Primer Control Acumulativo Tercero Mediosolucion
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SOLUCIÓN PRIMER CONTROL ACUMULATIVO NOMBRE: __________________________________________ CURSO: ____________ FECHA: ___________ I.
Reduce las siguientes potencias:
1.
[( 3x)
2.
( 27
2
( )
⋅ 5x 3
p −1
] = [9x ⋅ 25x ]
2 3
⋅ 93− p
6 3
2
) = [(3 ) 2
3 p −1
⋅ (32 ) 3− p
3.
[ y ⋅ (3 y ) ] : 9 y
4.
w3−m m w
5.
(m
6.
a x + y ⋅ a 2 x −3 y = a3x − 2 y
7.
(3mn )
2 2 2
2
3 a −1
−1
]
3
[
] = [3 2
]
2
3 p −3
⋅ 36 − 2 p
] = [3 ] 2
[ ]
2
p +3 2
= 32 p + 6
= y 2 ⋅ 9 y 4 : 9 y 4 = 9 y 6 : 9 y 4 = 81y12 : 9 y 4 = 9 y 8
4
1
wm = 3−m = w 2 m−3 w
) ( 3
⋅ m3a+1 = m 6 a
2 4
[
= 225 x 8 = 2253 x 24
= 81m 4 n8
)
3
= m18 a
Reduce las siguientes potencias:
1.
[( 3x)
2.
( 27
2
( )
⋅ 5x 3
p −1
] = [9x ⋅ 25x ]
2 3
⋅ 93− p
6 3
2
) = [(3 ) 2
3 p −1
⋅ (32 ) 3− p
3.
[ y ⋅ (3 y ) ] : 9 y
4.
w3−m m w
5.
(m
6.
a x + y ⋅ a 2 x −3 y = a3x − 2 y
7.
(3mn )
2 2 2
2
3 a −1
−1
]
3
[
] = [3 2
]
2
3 p −3
⋅ 36 − 2 p
] = [3 ] 2
[ ]
2
p +3 2
= 32 p + 6
= y 2 ⋅ 9 y 4 : 9 y 4 = 9 y 6 : 9 y 4 = 81y12 : 9 y 4 = 9 y 8
4
1
wm = 3−m = w 2 m−3 w
) ( 3
⋅ m3a+1 = m 6 a
2 4
[
= 225 x 8 = 2253 x 24
= 81m 4 n8
)
3
= m18 a
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