Practice Test 2

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  • Words: 1,233
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View Attempt 3 of 5 Title:

Practice Test 2

Started:

October 27, 2009 11:42 AM

Submitted:

October 27, 2009 11:42 AM

Time spent:

00:00:07

Total score: 0/20 = 0%

Total score adjusted by 0.0

Maximum possible score: 20

1. Consider the gas-phase reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g), for which Kp = 32 at 500 K. If the mixture is analyzed and found to contain 0.37 bar of Cl2, 0.47 bar of Br2 and 2.4 bar of BrCl, describe the situation:

Student Response

Value

Correct Answer

Feedback

1. Q < K and 0% more reactants will be made to reach equilibrium. 2. Q < K and 0% more products will be made to reach equilibrium. 3. Q > K and 100% more reactants will be made to reach equilibrium. 4. Q > K and 0% more products will be made to reach equilibrium. 5. Within 1 0% decimal place, Q = K and the reaction is at equilibrium

27-Oct-09 11:42 AM

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Score:

0/1

2. Consider the gas-phase reaction, N2(g) + 3 H2(g) <=> 2 NH3 (g), for which Kp = 43 at 400 K. If the mixture is analyzed and found to contain 1.8 bar of N2, 0.6 bar of H2 and 4.2 bar of NH3, describe the situation:

Student Response

Value

Correct Answer

Feedback

1. Q < K and 0% more reactants will be made to reach equilibrium. 2. Q < K and 0% more products will be made to reach equilibrium. 3. Q > K and 100% more reactants will be made to reach equilibrium. 4. Q > K and 0% more products will be made to reach equilibrium. 5. Within 1 0% decimal place, Q = K and the reaction is at equilibrium Score:

0/1

3.

2 of 9

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At a certain temperature, Kp for the reaction, N2(g) + 3 H2(g) <=> 2 NH3 (g) is 0.00212. Calculate the value of Kp for the reaction, NH3 (g) <=> 1/2 N2(g) + 3/2 H2(g).

Student Response Answer not answered Score:

Value

Correct Answer

0%

22

0/1

4. Calculate Kc for the following reaction, H2(g) + I2(g) <=> 2 HI(g); Kp = 39.50 at 25.0 o C

Student Response Answer not answered Score:

Value

Correct Answer

0%

39.5

0/1

5. At a particular temperature, an equilibrium mixture the reaction below was found to contain 0.509 atm of I2, 0.467 atm of Cl2 and 5.13 atm of ICl. Calculate the value of the equilibrium constant, Kp at this temperature. I2(g) + Cl2(g) <=> 2 ICl(g)

Student Response Answer not answered Score:

Value

Correct Answer

0%

110.71

0/1

6. Ammonia can be oxidized in oxygen as shown: 4 NH3(g) + 3 O2(g) <=> 2 N2(g) + 6 H2O(g). When 0.762 mol of NH3 and 0.552 mol of O2 are placed in a 1.00 L container at a certain temperature, the equilibrium [N2] is 0.184. Calculate the value of Kc for the reaction. Give your answer to 3 significant figures.

Student Response Answer not answered

3 of 9

Value

Correct Answer

0%

1.89E0 (1.89 × 100)

27-Oct-09 11:42 AM

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Score:

0/1

7. In the reaction below, 8.77 atm each of H2 and I2 were placed into a 1.00 L flask and allowed to react: H2(g) + I2(g) <=> 2 HI(g) Given that Kp = 68.4, calculate the equilibrium pressure of I2.

Student Response Answer not answered Score:

Value

Correct Answer

0%

1.71

0/1

8. Consider the reaction H2(g) + Cl2(g) <=> 2 HCl(g), which is exothermic as written. What would be the effect on the equilibrium position of adding HCl(g)?

Student Response

Value

Correct Answer Feedback

1. Reaction 0% would go to the right, making more "products" 2. Reaction 100% would go to the left, making more "reactants" 3. Reaction 0% would go to the left, making more "products" 4. Reaction 0% would go to the right, making more "reactants"

27-Oct-09 11:42 AM

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5. No change 0% on the equilibrium position Score:

0/1

9. Consider the reaction N2(g) + 3 H2(g) <=> 2 NH3(g), which is exothermic as written. What would be the effect on the equilibrium position of removing H2(g)?

Student Response

Value

Correct Answer Feedback

1. Reaction 0% would go to the right, making more "products" 2. Reaction 100% would go to the left, making more "reactants" 3. Reaction 0% would go to the left, making more "products" 4. Reaction 0% would go to the right, making more "reactants" 5. No change 0% on the equilibrium position Score:

0/1

10.

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What is the pH of a 0.02874 M solution of HCl?

Student Response Answer not answered Score:

Value

Correct Answer

0%

1.54

0/1

11. Give the conjugate acid of H2PO4-. Write it ignoring super and subscripts (so, HPO42- would be HPO42-)

Student Response 1. not answered Score:

Value

Correct Answer

0%

Equals H3PO4 (100%)

0/1

12. Is an aqueous solution of NaCl acidic, basic or neutral (use A, B or N)?

Student Response 1. not answered Score:

Value

Correct Answer

0%

Equals N (100%)

0/1

13. Is an aqueous solution of CH3NH3I acidic, basic or neutral (use A, B or N)?

Student Response 1. not answered Score:

Value

Correct Answer

0%

Equals A (100%)

0/1

14. A weak base, B, has a Kb value of 8.88 x 10-5. What is the pKa of HB+?

Student Response Answer not answered

6 of 9

Value

Correct Answer

0%

9.95

27-Oct-09 11:42 AM

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Score:

0/1

15. What is the pH of 0.805 M potassium formate, HCOOK? The Ka of formic acid, HCOOH is 1.8 x 10-4.

Student Response Answer not answered Score:

Value

Correct Answer

0%

8.83

0/1

16. The weak acid, HQ has a pKa of 4.37. Calculate the [OH-] in a 0.140 M solution of HQ. Use E notation and 3 significant figures.

Student Response Answer not answered Score:

Value

Correct Answer

0%

4.09E-12 (4.09 × 10-12)

0/1

17. Calculate the pH of 0.647 M ethanolamine, Kb = 3.2 x 10-5?

Student Response Answer not answered Score:

Value

Correct Answer

0%

11.66

0/1

18. Select the weaker acid from each of the following pairs: I. HBr or H2Se II. HClO3 or H2SO3 III. H2SO3 or H2SO4

Student Value Response

Correct Answer Feedback

1. I. HBr, 0% II. HClO3 III. H2SO4

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2. I. HBr, 0% II. H2SO3 III. H2SO4 3. I. H2Se, 0% II. HClO3 III. H2SO3 4. I. H2Se, 100% II. H2SO3 III. H2SO3 5. I. HBr, 0% II. H2SO3 III. H2SO3 Score:

0/1

19. A first order reaction has an activation energy of 54.5 kJ/mol and a frequency factor (Arrhenius constant) of 6.49 x 1013 sec -1. Calculate the rate constant at 20 o C.

Student Response Answer not answered Score:

Value

Correct Answer

0%

12,471

0/1

20. The proposed mechanism for the reaction below is a one-step mechanism. NO + O3 => NO2 + O2 Which of the following would be a rate law for the reaction?

Student Response

Value

Correct Answer Feedback

100% 1. rate = k[NO][O3] 2. rate = k[O3]

0%

3. rate = k[NO]

0%

4. rate = 0% k[O][NO3]

27-Oct-09 11:42 AM

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5. rate = 0% k[NO2][O2] Score:

0/1

Done

9 of 9

27-Oct-09 11:42 AM

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