 −4(3)( −24 ) 2(3) 2

4 −12 ( −24 ) 6 2 ± 4 +288 y = 6 2 +17 ,08 19 ,08 y = = 6 6 y =3,18 y =

−( −2 ) ±

x = 2 y 2 −3 y −4 = 2(3,18 ) −3(3,18 ) −4 = 2(10 ,1) −9,54 −4 = 20 , 2 −9,54 −4 =6,66 2

2 −17 ,08 −15 ,08 = 6 6 y =−2,55 y =

x =

y 2 + y −20 −1

X 14.0 0.0 -22.0 -52.0

Punto de equlibrio X Y 6.7 3.18

x = 2 y 2 − 3y − 4

Y 2 4 6 8

X -2 16 50 100

Y 2 4 6 8

8 7 6 Column C

5

Column G 4 3 2 -60.0

-50.0

-40.0

-30.0

-20.0

-10.0

0.0

10.0

20.0

−4

3(3,18 ) −4 54 −4 −4

unto de equlibrio

Column C Column G

10.0

20.0

4)

( x +12 )( y +6 ) =169

x − y +6 =0 y = x +6

( x +12 )( x +6 +6 ) =169 ( x +12 )( x +12 ) =169

x +25

=0

x =− 25

x 2 +12 x +12 x +144 =169 x 2 +24 x +144 =169 x 2 +24 x =169 −144

x −1 =0 x =1 y = x +6

x 2 +24 x = 25

y =1 +6

x 2 +24 x −25 =0 ( x +25)( x −1)

y =7

x 2 −x +25 x −25 x 2 +24 x −25 =0

( x +12 )( y +6 ) =169

y = x +6 X 1 2 3 4

Y 7 6.1 5.3 4.6

X 1 2 4 6

Y 7 8 10 12

Punto de equlibrio X 1

Y 7

12 11 10 9 8

Colum Colum

7 6 5 4 1

1.25

1.5

1.75

2

2.25

2.5

2.75

3

3.25

3.5

3.75

4

5

Column C Column G

3.5

3.75

4

5)

P1 =80

P2 =60

Q1 =10

Q2 = 20

m =

P2 −P1 Q2 −Q1

60 −80 20 −10 −20 m = 10 m =− 2 m =

P −P1 =m(Q −Q1 )

P −80 =−2(Q −10 ) P −80 =−2Q +20 P =−20 +20 +80 P =−2Q +100 Comprobación P =−2(10 ) +100 P =−20 +100 P =80 6) P =100 1

P2 = 0

Q1 = 0 m =

Q2 =50

P2 −P1 Q 2 −Q1

0 −100 50 −0 −100 m = 50 m =− 2 m =

P −P1 = m(Q −Q1 )

P −100 = −2(Q −0 ) P −100 = −2Q +0 P = −2Q +100 Comprobaci

ón

P = −2(0 ) +100 P =0 +100 P =100

7)

P1 =50

P2 = 75

Q1 =50

Q2 =100

m =

P2 −P1 Q 2 −Q1

75 −50 m = 100 −50 25 m = 50 m =0,5 P −P1 = m(Q −Q1 )

P −50 =0,5(Q −50 ) P −50 =0,5Q −25 P =0,5Q −25 +50 P =0,5Q +25 Comprobaci ón

P =0,5(50 ) +25 P = 25 +25 P =50

8) P = 25 1

Q1 = 0 m =

P2 −P1 Q 2 −Q1

35 −25 20 −0 10 m = 20 m =0,5 m =

P −P1 = m(Q −Q1 )

P −25 =0,5(Q −0 ) P −25 =0,5Q −0 P =0,5Q +25 Comprobaci ón P =0,5(0 ) +25 P =0 +25 P = 25

P2 =35 Q2 = 20

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