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View Attempt 2 of 5 Title:
Practice Test 2
Started:
October 27, 2009 2:22 AM
Submitted:
October 27, 2009 2:22 AM
Time spent:
00:00:07
Total score: 0/20 = 0%
Total score adjusted by 0.0
Maximum possible score: 20
1. Consider the gas-phase reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g), for which Kp = 32 at 500 K. If the mixture is analyzed and found to contain 0.55 bar of Cl2, 0.65 bar of Br2 and 3.3 bar of BrCl, describe the situation:
Student Response
Value
Correct Answer
Feedback
1. Q < K and 0% more reactants will be made to reach equilibrium. 2. Q < K and 100% more products will be made to reach equilibrium. 3. Q > K and 0% more reactants will be made to reach equilibrium. 4. Q > K and 0% more products will be made to reach equilibrium. 5. Within 1 0% decimal place, Q = K and the reaction is at equilibrium
27-Oct-09 2:23 AM
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2. Consider the gas-phase reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g), for which Kp = 32 at 500 K. If the mixture is analyzed and found to contain 0.41 bar of Cl2, 0.45 bar of Br2 and 2.4 bar of BrCl, describe the situation:
Student Response
Value
Correct Answer
Feedback
1. Q < K and 0% more reactants will be made to reach equilibrium. 2. Q < K and 100% more products will be made to reach equilibrium. 3. Q > K and 0% more reactants will be made to reach equilibrium. 4. Q > K and 0% more products will be made to reach equilibrium. 5. Within 1 0% decimal place, Q = K and the reaction is at equilibrium Score:
0/1
3.
27-Oct-09 2:23 AM
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At a certain temperature, Kp for the reaction, N2O4(g) <=> 2 NO2(g) is 2.36 x 10-8. Calculate the value of Kp for the reaction, NO2(g) <=> 1/2 N2O4(g)
Student Response Answer not answered Score:
Value
Correct Answer
0%
6,509
0/1
4. Calculate Kc for the following reaction, 2 SO2(g) + O2(g) <=> 2 SO3(g); Kp = 30.83 at 48 o C Give your answer to 3 significant figures
Student Response Answer not answered Score:
Value
Correct Answer
0%
812
0/1
5. At a particular temperature, an equilibrium mixture the reaction below was found to contain 0.231 atm of Br2, 0.119 atm of F2 and 8.36 atm of BrF. Calculate the value of the equilibrium constant, Kp at this temperature. Br2(g) + F2(g) <=> 2 BrF(g)
Student Response Answer not answered Score:
Value
Correct Answer
0%
2,542.46
0/1
6. At a given temperature, 1.70 atm of Cl2 and 2.02 atm of Br2 are mixed and allowed to come to equilibrium. The equilibrium pressure of BrCl is found to be 1.409 atm. Calculate Kp for the reaction at this temperature. Cl2(g) + Br2(g) <=> 2 BrCl(g)
Student Response Answer not answered
3 of 9
Value
Correct Answer
0%
1.516
27-Oct-09 2:23 AM
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7. In the reaction below, 2.37 atm each of H2 and Br2 were placed into a 1.00 L flask and allowed to react: H2(g) + Br2(g) <=> 2 HBr(g) Given that Kc = 76.1, calculate the equilibrium pressure of H2.
Student Response Answer not answered Score:
Value
Correct Answer
0%
0.44
0/1
8. Consider the reaction H2(g) + Cl2(g) <=> 2 HCl(g), which is exothermic as written. What would be the effect on the equilibrium position of decreasing the volume of the reaction container?
Student Response
Value
Correct Answer Feedback
1. Reaction 0% would go to the right, making more "products" 2. Reaction 0% would go to the left, making more "reactants" 3. Reaction 0% would go to the left, making more "products" 4. Reaction 0% would go to the right, making more "reactants"
27-Oct-09 2:23 AM
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5. No change 100% on the equilibrium position Score:
0/1
9. Consider the reaction H2(g) + Br2(g) <=> 2 HBr(g), which is exothermic as written. What would be the effect on the equilibrium position of removing Br2(g)?
Student Response
Value
Correct Answer Feedback
1. Reaction 0% would go to the right, making more "products" 2. Reaction 100% would go to the left, making more "reactants" 3. Reaction 0% would go to the left, making more "products" 4. Reaction 0% would go to the right, making more "reactants" 5. No change 0% on the equilibrium position Score:
0/1
10.
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What is the pOH of a 0.03667 M solution of HI?
Student Response Answer not answered Score:
Value
Correct Answer
0%
12.56
0/1
11. Give the conjugate acid of HSO4-. Write it ignoring super and subscripts (so, HPO42- would be HPO42-)
Student Response 1. not answered Score:
Value
Correct Answer
0%
Equals H2SO4 (100%)
0/1
12. Is an aqueous solution of NaCN acidic, basic or neutral (use A, B or N)?
Student Response 1. not answered Score:
Value
Correct Answer
0%
Equals B (100%)
0/1
13. Is an aqueous solution of NaCl acidic, basic or neutral (use A, B or N)?
Student Response 1. not answered Score:
Value
Correct Answer
0%
Equals N (100%)
0/1
14. What is the pH of 0.314 M potassium benzoate? The Ka of benzoic acid, C6H5COOH is 6.3 x 10-5.
Student Response Answer not answered
Value
Correct Answer
0%
8.85
27-Oct-09 2:23 AM
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15. What is the pH of 0.250 M sodium benzoate? The Ka of benzoic acid, C6H5COOH is 6.3 x 10-5.
Student Response Answer not answered Score:
Value
Correct Answer
0%
8.80
0/1
16. The Ka of phenol, C6H5OH, is 1.00 x 10-10. What is [C6H5O-] in a 0.366 M solution of phenol? Use E notation and 3 significant figures.
Student Response Answer not answered Score:
Value
Correct Answer
0%
6.05E-6 (6.05 × 10-6)
0/1
17. A 0.00643 mol sample of a weak acid, HY, is dissolved in enough water to form 0.0217 L of solution. If the pH of the solution is 3.72, what is the Ka of HY? Use E notation with 3 significant figures.
Student Response Answer not answered Score:
Value
Correct Answer
0%
1.23E-7 (1.23 × 10-7)
0/1
18. Select the weaker acid from each of the following pairs: I. HI or HBr II. H3AsO3 or H2SeO3 III. HNO3 or HNO2
Student Value Response
Correct Answer Feedback
27-Oct-09 2:23 AM
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1. I. HBr II. 0% H2SeO3 III. HNO2 2. I. HBr II. 100% H3AsO3 III. HNO2 3. I. HBr II. 0% H3AsO3 III. HNO3 4. I. HI II. 0% H3AsO3 III. HNO2 5. I. HI II. 0% H2SeO3 III. HNO3 Score:
0/1
19. A first order reaction has a rate constant of 0.740 at 15 o C. Given that the Arrhenius constant for the reaction is 7.52 x 1011 sec -1, calculate the value of the activation energy in KILOJOULES (enter answer in E format to 3 significant figures. Remember - 2.41 would be 2.41E0)
Student Response Answer not answered Score:
Value
Correct Answer
0%
66.2
0/1
20. The rate of formation of carbon tetrachloride from chloroform, CHCl3(g) + Cl2(g) => CCl4(g) + HCl(g) is first order in CHCl3 and half order in Cl2. Which step of the proposed mechanism must be slow in order to agree with this rate law? 1. Cl2(g) => 2 Cl(g) 2. Cl(g) + CHCl3(g) => HCl(g) + CCl3(g) 3. CCl3(g) + Cl(g) => CCl4(g)
Student Value Response 1. 1
8 of 9
Correct Answer Feedback
0%
27-Oct-09 2:23 AM
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2. 2
100%
3. 3
0%
Score:
0/1
Done
9 of 9
27-Oct-09 2:23 AM