Rotary Vacuum Filter.docx

ROTARY VACUUM FILTER

Mud = 42.44920 tons/hr % Sucrose = 2% Temperature = 85 ˚C

Filtrate % Sucrose

Filter Cake = 11.2 tons/hr % Sucrose = 1.5% Material Balance Mud = Filter cake + Filtrate 42.44920 = 11.2 + Filtrate Filtrate = 31.2492

Component Mass Balance Sucrose Balance:

Mx m = Filter Cake (x c ) + Filtrate(x f ) 42.44920(0.02) = 11.2(0.015) + 31.2492(x f ) x f = 0.0218

FLASH TANK Milk of lime

F = 31.2492 tons/hr Tf = 220oF

Incondensable Gas

FLASH TANK Lime Juice Tp = 213oF

Assuming negligible amount of incondensable gas, Feed + Milk of Lime = Limed Juice + Incondensable gas Feed + Milk of Lime = Limed Juice

Amount of Milk of Lime used: CaO used: 31.2492

tons 0.5 kg CaO kg CaO × = 15.6246 hr 1ton cane hr

Weight of Lime: 15.6246

kg CaO 1kg Lime kg Lime × = 18.3818 hr 0.85 kg CaO hr

Milk of Lime: 18.3818

kg Lime 1kg solution 1ton tons of milk lime × × = 0.3342 hr 0.055 kg solid lime 1000 kg hr

Feed + Milk of Lime = Limed Juice tons tons 31.2492 + 0.3342 = Limed Juice hr hr tons Limed Juice = 31.5834 hr

CLARIFIER

Limed Juice=31.5834 tons/hr 14 Brix Tf = 213oF

CLARIFIER

Mud (2% sucrose)

Clarified Juice 16 Brix Tf = 213oF

Material Balance Limed Juice = Filter Cake + Clarified Juice

Component Mass Balance Fx f = Filter Cake(0.02) + Px p tons    31.5834  (0.14) = Filter Cake  0.02  + 0.16P hr   tons Clarified Juice, P = 27.0715 hr tons Mud = 4.5119 hr tons Sucrose(2%of mud) = 0.090238 hr