Practice Test 2

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  • Words: 1,180
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1 of 8

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View Attempt 1 of 5 Title:

Practice Test 2

Started:

October 27, 2009 12:47 AM

Submitted:

October 27, 2009 2:07 AM

Time spent:

01:20:20

Total score: 12/20 = 60%

Total score adjusted by 0.0

Maximum possible score: 20

1. Consider the gas-phase reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g), for which Kp = 32 at 500 K. If the mixture is analyzed and found to contain 1.2 bar of Cl2, 1.6 bar of Br2 and 7.9 bar of BrCl, describe the situation:

Student Response

Value

Correct Answer

Feedback

1. Q < K and 0% more reactants will be made to reach equilibrium. 2. Q < K and 0% more products will be made to reach equilibrium. 3. Q > K and 100% more reactants will be made to reach equilibrium. 4. Q > K and 0% more products will be made to reach equilibrium. 5. Within 1 0% decimal place, Q = K and the reaction is at equilibrium

27-Oct-09 2:22 AM

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Score:

1/1

2. At a given temperature, Kp for the reaction below is 0.24. In a given experiment, 0.10 atm of each product and 0.0020 atm of NOBr are intoduced into a container. In which direction will the reaction proceed, or is it at equilibrium? 2 NOBr(g) <=> 2 NO(g) + Br2(g)

Student Response

Value

1. Reaction will go to the left

100%

2. Reaction will go to the right

0%

Correct Answer

Feedback

3. Reaction is 0% an equilibrium Score:

1/1

3. At a certain temperature, Kp for the reaction, H2(g) + Br2(g) <=> 2 HBr(g) is 0.00738. Calculate the value of Kp for the reaction, HBr(g) <=> 1/2 H2(g) + 1/2 Br2(g)

Student Response Answer 11.6 Score:

Value

Correct Answer

100%

12

1/1

4. Calculate Kc for the following reaction, H2(g) + I2(g) <=> 2 HI(g); Kp = 61.40 at 25.0 o C

Student Response Answer 61.40 Score:

2 of 8

Value

Correct Answer

100%

61.4

1/1

27-Oct-09 2:22 AM

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5. At a particular temperature, an equilibrium mixture the reaction below was found to contain 0.741 atm of I2, 0.644 atm of Cl2 and 4.81 atm of ICl. Calculate the value of the equilibrium constant, Kp at this temperature. I2(g) + Cl2(g) <=> 2 ICl(g)

Student Response Answer .485 Score:

Value

Correct Answer

0%

48.48

0/1

6. At a given temperature, 1.33 atm of H2 and 1.79 atm of Cl2 are mixed and allowed to come to equilibrium. The equilibrium pressure of HCl is found to be 1.573 atm. Calculate Kp for the reaction at this temperature. H2(g) + Cl2(g) <=> 2 HCl(g)

Student Response Answer 4.54 Score:

Value

Correct Answer

100%

4.537

1/1

7. In the reaction below, 2 atm of H2 and 4 atm of Cl2 were placed into a 1.00 L flask and allowed to react: H2(g) + Cl2(g) <=> 2 HCl(g) Given that Kp at 700 K = 54, calculate the equilibrium pressure of HCl.

Student Response Answer .705 Score:

Value

Correct Answer

0%

3.75

0/1

8. Consider the reaction Cl2(g) + Br2(g) <=> 2 BrCl(g), which is endothermic as written. What would be the effect on the equilibrium position of removing Br2(g)?

Student Response

3 of 8

Value

Correct Answer

Feedback

27-Oct-09 2:22 AM

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4 of 8

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1. Reaction 0% would go to the right, making more "products" 2. Reaction 100% would go to the left, making more "reactants" 3. Reaction 0% would go to the left, making more "products" 4. Reaction 0% would go to the right, making more "reactants" 5. No change 0% on the equilibrium position Score:

1/1

9. Consider the reaction 2 NO2(g) <=> N2O4(g), which is exothermic as written. What would be the effect on the equilibrium position of increasing the temperature?

Student Response

Value

Correct Answer

Feedback

1. Reaction 0% would go to the right, making more "products" 2. Reaction 100% would go to the left, making

27-Oct-09 2:22 AM

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more "reactants" 3. Reaction 0% would go to the left, making more "products" 4. Reaction 0% would go to the right, making more "reactants" 5. No change 0% on the equilibrium position Score:

1/1

10. What is the pOH of a 0.05848 M solution of HNO3?

Student Response Answer 12.77 Score:

Value

Correct Answer

100%

12.77

1/1

11. Give the conjugate base of H3PO4. Write it ignoring super and subscripts (so, HPO42- would be HPO42- HSO4-)

Student Response 1. HPO43-

Score:

Value

Correct Answer

0%

Equals H2PO4- (100%) Equals H2PO41- (100%)

0/1

12. Is an aqueous solution of LiClO4 acidic, basic or neutral (use A, B or N)?

27-Oct-09 2:22 AM

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Student Response 1. N Score:

Value

Correct Answer

100%

Equals N (100%)

1/1

13. Is an aqueous solution of K3PO4 acidic, basic or neutral (use A, B or N)?

Student Response 1. B Score:

Value

Correct Answer

100%

Equals B (100%)

1/1

14. What is the pH of 0.418 M ammonium iodide, NH4I? The Kb of ammonia is 1.8 x 10-5.

Student Response Answer 1.14 Score:

Value

Correct Answer

0%

4.82

0/1

15. 6What is the pH of 0.355 M triethylammonium bromide, (C2H5)3NHBr. The Kb of triethylamine, (C2H5)3N, is 5.2 x 10-4.

Student Response Answer 1.21 Score:

Value

Correct Answer

0%

5.58

0/1

16. The Ka of formic acid, HCOOH is 1.8 x 10-4. What is [OH-] in a 0.289 M solution of HCOOH? Use E notation and 3 significant figures.

Student Response Answer 7.08E-6 Score:

6 of 8

Value

Correct Answer

0%

1.39E-12 (1.39 × 10-12)

0/1

27-Oct-09 2:22 AM

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17. Calculate the [OH-] in a solution of 0.550 M diethylamine, Kb = 8.6 x 10-4?

Student Response Answer 2.17E-2 Score:

Value

Correct Answer

100%

0.0217

1/1

18. Select the stronger acid from each of the following pairs: I. HI or HBr II. H3AsO3 or H2SeO3 III. HNO3 or HNO2

Student Value Response

Correct Answer

Feedback

1. I. HBr II. 0% H2SeO3 III. HNO2 2. I. HBr II. 0% H3AsO3 III. HNO2 3. I. HBr II. 0% H3AsO3 III. HNO3 4. I. HI II. 0% H3AsO3 III. HNO2 5. I. HI II. 100% H2SeO3 III. HNO3 Score:

1/1

19. A first order reaction has a rate constant of 0.730 at 25 o C and 8.03 at 50 o C. Calculate the value of the activation energy in KILOJOULES (enter answer in E format to 3 significant figures. Remember - 2.41 would be 2.41E0)

Student Response Answer not answered

7 of 8

Value

Correct Answer

0%

76.8

27-Oct-09 2:22 AM

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Score:

0/1

20. The proposed mechanism for a reaction is Cl2 => Cl+ + Cl- Slow Cl- + H2S => HCl + HS- Fast Cl+ + HS- => HCl + S Fast Which of the following would be a rate law for the reaction?

Student Response

Value

1. rate = k[Cl2]

100%

2. rate = k[Cl2][H2S]

0%

Correct Answer

Feedback

3. rate = 0% k[Cl2]1/2[H2S] 4. rate = k[Cl-][H2S]

0%

5. rate = [Cl+][Cl-]

0%

Score:

0/1

Done

8 of 8

27-Oct-09 2:22 AM

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