Stpm Trial 2009 Bio Q&a (pahang)

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964/1

PEPERIKSAAN PERCUBAAN SIJIL TINGGI PERSEKOLAHAN MALAYSIA NEGERI PAHANG DARUL MAKMUR 2009

BIOLOGY PAPER 1 MULTIPLE-CHOICE ONE HOUR AND FORTY-FIVE MINUTES

Instructions to candidates DO NOT OPEN THIS BOOKLET UNTIL YOU ARE TOLD TO DO SO

There are fifty questions in this paper. For each question, four suggested answers are given. Choose one correct answer and indicate it on the multiplechoice answer sheet provided. Read the instructions on the multiple-choice answer sheet carefully. Answer all questions. Marks will not be deducted for wrong answers.

CONFIDENTIAL *

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1

2

3

Which one of the following is a characteristic of saturated fats that distinguishes them from unsaturated fats? A

They have no double bonds between their carbon atoms

B

They contain only unbranched fatty acids

C

They contain high proportion by mass of oxygen

D

They do not contain glycerol

Which part of a phospholipid molecule contributes most to the thickness of a cell surface membrane? A

Glycerol

B

Hydrocarbon chain

C

Hydrophilic head

D

Phosphate group

What does a haemoglobin molecule contain? A

Four iron (Fe2+) ions attached to each haem group

B

Four oxygen molecules attached to each haem group

C

Four polypeptide chains each with four attached haem groups

D

Four polypeptide chains each with one attached haem group

4 Potassium cyanide is known to interfere with the formation and use of ATP in cell metabolism. If the use of potassium cyanide resulted in an accelerated entry of a solute into a cell, it may be reasonably assumed that, under normal circumstances, the solute enters by A

Active transport

B

Osmosis

C

Passive diffusion

D

Pinocytosis

2

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5

6

Which cell component forms pinocytic vesicles? A

Lysosome

B

Nucloelus

C

Cell surface membrane

D

Endoplasmic reticulum

A culture of bacteria had their entire DNA labelled with the heavy isotope of nitrogen, 15

N. The culture was then allowed to reproduce using nucleotides containing normal 14N.

The DNA was examined using a centrifuge after one generation and again after two generations. The diagram shows the position of the DNA band at Z in the centrifuge tube when the DNA was first labelled.

X Y Z In which patterns would the DNA be found after the first and after the second cell generations? After first generation

After second generation

A Half at X and half at Y

Quarter at X and at Z and half at Y

B Half at X and half at Z

Quarter at X and at Z and half at Y

C

All at Y

Half at X and half at Y

D

All at Z

Half at Y and half at Z

3

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7

Turgid plant tissue is placed in a solution which has the same solute potential as the contents of the cells. The diagram shows a cell after one hour.

Which equation describes the value of the pressure potential for this cell? A Pressure potential = solute potential of the cell B Pressure potential = solute potential of the external solution C Pressure potential = water potential of the cell D Pressure potential = zero

8 A metabolic pathway is shown below. Enzyme 1 Reactant

Enzyme 2 substance X

Enzyme 3 substance Y

end

product

What would be the effect of adding a small amount of a non-competitive inhibitor to enzyme 2? A Enzyme 2 would be partially denatured B Substance X would increase in concentration C Substance Y would no longer be formed D The initial reactant would no longer be metabolised

4

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9 Which statement is true of photophosphorylation? I

High energy phosphate bond is split

II High energy phosphate bond is formed III It occurs in the thylakoid membrane IV Light is transformed to chemical energy A II, III, and IV B II and III C II and IV D I and III

10 The following scheme shows a pathway in the formation of fatty acids in plants. CO₂ RuBP

W

X

Y

Z Fatty acid

Which of the following compounds are represented by W, X, Y, and Z in the above scheme? A B C D

W Pyruvate Phosphoglyceraldehyde Phosphoglycerate Phophoglycerate

X Phosphoglyceraldehyde Acetyl CoA Phosphoglyceraldehyde Phosphoglyceraldehyde

5

Y Phosphoglycerate Phosphoglycerate Acetyl CoA Pyruvate

Z Acetyl CoA Pyruvate Pyruvate Acetyl CoA

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11 Six tubes containing preparations from animals were set up as shown below: Tube 1 2 3 4 5 6

Contents Glucose + homogenised cells Glucose + mitochondria Glucose + cytoplasm lacking organelles Pyruvic acid + homogenised cells Pyruvic acid + mitochondria Pyruvic acid + cytoplasm lacking organelles

After incubation, in which three tubes would carbon dioxide be produced? A

1, 2 and 3

B

1, 4 and 5

C

2, 4 and 5

D 3, 5 and 6 12

13

When a glucose molecule is completely oxidised to carbon dioxide and water, 38 moles of ATP molecules are formed. How many ATP molecules can be formed if a respiratory poison such as cyanide is added to the oxidation process? A

2 ATP

B

8 ATP

C

9 ATP

D

30 ATP

The following statements are related to the nutrition of living organisms W- Photosynthetic bacteria synthesise organic food from carbon dioxide and water using light energy absorbed by bacteriochlorophyll X- Chemosynthetic bacteria use energy obtained from the oxidation of organic matter Y- Human nutrition is holozoic nutrition Z- Bacteria and fungi involved in decomposition are saprophytic organisms Which of the above statements are true? A W and Y B

Y and Z

C W, Y and Z D X, Y and Z

6

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14 Graph 1 shows oxygen dissociation curves which illustrate the Bohr effect. Percentage of saturation

X

P O2 mmHg

Which one of the following statements could represent the X factor? I

High pH

II

Less CO2 partial pressure

III

Smaller size of animals

IV

Higher altitude

V

Myoglobin

A I, II, IV and V B I, III, IV and V C II, III, IV and V D I, II, III, IV and V

15 Which of the following is not a function of transpiration? A Cooling of the leaf B Excretion of mineral salts C Transport of mineral salts D Transport of water upwards

7

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16 Which nerve impulses can initiate normal expiration and prevent over expansion of the lungs? A Impulses from chemoreceptors in the lungs B Impulses from stretch receptors in the diaphragm C Impulses from the external intercostal muscles D Impulses from the stretch receptors in the walls of the alveoli

17 Which one of the following is a function of the lymphatic system? A To assist in the clotting mechanism of the blood B To return tissue fluid to the bloodstream C To transport dissolved food molecules to all cells of the body D To transport hormones from endocrine glands to their target organs

18 What effect would be caused by cutting the sympathetic nerve fibres to the heart? A A decrease in heart rate B A decrease in the length of the diastole phase C A decrease in the length of the systole phase D A decrease in the stroke volume

8

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19 The passage of some of the contents of the plasma through the capillary wall depends on the effective hydrostatic pressure (HP) of the blood in the capillary and the effective osmotic pressure (OP) of the blood plasma. The diagram below shows the HP of the blood at the arteriole and venule ends of a capillary and the HP of the tissue fluid, together with the OP of the blood plasma protein and the OP of the tissue fluids. All pressures are in mm Hg.

OP = 25 HP = 32

OP = 25

capillary

HP = 12

Tissue fluid OP = 10 HP = 8 venule

arteriole

Which one of the following is the pressure of filtration at the arteriole end of the capillary? A 1mm Hg B 9 mm Hg C 15 mm Hg D 25 mm Hg

9

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20 The diagram below shows a nephron of the mammalian kidney.

Which one of the regions A, B, C or D is the main region responsible for restoring the metabolite level of the blood plasma to its pre-renal level?

21 The following sequence of events occurs at the neuromuscular junction Nerve Impulses

Release of V

end plate potential

X released from sarcoplasmic reticulum

formation of Y

W produced in muscle fibre Muscle contraction

Which one of the following shows the correct sequence from V to Y? V

W

X

Y

A Acetylcholine

Action potential

Calcium ions

Actomyosin

B Acetylcholine

Action potential

Actomyosin

Calcium ions

C Actomyosin

Acetylcholine

Calcium ions

Action potential

D Calcium ions

Action potential

Actetylcholine

Actomyosin

10

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22 Which statement is correct? I

Phytochrome is produced in the dark

II

Phytochrome is a simple protein

III Phytochrome is a simple photoreceptor IV

Phytochrome is initially produced in an inactive form before it is converted into the active form.

A

I and II

B

I and III

C

III and IV

D

II and III

23 The female oestrous cycle is controlled by the secretion and sequential release of at least four hormones: FSH-follicle stimulating hormone LH-luteinising hormone Oestrogen Progesterone Which one of the following shows the correct order in which they are released? A

FSH

Oestrogen

LH

Progesterone

B

FSH

LH

Progesterone

Oestrogen

C

Oestrogen

FSH

LH

Progesterone

D

FSH

LH

Oestrogen

Progesterone

11

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24 Which one of the following chemical substances causes apical dominance in plants? A

Indole acetic acid

B

Giberellic acid

C

Cytokinine

D

Abscissic acid

25 Which one of the following is true of T cells? I

T cells produce complement proteins

II

T cells mature in the bone marrow

III

T cytotoxic cells kill body cells that are infected with viruses

IV

T suppressor cells inhibit the acivities of T cytotoxic cells

A

I and II

B

I and IV

C

II and III

D

III and IV

26 Which is not correct about the concept of self and non-self ? A

MHC protein markers on the surface of cells act as specific antigens

B

Each organism carries a set of antigens which is unique to each individual

C

In the embryo, T lymphocytes which can bind to the receptors (proteins and polysaccharides) of their own body cells are induced to proliferate to form a clone of T cells

D The immune system can distinguish “self” (the body’s own tissue) from “non-self” (foreign tissue)

12

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27 Which one of the following represents the general pattern of the alternation of generations? A

gametophyte

meiosis

B

gametophyte

C

sporophyte

meiosos

D

sporophyte

meiosis

meiosis

sporophyte

spores

spores

sporophyte

gametophyte spores

spores

gametophyte

28 If the diploid state is represented by (D) and the haploid state by (H), which one of the following sequences correctly describes the chromosome number in the named plant structures? Polar Nucleus Pollen grain Pollen tube nucleus

Cell in the testa Cell in the pericarp

A

(D)

(D)

(D)

(D)

(D)

B

(D)

(H)

(H)

(H)

(H)

C

(H)

(D)

(H)

(H)

(D)

D

(H)

(H)

(H)

(D)

(D)

13

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29 Some seeds, in which the major food reserve is lipid, were analysed for lipid and sugar content during germination in the dark. During germination, most of the lipid is converted to sugar. The results of this experiment are shown in the graph below.

lipid

sugar

Lipid Dry mass

Sugar dry mass

0

Time from sowing/ days

12

Which one of the following explains why the total sugar content decreases after one week? A The rate of consumption of sugar in respiration suddenly increases B Sugar is no longer being produced by photosynthesis C The rate of consumption of sugar in metabolism exceeds the rate of production of sugar from lipid D The sugar has moved from the endosperm, where it was produced, to the embryo, where it is needed

14

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30 The diagram below shows the scheme of hormonal control in insects. External stimulation

Neurosecretory cells in brain Larva Neurosecretory hormones

I

I

Pupa Adult

III

II

IV Different hormone Concentrations in blood

Which of the following identifies I, II, III, and IV?

I

II

III

IV

A

Corpus allatum

Prothoracic gland

Ecdysone hormone

Juvenile hormone

B

Corpus allatum

Prothoracic gland

Juvenile hormone

Ecdysone hormone

C

Prothoracic gland

Corpus allatum

Juvenile hormone

Ecdysone hormone

D

Prothoracic gland

Corpus allatum

Ecdysone hormone

Juvenile hormone

15

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31 Drosophilia flies heterozygous for the size of the wing and body colour were crossed with flies with vestigial wings and ebony bodies. The F1 offspring obtained were as follows: • Normal wing, grey body: 522 • Vestigial wing, grey body: 98 • Normal wing, ebony body: 104 • Vestigial wing, ebony body: 496 What is the crossover value? A 8% B 9% C 17% D 20% 32 Two animals are mated. One is homozygous dominant for one character and homozygous recessive for another. The other animal is heterozygous for both characters. How many phenotypes are expected in the offspring of this cross? A 1 B 2 C 3 D 4

33 Two parents each of blood group A have a daughter of blood group O. What is the probability that their next child will be a boy who has blood group O? A 0.125 B 0.25 C 0.50 D 0.75 E 0.825

16

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34 Haemophilia is caused by a sex-linked, recessive allele. Two parents have a haemophiliac son and a haemophiliac daughter. What are the most likely genotypes of the parents? mother

father

A

XHX h

X Y

B

XHY h

X Y

C

XhX h

X Y

D

XHY H

X Y

h

H

H

h

35 During the formation of an ovum, non-disjunction of the sex chromosomes occurred. The ovum was then fertilised by a normal Y bearing sperm cell. Which one of the following shows the sex chromosome complement of the resulting zygote? A XO B XY C XXY D XXXY E XXYY

17

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36 The diagram below shows an intergeneric cross performed in a breeding experiment

X plant

Y plant

(2n=18)

(2n=20)

Sterile hybrid

Fertile hybrid

What is the chromosome number in the sterile hybrid and fertile hybrid? Sterile hybrid

Fertile hybrid

A

18

36

B

19

19

C

19

38

D

20

40

37 In a population of Africans, 1.0% of its individuals suffered from sickle-cell anaemia and died. What is the percentage of the heterozygous individuals in that population that possess abnormal haemoglobin? A 1% B 10% C 18% D 99%

18

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38 Which one of the following phenotypic features of Man can be affected only by genotype? A height B intelligence C skin colour D number of different blood group antigens

39 The genotype and phenotype for a population of rabbits are as given below:

Genotype RMRM RM RP RPRP

Phenotype Black Black, White White

Number of rabbits 110 150 48

The frequencies of allele RM and RP in this population are RM

RP

A

0.4

0.6

B

0.3

0.7

C

0.2

0.8

D

0.6

0.4

40 Which one of the following statements is not true of the lactose operon? A The lactose operon hypothesis was proposed by Jacob and Monod B This system consists of four parts and they are the regulator gene, the promoter gene, the terminator gene and the three structural genes C This system is activated by the presence of lactose in the medium D A repressor molecule bound to the operator gene will prevent the transcription of the structural genes

19

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41 Resctriction enzymes EcoRI and BamHI both have the following properties I

They are extracted from bacteria

II Their action produces DNA fragments with sticky ends III They identify a sequence of six bases during restriction IV They carry out incomplete cutting of DNA V Their action is very specific A I, II and IV only B I, II, III and V only C II, III and IV only D I, II, III, IV and V

42 The following dichotomous key was made to identify different groups of organisms A1 A2 B1 B2 C1 C2 D1 D2

Unicellular organism ………… Multicellular organism ………... Enteron present ………... Enteron absent ………… Coleom present ………… Coleom absent ……….. Chitinous exoskeleton present ….. Chitinous exoskeleton absent ……

organism Q go to B organism R go to C go to D organism S go to E organism T

Among organisms Q, R, S and T, which organism belongs to the phylum Annelida A Organism Q B Organism R C Organism S D Organism T

20

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43 Which one of the following statements describes a feature of a natural system of classification which an artificial system does not have? A A natural system of classification is based on phenotypic characters. B A natural system of classification is based on analogous structures. C A natural system of classification is based on evolutionary relationships between organisms. D A natural system of classification is based on single characteristics rather than several similar features. 44 Human blood when mixed with antibodies to human blood, will give maximum precipitation. If another animal’s blood is mixed with antibodies to human blood, the percentage of precipitation indicates how similar the animal is to a human. The following experimental results were obtained Species: H 100%;

H ON

M 37%;

N 75%;

M P

H O N

A H M N O

O 79%;

M

P

B P

H N M

O

D

C

Which phylogeny would fit these results?

21

P

P 17%

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45 Refer to the following graphs which show the distribution of fang length in two populations A and B of adult female wolf spiders that live in different environments. The dotted line indicates the optimum fang length for capturing the most common prey in each environment. 500

500

Population A

Number of individuals

Population B

Number of individuals

0.5

1.5

2.5

0.5

1 .5

2.5

Fang length (mm)

Fang length (mm)

Which one of the following statements is consistent with the information shown in the graphs? A The average fang length in population A is greater than the average fang length in population B B The environment of population A has a wider range of prey than the environment of population B C The number of individuals in population A is the same as that in population B D Population A would be more likely than population B to become extinct if the average size of the prey in both environments decreased

46 Excess nitrate is a common pollutant in rivers and lakes causing rapid growth of planktonic algae and the death of submerged plants rooted in the mud. Lack of which factor causes the death of the submerged plants? A Carbon dioxide B Light C Organic debris D Oxygen

22

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47 Competition between species will be greatest if they try to occupy the same A Community B Ecosystem C Habitat D Niche 48 Humans affect the environment in the following ways 1

Felling of tropical rain forests

2

Harvesting of marine algae

3

Re-afforestation

4

Combustion of fossil fuels

5

Over-use of nitrate fertilisres

Which activities lead to an increase in the level of carbon dioxide in the earth’s atmosphere? A 1, 2 and 3 B 1, 2 and 4 C 2, 3 and 4 D 2, 4 and 5

23

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49 The diagram represents a pyramid of energy which shows energy loss from a food chain to decomposers, upward transfer of energy to the next trophic level and energy loss through repiration. All figures are in kJ, m-², y-1.

Loss to decomposers

Total energy of trophic level 40

24

Respiratory loss 16

114

360

206

1188

3600

2052

11 880

36 360 primary producers

20 880

What is illustrated by this diagram? A

A pyramid of energy shows the nutrient transfer less clearly than a pyramid of numbers

B

Energy loss to decomposers is higher than respiratory loss

C

Food chain efficiency is about 10%

D

The energy of the final trophic level is not used

24

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50 A student analyses the population of species X in an area S by using 1m X 1m quadrats (as shown in the diagram below). The numbers in the quadrats represent the number of species X. Calculate the density and frequency of species X

19

30

41

19

28

11

15

22

26

17

19

27

24

19

20

Density (m-2)

Frequency (%)

A

22.4

100

B

22.4

50

C

44.8

100

D

44.8

50

25

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964/2 PEPERIKSAAN PERCUBAAN SIJIL TINGGI PERSEKOLAHAN MALAYSIA NEGERI PAHANG DARUL MAKMUR 2009

BIOLOGY PAPER 2 Two and a half hours

Instruction to candidates: DO NOT OPEN THIS QUESTION PAPER UNTIL YOU ARE TOLD TO DO SO. Answer all questions in Section A. Write your answers in the spaces provided. Answer any four questions in Section B. Write your answers on your own answer sheets. Begin each answer on a fresh sheet of paper. Answers should be illustrated by large and clearly labelled diagrams wherever suitable.

For examiner’s use 1 2 3 4 5

Answers may be written in either English or Bahasa Malaysia. Arrange your answers in numerical order and tie the answer sheets to this question paper

6 7 8 9 10

Total

This question paper consists of 11 printed pages

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CONFIDENTIAL*

2 Section A [ 40 marks ] Answer all questions in this section.

1.

The diagram below shows the DNA replication fork during DNA replication

(a)

When does the replication occur in a cell cycle?

[1 mark]

………………………………………………………………………………………………………… (b)

Name enzymes C and D involved in replication and state their function. [4 marks]

C : …………………………………………………………………………………………………….. Function : ……………………………………………………………………………………………. ………………………………………………………………………………………………………… D : ……………………………………………………………………………………………………. Function : ……………………………………………………………………………………………. ………………………………………………………………………………………………………… (c)

Based on the diagram, there are two newly synthesized strands, strand X and Y (i)

Name both strands and state the way they are synthesized.

[2 marks]

X: …………………………………………………………………………………………….. Y: ………………………………………………………………………………………………

964/2 This Question paper is CONFIDENTIAL until the examination is over.

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(d)

3

State why DNA replication is said to be semi-conservative.

[1 mark]

……………………………………………………………………………………………………….. ……………………………………………………………………………………………………….. (e)

Explain why strand X is synthesized as fragments

[2 marks]

……………………………………………………………………………………………………….. ………………………………………………………………………………………………………… …………………………………………………………………………………………………………

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

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CONFIDENTIAL*

2.

4

The diagram below shows changes in the membrane potential of a neurone during the production of an action potential

(a)

Label phases A,B,C and the period labelled D as shown in the diagram.

[4 marks]

A : …………………………………………………………………………………………………….. B : ……………………………………………………………………………………………………. C : ……………………………………………………………………………………………………. D : …………………………………………………………………………………………………….

(b)

Describe how A is maintained

[2 marks]

………………………………………………………………………………………………………… ………………………………………………………………………………………………………… ……………………………………………………………………………………………………..

(c)

Distinguish between B and C

[2 marks]

………………………………………………………………………………………………………… ………………………………………………………………………………………………………… ………………………………………………………………………………………………………..

964/2 This Question paper is CONFIDENTIAL until the examination is over.

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5

………………………………………………………………………………………………………. (d)

Why is the potential of D less than A?

[1 mark]

……………………………………………………………………………………………………….. ……………………………………………………………………………………………………….. (e)

State the importance of D

[1 mark]

………………………………………………………………………………………………………. ……………………………………………………………………………………………………….

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

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CONFIDENTIAL*

6

3. Graphs S and T show the measurements of growth of a same plant, Zea mays.

(a)

Name the type of curve illustrated by graphs S and T.

[2 marks]

S:………………………………………………………………………………………………………… T:………………………………………………………………………………………………………… (b)

Explain what graphs S and T represent.

[2 marks]

S: ……………………………………………………………………………………………………….. T: ……………………………………………………………………………………………………….. (c)

Based on its lifespan, what type of plant is Zea mays known as?

[1 mark]

…………………………………………………………………………………………………………..

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

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CONFIDENTIAL* (d)

(i)

7

Describe the growth pattern in Zea mays

[2 marks]

………………………………………………………………………………………………………….. …………………………………………………………………………………………………………. (ii)

Explain how this type of growth pattern differs from that of woody plants [3 marks]

………………………………………………………………………………………………………….. ………………………………………………………………………………………………………….. ………………………………………………………………………………………………………….

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

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CONFIDENTIAL* 4.

8

The figure below shows a summary of a procedure designed to clone genes

Foreign DNA

Isolated plasmid

restriction

I

Recombinant DNA

II

Bacterial cell

III

SCREENING

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

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(a)

9

What is meant by recombinant DNA?

[1 mark]

…………………………………………………………………………………………………………. (b)

State briefly what happens at step I, II and III

[3 marks]

I : ……………………………………………………………………………………………………… II: ……………………………………………………………………………………………………… III: …………………………………………………………………………………………………….. r (c)

Why are the plasmid and foreign gene cut by using the same restriction enzyme? [1 mark]

………………………………………………………………………………………………………… (d)

State two ways in which bacteria can be screened for the presence of recombinant plasmids [ 2 marks]

………………………………………………………………………………………………………….. ………………………………………………………………………………………………………….. ………………………………………………………………………………………………………….. (e) (i) State two benefits of insulin produced by genetic engineering

[2 marks]

………………………………………………………………………………………………………….. ………………………………………………………………………………………………………….. …………………………………………………………………………………………………………. (ii) Unlike insulin, blood cannot be produced by genetic engineering. Explain why ?

[1 mark]

………………………………………………………………………………………………………… …………………………………………………………………………………………………………

964/2 This Question paper is CONFIDENTIAL until the examination is over.

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10

Section B [60 marks] Answer any four questions in this section.

5. (a) With reference to cellulose, explain briefly the term polymerization. State briefly the differences between the formation of polysaccharides and polypeptides [7 marks] (b) Describe the mechanism of action of an enzyme based on the induced fit model [8 marks] . 6. (a) State briefly the differences between anaerobic respiration that occur in plants and animals. [6 marks] (b) NAD and NADP are important molecules in plant cells. Describe in detail, the role of these molecules within a palisade mesophyll cell . [9 marks] 7. (a) Drugs affect the nervous system by altering the mechanism of synaptic transmission. By using a suitable example, describe the effects of a stimulant drug on the nervous system. [6 marks] (b) AIDS is an immunodeficiency disease caused by an RNA virus. Describe how the virus replicates in the host cell . [9 marks] 8. (a) Explain why no flowering response is shown by some plants that grow near highways. [5 marks] (b) Explain the changes that occur during the onset of labour in humans. [10marks] 9. (a) With reference to an example, explain what is meant by the following genetic terms (i) multiple alleles (ii) polygenic inheritance [6 marks] (b) In sweet corn plants, the alleles for red and smooth seed are dominant over the alleles for white and wrinkled seeds. Sweet corn plants with red and smooth seeds were crossed with plants with white and wrinkled seeds. A test cross was done using the F1 progeny and the results are as follows: Red, smooth 348 White. wrinkled 335 Red, wrinkled 40 White, smooth 39 By using suitable symbols, draw a genetic cross diagram to explain the results. [9 marks]

964/2 This Question paper is CONFIDENTIAL until the examination is over.

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11

10. (a) Explain why proper management and conservation of ecosystems are needed. [5 marks] (b) (i) Define sustainable development

[2 marks]

(ii) Explain the benefits of sustainable development techniques used in the management of forests. [8 marks]

964/2 This Question paper is CONFIDENTIAL until the examination is over.

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964/1

PEPERIKSAAN PERCUBAAN SIJIL TINGGI PERSEKOLAHAN MALAYSIA NEGERI PAHANG DARUL MAKMUR 2009

BIOLOGY PAPER 1 MULTIPLE-CHOICE

ANSWERS

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1

A

11

B

21

A

31

C

41

B

2

B

12

A

22

C

32

B

42

D

3

D

13

C

23

A

33

A

43

C

4

A

14

A

24

A

34

A

44

B

5

C

15

B

25

D

35

C

45

B

6

C

16

D

26

C

36

C

46

B

7

D

17

B

27

D

37

C

47

D

8

B

18

D

28

D

38

D

48

B

9

A

19

B

29

C

39

D

49

C

10

D

20

B

30

B

40

B

50

A

papercollection

PEPERIKSAAN PERCUBAAN SIJIL TINGGI PERSEKOLAHAN MALAYSIA NEGERI PAHANG DARUL MAKMUR 2009

BIOLOGY PAPER 2

MARKING SCHEME

papercollection

2

CONFIDENTIAL*

1. (a) - during S phase / interphase (b) - enzyme C :

1

1

DNA polymerase

1

- function :

adds complementary nucleotides to the growing strand

1

- enzyme D:

DNA ligase

1

- function :

links Okazaki fragments by forming phosphodiester bonds between the fragments

1

4

lagging strand, which is synthesized discontinuously leading strand, which is synthesized continuously

1 1

2

(d) - because each new DNA molecule contains one old and one new strand

1

1

(e) - the template for strand X is in the 5’ to 3’ end direction

1

(c) - strand X : - strand Y :

- DNA polymerase only adds nucleotides at the 3’ of a growing Strand - therefore, strand X has to be synthesized away from replication fork any 2

1 1 2 ------total 10

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

papercollection

3

CONFIDENTIAL*

2

(a)

(b)

A: B: C: D:

Resting potential depolarization repolarisation refractory period

1 1 1 1

- The active transport of sodium and potassium ions in and out across the membrane/ 3Na+ out, 2 K + in - The membrane is more permeable to potassium ions compared to sodium ions ; thus more potassium ions diffuse out of the neurone compared to sodium ions diffuse in

4

1 1 2

(c) B / depolarization Sodium-gated channels open

C / Repolarisation Potassium-gated channesl open

Sodium ions enter the neurone

Potassium ions leave the neurone

The inside of a neurone becomes positive

The inside of a neurone becomes negative

(d)

(e)

Any 2 pairs - the potassium-gated channels remain open / slow to close This allows further efflux of potassium ions

1

- Limits the frequency in which impulses may flow - Ensures that impulses flow in one direction along the nerve

2 1

1 1 any 1

1 total

964/2 This Question paper is CONFIDENTIAL until the examination is over.

--------10

CONFIDENTIAL*

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CONFIDENTIAL*

4

3 (a) - graph S : absolute growth curve - graph T : absolute growth rate curve

1 1

2

(b) - graph S : actual increase in size / area/ growth over a period of time - graph T : the increase in size / area / growth per unit time over a period of time

1 1

2

(c) - annual plant

1

1

1

2

(d) (i) (ii)

- Limited growth - the growth curve is a sigmoid curve

1

- woody plants are perennial plants - display unlimited growth - the growth curve is a series of sigmoid curve

964/2 This Question paper is CONFIDENTIAL until the examination is over.

1 1 1

3 ----Total 10

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

5

4 (a) - DNA that contains genes from more than one source

1

(b) - step I : Insertion of the DNA fragment into the plasmid

1

1

- step II : Transformation / introducing recombinant DNA into host cell - step III: DNA cloning / amplification making multiple copies of target gene

1 1

3

(c)

- to produce the same sticky / blunt ends which are complementary to each other

1

1

(d)

- cultured in a medium containing antibiotics/ ampicillin and X-gal before a blue-white screening - hybridization by using genetics / radioactive probes

1

1

1

1

(i)

1

(e)

- insulin produced through genetic engineering is similar to human insulin - insulin produced is non –allergic - cheaper / not costly

1 1

Any 2 (ii)

- because DNA / gene only codes for the synthesis of a protein and blood is not a protein

964/2 This Question paper is CONFIDENTIAL until the examination is over.

2 1

1

Total

----10

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

6

5. (a)

i.

answer polymerization is formation of long repeated units of monomer

ii.

by condensation with the removal of water molecules

1

iii.

in cellulose the monomer unit is β-glucose

1

iv

β-glucose linked together by β- 1,4 glycosidic bonds

1

[any 3]

i.

Polysaccharide does not involve ribosome

marks 1

maximum

polypeptide Involve ribosome

3

marks 1/0

ii. only involve one type of monomer – hexose molecule

Involve 20 different types of amino acid

1/0

iii. formation of glycosidic bonds between the monomers

formation of peptide bonds between the monomers

1/0

iv. does not involve gene / DNA

Involve gene / DNA to code the amino acid sequences

1/0

v. does not involve mRNA and tRNA

Involve mRNA and tRNA

1/0

vi. no transcription and translation stages

Involves transcription and translation stages

1/0

[ Any 4 pairs]

964/2 This Question paper is CONFIDENTIAL until the examination is over.

maximum

4

CONFIDENTIAL*

papercollection

7

CONFIDENTIAL*

(b)

i.

Answer the active site of an enzyme is flexible

marks 1

ii.

and not exactly complementary / fitting to the shape of the substrate

1

iii.

the active site of an enzyme can be modified when its interacts with substrate

1

iv.

the active site changes its shape slightly as the substrate enters

1

v.

the active site continues to change until the substrate is completely bound and final shape is determined

1

vi

making the fit more precise

1

vii

these structural changes may help to stabilized the transition state

1

viii.

when the substrate binds to the enzyme, it forms an enzyme substrate complex

1

ix

the substrate is then converted into products

1

x.

the products are released from the active sites

1

xi,

the enzymes return to its original conformation

1

xi.

Products are released from the active sites

1

xii.

the enzymes return to its original conformation

1

[any 8]

maximum

964/2 This Question paper is CONFIDENTIAL until the examination is over.

8

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

8

6. (a) Plants i. occurs in roots / seed / storage organ /tuber

Animals Occurs in skeletal muscles

ii. occurs when root are submerged // oxygen supply decreases

Occurs when muscles are actively Contracting

1/0

iii. products are ethanol and carbon dioxide

Product is lactic acid

1/0

iv. pyruvate changed / reduced to ethanal first then to its final product, ethanol

Pyruvate directly changed / reduced to its final product , lactic acid

1/0

v. ethanol is poisonous / can kill the plant cells

Lactic acid is still useful / not poisonous

1/0

vi. ethanol cannot be converted back to glucose

Lactic acid can be converted back to glucose

1/0

vii. anaerobic respiration is not needed to sustain the supply of ATP

anaerobic respiration is useful to sustain the supply of ATP

1/0

Any 6 pairs

marks 1/0

maximum

6

6 (b)

i.

Answer NAD involved in cellular respiration

ii.

2 molecules of reduced NAD / NADH produced in glycolysis

1

iii.

1 / 2 molecules of NADH produced in link reaction

1

iv.

3 / 6 molecules of NADH produced in Kreb cycle

1

v.

NAD accepts hydrogen / electron and transfers / carry to the inner mitochondrial membranes / cristae / cytochromes / ETC / matrix

1

vi.

NADP involved in photosynthesis

1

vii

viii.

marks 1

NADP accept electron and hydrogen ion forming NADPH in non-cyclic photophosphorylation / light dependent reaction / light reaction NADPH used in Calvin cycle / dark reaction / light independent reaction

1

1

ix.

NADPH is used to reduce CO2 / in reduction phase

1

x.

NADPH reduces glycerate -1,3-diphosphate into

1

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

papercollection

9

CONFIDENTIAL* glyceraldehydes- 3-phosphate / [ Any 9]

PGAL

maximum

9

7. (a)

i.

Answer cocaine present in the synaptic cleft

marks 1

ii.

cocaine bind to the transporter molecules

1

iii.

cocaine delays the breakdown of norepinephrine / dopamine / noradrenaline

1

iv.

reuptake/reabsorption of the norepinephrine / dopamine / noradrenalin from synaptic cleft is prevented / blocked

1

v.

norepinephrine / dopamine / noradrenalin remains / accumulates in the synaptic cleft

1

vi.

norepinephrine / dopamine / noradrenalin keep on binding to the receptors on the post-synaptic membrane

1

vii.

impulses will be generated repeatedly

1

viii.

causes continuous euphoria / intense pleasure

1

[ Any 6]

maximum

964/2 This Question paper is CONFIDENTIAL until the examination is over.

6

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

10

(b) i.

Answer HIV glycoprotein (gp 120) binds to CD4 receptor on the surface of the helper T cell / TH cell / host cell

marks 1

ii.

HIV protein envelope / lipoprotein / fuse with / to host cell membrane

1

iii.

Reverse transcriptase and viral RNA enter the host / TH cell by endocytosis

1

iv.

reverse transcriptase makes a DNA copy (cDNA) of the viral DNA // The first DNA strand is formed from RNA viral by using reverse transcriptase

1

v.

DNA copy (cDNA) / the first DNA strand becomes a template for the synthesis of complementary / second strand of viral DNA

1

vi.

the double stranded viral DNA formed then enters the nucleus and incorporated into the DNA of the host cell called provirus

1

vii.

each time the host’s DNA divides / replicates, viral DNA / provirus also replicates

1

viii.

this carries on for six years without any symptoms of disease are exhibited

1

ix.

the activated provirus will direct the host cell to synthesis new viral protein and viral RNA

1

x.

new viral protein and RNA assembled into new retroviruses

1

xi.

new retrovirus particles bud off from host cell membrane by exocytosis

1

xii.

finally, the virus spreads to all the helper T cells and destroys them

1

xiii.

resulting the destruction of the immune system

1

Any 9 Maximum

964/2 This Question paper is CONFIDENTIAL until the examination is over.

9

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

11

8. (a) marks 1

i.

answer these types of plants are short day plants The plants require a period of darkness equal to / longer than critical night length light / spotlight flashes from vehicles interrupt / shorten the period of darkness

1

ii. iii. iv.

causes the conversion of Pr into Pfr

1

v.

Pfr is the (biological) active form

1

vi.

high concentration / level of Pfr inhibit flowering in SDP’s

1 [any 5] Maximum

964/2 This Question paper is CONFIDENTIAL until the examination is over.

1

5

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

12

(b) Explain the changes happens and action of hormone on the onset of labour in human [10marks]

i.

answer estrogen level high in the end / last week of pregnancy

marks 1

ii.

stimulate the development of oxytocin receptor in uterine wall // increase the sensitivity of uterus muscle/myometrium to oxytocin

1

iii.

baby’s head / growing fetus press against the mother cervix

1

vi.

causing the cervix and uterine wall to stretch

1

v.

this stimulates maternal posterior pituitary to release oxytocin

1

vi.

and also stimulates fetal pituitary gland secretes ACTH

1

vii.

ACTH triggers fetal adrenal gland to secrete corticosteroids hormone

1

viii.

corticosteroids hormone triggers placenta to secrete prostaglandin

1

ix.

oxytocin also stimulates placenta / fetal to produce prostaglandin

1

x.

both prostaglandin and oxytocin stimulates a powerful contraction of myometrium / uterus wall

1

xi.

The more frequent the myometrium contracts, the more oxytocin / prostaglandin produced the uterus contraction also stimulates stretch receptors in the uterine wall and the cervix to trigger further release of oxytocin

1

xiii.

the cervix dilates / widen, its tissue softens and become more flexible and amniotic bag burst

1

xiv.

contractions become stronger and stronger / more frequent help to push baby down/out (Any 10) Maximum

1

xii.

964/2 This Question paper is CONFIDENTIAL until the examination is over.

1

10

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

13

9.(a) Multiple alleles:

Answer one particular characteristic / phenotype is controlled by three or more alleles

marks 1

ii.

each allele can occupy the same gene locus on a pair of homologous chromosomes

1

iii.

only two alleles can occupy a locus on a pair of homologous chromosomes at any time e.g. human ABO blood group

1

i.

iv.

1

Maximum

3

Polygenic inheritance:

i.

Answer one particular characteristic is controlled by two or more than two different genes

ii.

genes located at different loci on different chromosomes

1

iii.

each dominant allele has a small quantitative effect individually on the phenotype// phenotype produced is the total effect of all dominant genes present

1

iv.

e.g. height in human

1 Maximum

964/2 This Question paper is CONFIDENTIAL until the examination is over.

Marks 1

3

CONFIDENTIAL*

papercollection

14

CONFIDENTIAL*

(b) [9 marks] Parents (p)

1

Phenotype

Red smooth seed R

1

x

White wrinkled seed

R

Genotypes

r

r

s

s

x S

S

Meiosis

1

R

r

S

s

Gametes

Fertilisation

1

F1 generation genotype

Phenotype

R

r

S

s

All red and smooth seed

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

papercollection

15

CONFIDENTIAL*

Test cross for F1 progeny

] R 1

r

Genotype

1

r

s

s

x S

1

r

Phenotype

s

Red smooth seed

x

White wrinkled seed

R

r

R

r

r

S

s

s

S

s

Gametes

Recombinant/new combination of genes

1

1

1

Genotype offspring

Phenotypes

R

r

r

r

R

r

r

r

S

s

s

s

s

s

S

s

Red smooth

White wrinkled

Prental combination 346

335

Red wrinkled

White smooth

Recombinants forms as a result of crossing over 40

39

964/2 This Question paper is CONFIDENTIAL until the examination is over.

CONFIDENTIAL*

papercollection

16

CONFIDENTIAL* Maximum 9

10. (a)

i.

answer to sustain the biodiversity / flora and fauna of ecosystems

ii.

to maintain / improve the quality of life

1

iii.

to prevent the useful biological resources that have economical /medicinal value from extinct

1

iv.

to prevent the biogeochemical cycles from disrupted by the extinction of some species

1

v.

to prevent an extreme global climatic changes

1

vi.

to keep the ecosystems in their natural state (e.g. ecotourism) which provides aesthetic values for humans

1

vii.

to protect the environment for future generation

1

maximum

marks 1

5

(b)(i)

i.

answer is development that can continue indefinitely

ii.

can be achieved by minimizing the use of non-renewable resources

1

iii.

and controlling the use of renewable resources of the earth

1

Maximum

964/2 This Question paper is CONFIDENTIAL until the examination is over.

marks 1

2

CONFIDENTIAL*

papercollection

CONFIDENTIAL*

17

(b) (ii) techniques i. Replanting trees in areas that have been logged ii. Creating forest reserves

benefits Can decrease the carbon dioxide level in the Atmosphere // can reduced the greenhouse Effect

marks 1+1

- Able to avoid the complete destruction and maintain the biodiversity of the forests. - to keep the ecosystems in their natural state(e.g. ecotourism) which provides aesthetic values for humans

1+1

- to avoid lost of wildlife and potential resources [any 1] iii. Selective logging / only selects tree with certain diameters / species can be felled iv. Enforcement of laws and surveillance iv.

Recycling of paper

- to maintain soil fertility - to prevent flood, soil erosion - to avoid species extinct - to avoid loss of watershed areas - to avoid water pollution To prevent illegal logging

1+1

1+1

To reduce the demand for new raw materials

Any 4 pairs

964/2 This Question paper is CONFIDENTIAL until the examination is over.

Total

1+1

8

CONFIDENTIAL*

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