Management Aptitude Test 21 November

MANAGEMENT APTITUDE TEST AFTERSCHO☺OL

– DEVELOPING CHANGE MAKERS CENTRE FOR SOCIAL ENTREPRENEURSHIP PGPSE PROGRAMME – World’ Most Comprehensive programme in social entrepreneurship & spiritual entrepreneurship OPEN FOR ALL FREE FOR ALL

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

MANAGEMENT APTITUDE TEST Dr. T.K. Jain.

AFTERSCHO☺OL Centre for social entrepreneurship Bikaner M: 9414430763 [email protected] www.afterschool.tk, www.afterschoool.tk www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : When you draw a circle, you use a compass. • Correct : use proper words – there is nothing like compass, it is always a compasses. • When you draw a circle, you use compasses. • Similarly, we use trousers, scissors, spectacles, goggles etc.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : Shakuni was an expert in the game of dies. • Plural of die is dice. • Correct sentence : • Shakuni was an expert in the game of dice.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : Inventions are made by genii. • The word genius has two plurals – 1. Genii and 2. Geniuses • Genii (is plural in the sense of spirit) • Geniuses is plural in the sense of brilliant persons. • So correct sentence is : • Inventions are made by geniuses. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : The cloths he wears are costly. • There are two plurals of cloth – 1. cloths 2. clothes. • Cloths means pieces of cloth • Clothes means garments • Thus the correct sentence should be : • The clothes he wears are costly.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Mrs. Gandhi was Rajiv’s mother. Sanjay was Mrs. Gandhi’s son. So Rajiv and Sanjay were brethren. • Brethren means members of a community. Here we should use the word brothers and not brethren. • Mrs. Gandhi was Rajiv’s mother. Sanjay was Mrs. Gandhi’s son. So Rajiv and Sanjay were brethors. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : A realist sees a thing in its true colour. • Colour means red, blue etc. Colours means appearance. Thus the correct sentence should be : A realist sees a thing in its true colours.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : R B S Kochar , the custom official, virtually put an end to smuggling. • Custom means beliefs, • Customs means tax that is levied on import or export. Here we should use the word customs, • R B S Kochar, the customs official, virtually put an end to AFTERSCHO☺OL's smuggling.MATERIAL FOR PGPSE PARTICIPANTS www.afterschoool.tk

Correct it : The team members should listen to the advices given by the captain and the manager. • We don’t use advice in plural form as advices – because advice is not considered countable. • Therefore correct sentence should be : • The team members should listen to the advice given by the captain and the manager. • Or • The team members should listen to the the pieces of advice given by the captain and the manager. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : A book is printed on papers. • Papers means documents, therefore don’t use papers. • Correct sentence: • A book is printed on paper.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : This cattle has been in trouble ever since the famine. • Cattle is plural therefore, correct it as : • These cattle have been in trouble ever since the famine.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : Physics are a branch of science. • Physics is a singular, so correct sentence should be : • Physics is a branch of science.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

I have a lot of irons in my electric shop. • Irons means fetters. • Iron means metal and also the electric instrument • The correct sentence should be: • I have a number of iron in my electric shop.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : I don’t have any good in my store. • Correct sentence : I don’t have any goods in my store.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : cart’s wheel was broken • Don’t use appostrophe comma with nonliving sentences (there are some exceptions). • Correct sentence: • The wheel of cart was broken.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : I am going to Sumit’s the creative singer’s home. • Corrected sentence should be: • I am going to the home of Sumit, the creative Singer • Or • I am going to Sumit the creative singer’s home.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : Mr. Abul Kalam is a man of letter. • Mr. Abul Kalam is a man of letters.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it: My means is small. • Means here mean wealth. • When we use it in the sense of wealth, it is always plural. • Thus correct sentence should be : • My means are small.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : He has a poultry. • He has a poultry farm. • (poultry is plural, but it can be used as a singular form also – as it is used here).

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solve it : the baby loves his toys. • Don’t use his, instead use its. • The baby loves its toys.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : the mouse lost his tail, when the cat pounced at it. • Corrected sentence : • the mouse lost its tail, when the cat pounced on it.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : We don’t need no education. • • • •

Corrected sentence should be : We don’t need any education. Or We don’t need education.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : Never did the sky looked so beautiful. • Never did the sky look so beautiful.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Correct it : I am much glad to sce you. • Corrected sentence : • I am very glad to see you.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Five horses, Red, White, Grey, Black and Spotted participated in a race. As per the rules of the race, the persons betting on the winning horse get four times the bet amount and those betting on the horse that came in second get thrice the bet amount. Moreover, the bet amount is returned to those betting on the horse that came in third, and the rest lose the bet amount. Bitthal bets Rs.3000, Rs.2000 and Rs.1000 on Red, White and Black horses respectively and ends up with no profit and no loss. Answer the question on next slide.. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

question • • • • • • • •

Which of the following cannot be true? (1) At least two horses finished before Spotted (2) Red finished last (3) There were three horses between Black and Spotted (4) There were three horses between White and Red (5) Grey came in second Solution : (4) is the right answer – this is not possible – rest all are possible.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution – the possibilities are listed down

Red

3000 last

last

3rd

White

2000 2nd

3rd

last

Black

1000 last

1st

2nd

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Two candles of the same length are lighted at the same time. The first isconsumed in 6 hours and the second in 4 hours. Assuming that each candle burns at a constant rate, in how many hours after being lighted was the first candle twice the length of the second? • Options : (1.) 3 hours • (2) 7 hours • (3) 11 hours

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Let us try with options. Let us try with 3 hours. In 3 hours, the first is half burnt (it is completely burnt in 6 hours). In 3 hours, the second is 3/4 finished (as it is completely burnt in 4 hours). • Thus second is 25% left, while the first is 50% left, thus the first is double the second candle. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Efficiencies of two men are in the ratio 2 : 3. If the first - takes 30 days to do a piece of work, the time required when both of them work together on ajob twice as big as the first, Will be

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • The first takes 30 days, thus the second takes 20 days. • 1/30 + 1/20 = 50 / 600 = 1/12 or 12 days will be required for similar work. But the work is twice this work, therefore the dates will be double – so 12*2 = 24 days will be requied by the two working together. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Three factories of a corporation are capable of manufacturing a particular part of Car. Two of the factories can each produce 100,000 parts in 15 days. The third factory can produce them 30% faster. How many days would it take to produce a million parts with all the three working simulltaneously? (Correct to the nearest day) www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • The factories make as under: • In one day: • One day’s production: 100000/15 + 100000/15 + 130000/15 =22000 • Days : 10,00,000/22000 • =46 days approximately.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

• A and B together can do a job in 12 days. Had A done half of the job and then B, the remaining half, the whole job would have been carried out in 25 days. How much time would it take for A and B separately to do the job, if A is a better worker?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Let us assume that A takes 1/X days to complete the work and B takes 1/y days to complete the work. • 1/ A + 1/B = 1/12 • Or X + Y = 1/12 • A + B = 50 (because they take 25 days total to complete half work each, so to complete full work each, it will take them 50 days. ) the answer is 30 and 20 days. Thus A takes 30 days and B takes 20 days. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

GOTI agrees to build a wall 132 feet long in 36 days and employs 16 men. If after 20 days he finds that only 60 feet of the wall is finished, then how many more men all, now working 6/5 as many hours, will be required to finish the work on time?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

SOLUTION … • Start with the number of men. If no. of hours will increase the man required will reduce. • 16 * 5/6 *72/60* 20/16 • =20 persons are required, 16 are already there, wo we need 4 additional persons. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Eight men with 2 boys can do a piece of work in 7 days, which 25 men with 13 boys can do in 2 days. What fraction of the whole work, can be done in 1 day by 11 men with 20 boys?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution… • • • •

8 M + 2 B = 1/7 25 M + 13B = ½ (solving these…) 104 M + 26B=13/7 50M + 26B = 1 (deduct the second from 1st) 54 M = 6/7 or M = 6/ (7*54) = 1/63 or 1 Man will do it in 63 day. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution … • • • • • •

8 *1/63 + 2 B = 1/7 2B = 1/7 – 8/63 2 B = 1/63 B = 1/126 or 1 boy will do it in 126 days. 11/63 + 20 / 126 =42/126 = 1/3 or 3 days will be required to complete the work. In one day 1/3rd work will be completed. Answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

If 5 men can paint a room 50 m long, 6 m high & 13 m wide working @ 10 hours per day in 6 days, then how many days of 9 hours each will 10 men need to paint a room 40 m long, 7 m high and 10 m wide. (Assume all the walls and ceiling are painted leaving the floor) www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution … • • • •

Area of 4 walls 2 *H (L+W) =2*6(50+13) = 756 + 650 New area: 2*7 (40+10) = 700+400 What is asked – no. of days, so start with no. of days. • 6 * 5/10 *1100/1406*10/9 • =2.6 days answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

If 7 men or 8 women or 10 boys can finish a piece of work in 24 days each of 9 hours, then find how many men with the help of 4 women and 5 boys can finish the work in 18 days eachof 6 hours.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution … • • • • •

Let us convert 4 women into boys. 10/8 *4 = 5 boys. So now we have 5+5 = 10 boys. 10*24/18* 9/6 = 20 Thus 20 boys are required, but we have 10 boys, so 10 more boys are required. 10 boys are equal to 7 men, so 7 more men are required to complete the work. Answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A tradesman marks his goods at 30% above the cost price. If he allows a discount of 3 paise per rupee off the marked price, then what percentage of profit does he make? • Let us assume the cost to be Rs. 100. • Print price = 130. • Discount = 3% of 130 = 3.9 • Net price realised = 130-3.9 = 126.1 • Thus profit earned is 26.1% answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solve it • The result of an exam is given below. Out of 1000 students who appeared • (I) 658 failed in Physics • (ii) 166 failed in Physics and Chemistry • (iii) 372 failed in Chemistry, 434 failed in Physics and Maths • (iv) 590 failed in Maths, 126 failed in Maths & Chemistry. How many passed in individual papers ? www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • We have assumed that there is no student who has failed in all the three papers. • Passed in physics alone = 126 • Passed in chemistry alone = 434 • Passed in maths : = 166.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A man sold 250 chairs and has a gain equal to selling price of 50 chairs. What is his profit percent? • Let us assume that selling price of a chair is Re. 1 each. • Total sales collected = 250 • Profit = 50 • Profit is always compared to Cost. Therefore calculate cost = 250-50 = 200 • Profit in % = 50/200 *100 = 25% answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

‘A’ sells a car to ‘B’ at 10% profit. ‘B’ sells it to ‘C’ at 20% loss. If the cost of ‘A’ was Rs.5000, then find the cost of ‘C • Let us assume that the cost of A = 100. • He sells it to B at 110. • B sells it to C at reduced price = 110*80/100 = 88 • Thus cost of C should be 88/100 *5000 = 4400 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A Car costs Rs.48000. Its value depreciates by 30% in the first year and in each subsequent year the depreciation is 20% of the value at the beginning of that year. The value of the Car after 3 years will be ? • 48000*70/100*80/100*80/100 = 21504 www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Sunil bought 5 dozen apples at the rate of Rs.15 per dozen. He spent Rs.15 on transportation. If he sold the apples at the rate of Rs.24 per dozen, what was his profit percentage? • His total cost is 15*5 = 75 = fixed cost Rs. 15 = 90 • Sale = 24*5 = 120 • Thus profit is 120-90 = 30 • Profit in % = 30/90 *100= 33% answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

a dealer announces 20% reduction in the unit price of an article. As a result, his sales volume increases by 20%. what is the overall gain/loss to the dealer? • Let us assume that his selling price was Rs. 10 and he sold 10 units. (total 100) • Now Selling price is 8 and units sold are 12. Thus there is loss of 4 (96 as aginst 100). In such cases there is always loss (20*20 / 100) = 4% loss. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Goti sold his cricket bat for Rs.75 and got a percentage of profit equal to the cost price. The cost price of the watch is • Let us try for rs. 50. • Profit is 50% of 50 = 25 • Thus sale price = 50 + 25 = 75 answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A man’s petrol bill in July is Rs.200. In August, the price of petrol increases by 10% and his consumption is reduced by 10%. Find his petrol bill in August. • In such cases, just reduce it by (10*10/100) = 1%. • Thus the budget in next month is 200*99/100 = 198 Rupees. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

After enjoying three successive discounts of 30% each, a person paid Rs.3087 for the article. What must be the marked price of the article? • If price is 100, the price paid is 100*70/100*70/100*70/100 • =34.3 • Thus marked price is 3087*100/(34.3) = 9000 is the marked price. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

I sell 16 sheep at a gain of 12.5% and 20 more at a certain gain percent. If I gain 25% on the whole, how much percent gain did I make on the latter number? • Let us assume that cost of each sheep is Rs 1000. I get 16*1000*1.125 = 18000 • In all I get : 1000*1.25*36 = 45000 • I got 27000 from 20 sheep, thus selling price was 1350 which means that I got 35% margin on the latter sheep. Ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A farmer buys 240 cows. He sells some of them at a gain of 20% and the remaining at a gain of 30%. If he gains 28% on the whole, then how many did he sell at a gain of 20%?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Soluton • As we can see the ratio between the two cows is 8:2, therefore cows sold at 20% is : • 2/(8+2) *240 • = 48 cows answer. •

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Mixture

20

30

28 8

2

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

I buy two horses, A and B. A costs Rs.50 more than B sell A at a profit of 16% and B at a profit of 7%. My total gain is Rs.100. What was the original price of B?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • • • • • •

Let the price of A = X Price of B =X – 50 1.16X + 1.07 (X-50) = 2X – 50 +100 2.23X -53.5 = 2X +50 .23X = 103.5 X = 103.5 / .23 =450 Thus the original price of B was 400 answer

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solve it • The manufacturer of a certain item can sell all he can produce at the selling price of Rs.60 each. It costs him Rs.40 in material and labour to produce each item and he has overhead expenses of Rs.3000 per week in order to operate the plant. The number of units he should produce and sell in order to make a profit of at least Rs.1000 per week is www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • • • • • •

Contribution = selling price – variable cost Contribution = 60 -40 = 20 Fixed cost = 3000 Gain expected = 1000 Thus (3000+1000) / 20 =200 units. , { Fixed cost + desired profit / contribution = no. of units to make } • Thus by selling 200 units, the shopkeeper will earn desired profit. Ans. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A shopkeeper marked the price of an article at Rs.150. He gives a customer first discount of 10% and second discount of 5%. The amount he receives is I

• 150 – 15 = 135. Now taking 5% of this : • 6.75 • =135- 6.75 = 128.25 final price received.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

After distributing 1/4 of the milk in his can, the milkman fills it with water. After selling 1/5 of the mixture as milk, he fills it again and then sells the entire portion as milk. What is the percentage gain made by the milkman (selling at cost)?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Let us assume that the milkman has 200 liters of milk @ 1. • First he sells 50 liters. Then adds water. Now he has 200 liters. Now he sells 1/5th = 40 liters. He again has 200 liters, which he again sells @ 1. • Thus his revenue is 50+40+200 = 290 • The gain % is 45% answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Kapsa purchases toffees at Rs.10 per dozen and sells them at Rs.12 for every 10 toffees. Find the gain or loss percentage. • Let us assume that there are 12*10 = 120 toffees. • Cost is 10*10 = 100. • Selling price is 12*12 = 144. • Thus gain is 44% answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solve it … • Goti Retails gives 20% festival discount on an article. Further, the company announces a discount of 5% on the reduced price if a customer makes a cash purchase. I purchased an article in cash by paying Rs 2052 What was the “Marked Price” of the article?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • • • • • •

Let us assume the cost 100 First discount = 20 Now price is 80. Cash discount = 5% = 80-4 = 76 Thus marked price is 100/76 *2052 =2700 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Rohan sold a book at a profit of 12%. Had he sold it for l8% profit, 18 paise would have been gained. The cost price of the book is • Suppose the cost is 100, then he would have gained Rs. 6 by selling at 18% instead of 12%. • Thus 100/6 *.18 = 3 answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

The S.P of an article is Rs.550. what is the C.P is Rs. if the profit made is 26% • 100/126 *550 = 436.5 ans.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

If P = Rs 400, Loss = 20% then C.P =? • 20/80 *400 = 100 • Thus cost = 400 + 100 = 500 answer

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A man sells 6 mangoes at a price which is equal to the C.P of 8 rnangoes. Profit in %? • Let us assume that the cost of 8 mangoes is 48 • Thus selling price of 8 mangoes will be : • 8/6 * 48 = 64 • Profit = 64-48 =16 • Profit in % = 16/48 *100 = 33% answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Sapna purchased a table for Rs 200 and paid Rs 40 for transportation She sold it to a neighbour for Rs 300 and earned a profit of ?

• Cost = 240 • Profit = 300 – 240 = 60 • Profit in % = 60/240 *100 = 25% answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the loss percent if a man losesRs,10 on selling an article for Rs.100? • Loss % = 10/ (100 + 10) *100 = • 9.5% approx.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A man sells 320 bananas at the cost price of 400 bananas. What is his gain percent? • Let us assume that the cost of 400 banana is : 400*32 = 12800 • Now selling price of 400 banana is : • 12800 / 320 * 400 = 16000 • Profit in % = 3200/12800 = 25% answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A cistern has a leak which can empty it in 4 hours. A pipe which admits 20 litres of water per hour into the cistern is turned on and now the cistern is emptied in 6 hours. What is the capacity of the cistern? • Capacity of pipe to fill cistern (when there is no leak) ¼ - 1/6 = 2/24 = 1/12 www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Continued… • The pipe can fill the cistern (without leak) in 12 hours. • In one hour there is inflow of 20 liters of water. Thus the cistern has capacity of 20*12 = 240 liters of water. Answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Networking problem • Goti Garage works undertakes overhauling of imported vehicles. They do activities like scrubbing, denting, painting, repairs, assembly, etc. depicted in the network given below as P—Q, Q—R, P—S etc. The direction and the number on the link provides the sequence to be followed and the time required (in hours) in overhauling a 2-wheeler. The overhauling of a vehicle starts at node P and the overhauled vehicle is delivered at node U. All the activities must be completed before a vehicle is delivered. The time required for all activities for 2wheelers, 3-wheelers and trucks are in the ratio 1 : 2: 3. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

How much time (minimum) will it take to get a truck overhauled by Goti Garage Inc.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • The longest chain in the network is as under: • (P- Q – R- T- U) This is called Critical Path • =(8+10+17+9) = 44 • Thus truck will take 44*3 = 132 hours minimum. Answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the average annual profit of the companies in the given years?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • • • • •

Profits (combined for 3 years). A = 350, B = 80, C = 310 D = 220 E = 250 Let us add these: 1210 Now divide these by 3*5 (3 for years and 5 for companies) • 1210/15 = 80.6 approx. per annum per company. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

If total production cost is Rs.1,00,000 in 1973 and cost of production per ton remains the same next year then what is the total production cost for 1974?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • The total production of all the companies together is 3,00,000 in 1973. thus the cost is 1/3 of this which is 1,00,000. • Total production in 1974 is 3,05,000 • 1/3 of this is approx. 1,01,666 approx. • Answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

In a one day India made 280 runs, what was the run made by Dravid?

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Solution • 14

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the angle of Sachin Tendulkar?

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Solution • 35/100 *360 • = 126 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the difference in angles of Shrinath and Ganguli?

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Solution • The difference is 19-10 = 9 • 9% of 360 = 32.4 Answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

If the total expenditure is Rs. 50000, what is the money spent on rent?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • 35/100 *50000 = 17500 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

For which subject we had maximum applicants and how much?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

ANSWER: As we can see, maximum applicants are in Engineering stream with 500 applicants, calculation is shown below . . .

accepted

Rejected in %

accepted in %

applicants

400

20

80

500

380

22

78

487.1795

380

16

84

452.381

400

18

82

487.8049

430

12

88

488.6364

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

SOLVE IT • A swimming pooi is fitted with three pipes. The first two pipes, working simultaneously. fill the pool in the same time as the third pipe alone. The second pipe alone fills the pool 5 hours faster than the first pipe and 4 hours slower than the third pipe. In what time will the second and third pipes together fill the pool? • (1) 3 hours (2) 3.75 hours • (3) 4 hours (4) 4.5 hours www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

SOLUTION • • • • • • • •

Let us assume the speed of 3rd pipe is X. Second pipe = (X + 4) First pipe = (X+5 +4) = X +9 1/(X+4) + 1/(X +9) = 1/X (2X +13) / (X^2+13X +36) = 1/x 2X^2 +13X = X^2 +13X +36 X^2 = 36 or X = 6 Thus we have 2nd pipe with 10 and 3rd pipe with 6 hour capacity. • 1/6 + 1/10 = or 60/16 = 3.75 hours. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solve it • There is a leak in the bottom of a cistern. When the cistern had no leak, it was filled in 2.5 hours. It now takes half an hour longer. If the cistern is full of water, then how long would it take to empty itself if water starts leakIng out at double the usual rate once the cistern is half empty? • (1) 11 hrs 25 mm (2) 10 hrs 15 m • (3) 3.75 hrs (4) 11 hrs 15 minutes www.afterschoool.tk

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Solution • 1/ (2.5) – 1/3 = .5/7.5 or = 15 hours will be taken by the leak to empty the cistern. • However, once it is half empty, its speed will double. It will be half empty in 7.5 hours. Thus subsequently, it will take half of the usual time: • 3 hours 45 minutes. • Thus total time = 11 hours and 15 minutes. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

One woman was passing through deserts of Bikaner on camel. One person asked her about her relationship with the person riding the camel, she replied : that the mother in law of this person and mine are mother – daughter. What is the relation between the person and the lady? . www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • The man is the father in law of the lady. (the relation is simple, the lady’s mother in law’s mother is obviously the mother in law of father of the husband of the lady. ).

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• Three partners invested capital in the ratio 2 :7 :9. The time period for which each of them invested was in a ratio of the reciprocals of the amount invested. Find the share of the partner who bought in the highest capital, if profit is Rs. 1080. • (1) Rs.540 (2) Rs.360 • (3) Rs.420 (4) Rs.720 www.afterschoool.tk

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Solution • 1080/3 = 360 answer.

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There is a train which is moving from East to the West, where will its smoke flow? • Upside

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

There is an electric train which is moving from East to the West, where will its smoke flow? • No – smoke

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How many marks are minimum marks?

• A. Student A secured 38% marks in the examinatict a failed by 8 marks. Student B secured 42% marks a same-examination and got 12 more than the minb pass marks. • B. Student A secured 35% of the total marks in examination and failed by 23 marks. If he had secured 25 more marks, his percentage of marks would ban’ been 40%. • C A student will be declared passed if he secures 39.6% of the total marks. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Answer can be obtained from either A or B statement. For example : from A – • 100/4 *20 = 500 is total marks. When the student gets 42% marks, he gets: 210 and has 12 more marks, thus the minimum pass marks are : 198. Ans.

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arrange eight of the nine numbers 2,3,4,5, 7,10, 11,12,13 in the vacant squares of 3X4 array shown below so that the arithmetic average of the numbers in each row and column is the same integer. What is their average?

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Solution • Let us add these numbers: • • • •

Sum( 1,2,3,4,5, 7,9,10, 11,12,13,14,15, - X) X = left out number =106-X Let us assume average = Y

• The average is same, so total of columns should be 4Y. • 3*(4Y) = 106-X • 12Y = 106 – X, by hit and trial, we know that X should be 10. Thus Y = 8. • Thus average is 8 and left out number is 10. • Answer. www.afterschoool.tk

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For how many integers N, N/(20—n) is the square of an integer? • • • •

(a) 0 (b) 1 (c) 2 (d) 3 (e) 4 Solution : square cannot be negative, so 20-N must be positive. Therefore N can be upto 19 only. By trial, we can see that when N = 16, this is square, there is no www.afterschoool.tk AFTERSCHO☺OL's MATERIAL other option, Thus answer isFOR B.PGPSE PARTICIPANTS

Puzzle • A truck tra veiled from town A to town B over several days. During the first day, it covered 1/p of the total distance, where p is a natural number. During the second day, it travelled 1/q of the remaining distance, where q is a natural number. Duthig the third day, it travelled i/p of the distance remaining after the second day, and during the fourth day, l/q of the distance remaining after third day. By the end of the fourth day the truck had travelled 3/4 of the distance between A and B. • The value of p+q is • (a) 4 0) 5 • (c) 6 (d) 7 • (e) 8 www.afterschoool.tk

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Solution • Try from options, it cannot be 5 or 6, it has to be higher value 7 or 8. Let us try for 7. • Let us assume that the number is 144 (we have assumed it because 4*3*4*3 = 144) • First day: 36 is used, left out is 108. 2nd day: 36 is used and left out is 72. 3rd day: 18 is used and left out is 54. 4th day 18 is used and left out is 36. • We know that now 1/4 th is left out, so our condition is fulfilled. Thus this is the answer. • www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

In a certain factoiy, each day the expected number of accidents is related to the number of overtime hour by a linear equation. Suppose that on one day there were 1000 overtime hours logged and 8 accidents reported, and on another day there were 400 overtime hours logged and 5 accidents. What are the expected numbers of accidents when no overtime hours are logged?

• (a) 2 • (c) 4

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(b) 3 (d) 5

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Let us frame 2 equations and use them to solve this question: • 8 = 1000X +Y • 5 = 400 X +Y • Solving these we get : 3 = 600X • X = 1/200; putting this value, we get Y. • Y = 3. • Thus when there is no overtime, the number of accident is 3. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

In which year did the firm pay maximum tax?

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Solution • Since all the figures are in %, we cannot calculate the value of taxes paid as absolute value. We are not aware of change in sales also. So answer : cannot be determined.

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Solve it : • Seven integers A, B, C,D, E, Fand G arc to be arranged in an increasiug order such that • i. First four numbers are in arithmetic progression. • ii. Last four numbers are in geometric progression. • iii. There exists one number between E and G. • iv. There exist no numbers between A and B. • v. D is the smallest number and E is the greatest. • Vi. A / D = G /C = F / A >1 • vii. E= 960 • What is E / A? www.afterschoool.tk

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SOLUTION • F is more than A and A is more than D and G is more than C. • D is smallest :D - - - - - - E (G will come one less than E, A and B are close. C has to be near D. • DC BAGFE • The last four are in GP. • Thus E = A *r^3 (because it is GP) and A = D +3(common difference) www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Continued… • • • • • • • • • •

E = 960 Let us find factors of 960 2*2*2*2*2*2*3*5 Thus A must be 15 and ratio must be 4 The numbers will be : 15,60,240,960. Or A may be 120 and ratio may be 2, the numbers will be 120,240,480 and 960 Thus F/A = 240/15 = 16 or 480/120 = 2. The 2nd option is better. Thus A/D = 2 and D = 60 We can write that A = D + (3*common difference) =120=60 +(3*common difference).

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Continued… • • • • •

120=60 +(3*common difference). Common difference is 20 Thus the numbers are : 60,80,100,120,240,480,960 Thus we can find answer to the question: E/A • =960/120 = 8 answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Goti and Nitin could do a piece of work in 12 days. Nitin and Kap together do lt In 15 days. If Goti is twice as good a workman as Kap, find in how many days Goti alone will do it?

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Solution • • • • • • •

G = 2K (now add the two equations) 2K+N+N+K = 1/12+1/15 = 27/180, K+N = 1/15 or 2 (K+N) = 2/15 3K +2N = 3/20 K = 3/20 – 2/15 = 1/60 Thus Kap can do it in 60 days. Goti being twice fast, can do it in 30 days alone. Answer.

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Goti car paint a fence 100 metres long in 6 days, then how much time will both Goti and his friend Kap take, if Kap is thrice as efficient as Goti? • Goti’s one day work = 1/6, Kap=3*1/6 • 1/6 + 3/6 = 4/6 • Thus they will take 6/4 = 1.5 days to www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS complete the work.

Two pipes A and B can fill a cistern in 10 and 15 minutes respectively. Both pipes are opened together but at the end of 3 minutes, ‘B’ is turned off. How much time will the cistern take to fill? • 3/10 +3/15 = 75/150 thus the remaining pipe A will take 5 minutes to fill up the tank. Total time: 2+5 = 7 minutes. Ans. www.afterschoool.tk

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Explanation • 75/150 = is half of the total pip3 thus the pipe is helf illed. Thus A can fill the remaining portion in 5 minutes (it takes 10 minutes to fill completely).

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A is twice as good a workman as B; and together they finish a work in 14 days. In how many days can it be done by each separately? • Let us assume that A takes X and B takes 2X days. 1/2x + 1/x = 1/14 • Let us assume 1/x = Y • Y/2 + Y = 1/14 • 3/2Y = 1/14 or Y = 2/42 or 1/21 • Thus A can do it in 21 days and B in 42 days. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

If 20 men complete one-third of a piece of work in 20 days, how many more men should be employed to finish the rest of the work in 25 days? • • • •

Total work left = 2*20 = 40 days. Total mandays required = 40*20 = 800 Thus no. of persons required = 800/25=32 Additional persons required = 32-20=12 persons. Answer.

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Goti can copy 75 pages in 25 hours Goti and Kap together can copy 135 pages in 27 hours In what time can Kap copy 42 pages? • Goti copies 3 pages in one hour. Thus he copies 27*3 = 81 pages. Kap copies (13581) = 54 pages in 27 hours, or 2 pages in one hour. Thus 42/2 = 21 hours will be taken by Kap Sa. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

goti & Kap can do a piece of work in 4.8 days, Kap and Jitu together can do it in 8 days and the three together in 4 days. How long would Goti & Jitu together take to do it’

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Solution • (calculate for 1 day and add them to get the ans.) • G+K +K +J= 1 / (4.8) + 1/8 • GKKJ = 12.8 / 38.4 • GKJ = ¼ • K = 12.8 / 38.4 - ¼ • = (12.8 – 9.6) / 38.4 • = 3.2 / 38.4 = 1/12 • Thus G+J = ¼ - 1/12 = 2/12 = 1/6 • G + J will do it in 6 days. Answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A person works twice as fast as a woman. A woman works twice as fast as a child. If 16 persons can complete a job in 12 days, then how many days would be required for 32 women and 64 children together to complete the same job? • 32 women = 16 men • 64 children = 16 men. • Thus they will together do it in 6 days. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS Ans.

3 pipes A, B and C can fill a cistern in 15, 20 and 30 min. respectively. They were all turned on at the same time. After 5 minutes the first two pipes were turned off. In what time will the cistern be filled?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • 5/15 + 5/20 5/30 • = (20+15+10) / 60 = 45/60 or ¾ • Thus remaining ¼ of the cistern can be filled by C in 7.5 minutes only. • Thus total time taken is 5 + 7.5 =12.5 minutes

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A certain number of men can finish a piece of work in 100 days. If, however, there are 10 men less, it would take 10 days more for the work to finish. How many men were there? • • • •

Let the number of men = X Total work = 100X (X-10) 110 = 100X or 110X -1100 = 100X 10X = 1100 or X = 110.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A, B and C can do a piece of work in 20, 20 and 40 days respectively. They began the work together but C left 2 days before the completion of work. In how many days would the work have been completed?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • • • • •

For 2 days only A and B worked 2/20 + 2/20 = 4/20 or 1/5 Together (all three) : 1/20+1/20+1/40 = (2+2+1) / 40 = 1/8 Thus they take 8 days to complete the work, but they completed only 4/5 work together, so 8*4/5 = 6.4 days were taken by them. Thus total days : 8.4 days. Answer.

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ERROR SPOTTING Industrial accidents/(1)usually result into /(2) ignorance/(3)or carelessness/(4) No Error (5) • The correct sentence should be : • Industrial accidents are caused by ignorance or carelessness. • So answer is (2) www.afterschoool.tk

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Some people are like (1)to do a lot of social work/(2)even though they are poor(3)and lack resources • Correct sentence should be : • Some people want / are likely to do a lot of social work, even though they are poor and lack resources. www.afterschoool.tk MATERIAL FOR PGPSE PARTICIPANTS • So answer is (1)AFTERSCHO☺OL's .

ERROR SPOTTING Some men (1)have conveniently believe (2)that women are inferior to(3) men in respect of abilities.(4) No Error (5) • (2) = it should be : have conveniently believed.

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ERROR SPOTTING His qualities include(1)the ability to take/(2)right and/(3)quickly decisions.(4)/ No Error(5) • ANSWER : (4) • It should be quick decisions.

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ERROR SPOTTING If you want to (1)ensure prompt service (2)please be contacted to us (3) at your earlier convenience. (4) No Error (5) • Answer : (3) please contact us OR please be in contact with us

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They founded (1)this institution for/(2)the welfare of the poor (3) and the disable people.(4) No Error (5)

• Answer (4) it should be : • For the disable (there is no need to put people with disable). www.afterschoool.tk

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He asked me/U) what had my total investrnents(2)during the (3) last five years.(4) No Error. (5) • Answer : (2) it should be : • What had my total investments been

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He takes the(1) prescribed medicine regularly(2) and that is how(3) he has succeed to control his ailment.(4) No Error (5) • Answer : (3) • It should be : this is how

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We should take(1) regular exercises to keep ourself (2) fit and active.(3) No Error (4) • (2) it should be : regular exercises to keep • (there is no need of ourself).

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Each time (1) you reached this spot (2) go back and(3) start your next (4) round again.(4) No Error (5) • (2) it should be – you reach this spot.

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SENTENCE IMPROVEMENT • The honourable court had taken a leniency view because the accused had no previous criminal record. • (1) had viewed leniency (2) had taken a leniency viewing • (3) had taken a lenient view(4) Noae of these • (5) No correction required • Solution: • (3) www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Sentence improvement • Maintaining global peace is our self-made commitment to the word. • (1) self-making commitment • (2) self-made committee • (3) made of self-connnitment • (4) None of these • (5) No correction required • Solution (5) www.afterschoool.tk

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The dinner party hosted by the President at the club was shifted to an undisclosed location. • (1) a locality undisciosing • (2) a undisc location • (3) an undisc location • (4) None of these • (5) No correction required • Solution •www.afterschoool.tk (5) AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Sentence improvement • The government should launch such projects which should reversible the destructive cycle of flood and drought. • (1) should have reversible (2) should be reverse (3) should have been reverse • (4) None of these • (5) No correction required • Solution : • (4) correct answer: should reverse www.afterschoool.tk

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A comnilttee comprising eminent experts from various fields were setting up. (1) was setup (2) was setting up (3) were being set up (4) None of these (5) No correction required • Solution : (1) www.afterschoool.tk

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Our foreign exchange reserves have been increased substantial. (1) have been increased substantially (2) have increased substantially (3) have substantially increasing (4) None of these (5) No correction required • Solution : (2) www.afterschoool.tk

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The key to a competitive economy is its investment regime. • • • • • • •

(1) competition economy is (2) competing economist lays (3) economy competition was (4) None of these (5) No correction required Solution (5)

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Driving a car in jammed traffic require extraordinary patience especially when other drivers are not disciplined. (1) required extraordinary patient (2) requires extraordinary patience (3) requiring extraordinary patience (4) None of these (5) No correction required • Solution (2) www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Chinese army possesses highly sophisticated simulotors on which their soldiers are training. • • • • • •

(1) which their soldiers training on (2) on which their soldiers have trains (3) which their soldiers do train (4) None of these (5) No correction required Solution : last part : soldiers are getting training. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS (so answer is (4))

Every novel activity will be likely to face resistance from vested interests. • • • • • •

(1) is likely to face (2) would be like facing (3) No correction required (4) will be likely facing (5) None of these Solution : (1)

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We observed that traders were not primarily dedicated with art of selling. • • • • •

(1) dedicated to the art of(2) None (3) dedicated in the art by (4) dedicated by the art of (5) No correction required Solution (1) preposition error .

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

If expenses per participant during the meeting is Rs.200 in 1995, which keeps on increasing at the rate of 10% per year, then what are the total expenses (in Rs.thousand) in 1996. The graph below shows the number of participants coming from different regions?

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Solution • 200*1.1*360 = 79200 answer.

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The following graph shows profits of 5 companies. What was the average profit in 1979?

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Solution : • • • • • • •

A =130 B = 40 C = 110 D = 60 E = 90 Let us add them and divide by 5: =430/5 = 86 answer.

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Solve it • A cube with edges equal to 8cm is painted on all the six faces and is subsequently cut into 64 identical cubes. The number ct smaller cubes painted on atleast two faces is • (1) 24 (2) 16 • (3) 36 • (4) 32 www.afterschoool.tk

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Solution • There are four on the top right side. There are 4 on the opposite side also (4*4*4 = 64). • Thus we have 4+4+2+2 cubes in front, same 12 in the back side also. We have 8 in sides also. Thus we have 32 cubes. • Ans. www.afterschoool.tk

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Solve it • The perimeter of a regular hexagon is 36cm. The area of the hexagon is • (1) 54*sqrt(3) sq cm (2) 108*3 sq cm • (3) 27*3 sq cm (4) 18*3 sq cm • Solution: • One side of hexagon = 6 • One triagle = ((sqrt(3)/4 * side )^2 =1.7/4* 36 • Hexagon = 6* equilateral triangle = 6*sqrt(3)/4*36 • =54* sqrt(3) ans www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solve it … • How many patient does the doctor examine in a day, if he treats 5 patients in 3 hours with breaks of 10 minutes between two consecutive patients and works for 10 hours per day? • (1) 16 (2) 15 • (3) 12 (4) 20

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Solution • • • • • • •

3 hours = 180 minutes Break = 4*10 = 40 Time per patient = 140 / 5 = 28 minutes Total time : 10 hours *60 = 600 minutes 600 – 28 = 572 Now dividing 572 / (28+10) = 15 Thus the doctor checks 15+1 = 16 patients.

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If the interior angle of a regular polygon is twice its exterior angle then the polygon is a (1) rhombus (2) pentagon (3) hexagon (4) heptagon Interior angle = 2X and exterior angle = X 3X = 180 or X = 60 Thus one exterior angle is 60 Thus 360/60 = 6 Thus the shape is hexagon. Answer. www.afterschoool.tk

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DATA SUFFICIENCY QUESTION. 40 pens were distributed equally amon all the participants, then how many participants were there? (A) The number of participants was a prime number greater than 10. (B) The leftover pen was kept by the Chairman. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • If we combine both the statements, we can get the answer. One pen was left (given to the chairman), so 39 pen were distributed. • 39 = 3*13 • Thus the number of participants must be either 3 or 13. since it had to be above 10, therefore the answer is 13. (so answer can be drawn with the help of both the students together). Ans. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

WHAT IS THE VALUE OF X

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

WHAT IS THE VALUE OF X

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Data sufficiency question. • • • • • • •

Is the series a GP? (A)If the third term is twice the second. (B)The fourth term is eight times the first. Solution Let us start from 1 1,2,4,8 = yes it is GP Thus the answer can be drawn with the help of both the statements. Ans.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

The number of common terms in the two-seç 17, 21, 25,.. ., 417 and 16, 21, 26,. . ., 466 • Let us start from 21. In the first term the gap is of 4 and in second series the gap is of 5. their LCM is 20 so we have to find the gaps of 20 each. • Last term is 417. let us deduct 21 from 417, we get 396. now let us divide it by 20. We get : 19. Thus we have 19+1 = 20 common terms. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution continued. .. . • The final series is : • 21,41,61,81,101,121,141,161,181,201,22 1,241,261,281,301,321,341,361,381,401,

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the total production of machine no. 3?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Production accepted : 100 – 27 = 73%. • Thus total production • 100/73 * 438 = 600 units answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

• The integers 1, 2,..., 40 are written on a blackboard. The following operation is then repeated 39 times: In each repetition, any two numbers, say a and b, currently on the blackboard are erased and a new number a + b —1 is written. What will be the number left on the board at the end? • Options: (1) 820 (2) 821 (3) 781 (4) 819 (5) 780 www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution …. • In the first round, we add up 1 and 2 and get 2. now we take up 2 and 3, we get 4, now we take up 4 and 4 and get 7. now we take up 7 and 5 and get 11. Now we take up 11 and 6 and get 16. We can find that we have an increasing series : • 2,4,7,11,16 …. … • Let us add 1 to 39. =39*40/2 = 780 • Let us add 780 + 1= 781 answer. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the total sale (in no. of units) in the year 1991?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

• = 82016 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the % increase in the sale of VCR in 1993 against 1992? • • • • •

Sale in 1993 =6151 Sale in 1992 = 3006 Difference = 3145 Increase in % = 3145/3006 *100 = 105% answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

This graph shows price of 4 shares, what is the average price of these 4 shares?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Let us add them: • (150+40+120+90)/4 = 100 answer

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

what is the production of food grains in 1991, expressed as a percentage of its production in 1989?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • 15/20 *100 = 75 % answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Which is the most logical idea? • If an ant were as big as a horse, could it move mountains? • No. A giant ant . . . . . (select from a,b,c,d) • (a) Would be a structural failure. • (b) Would never be able to move mountains. • (c) Would be a mere curiosity. • (d) Would never be able to hunt for food. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • A giant Ant would not be able to move mountains because it is just a curoisity (we are not sure about what could it do). Other options are not logical – as logically we cannot say that it is structural failure or it cannot hunt for food or it cannot move mountains.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Puzzle test… • Nine cricket fans are watching a match in a stadium. Seated in one row, they are J, K, L, M, N, 0, P, Q and R. L is at the right of M and at third place at the right of N. K is at one end of the row. Q is immediately next to 0 and P. 0 is at the third place at the left of K. J is right next to left of 0. • Who is sitting in the centre of the row? • (a)L (b)O • (c)J (d)Q www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution … • NRMLJOPQK • J IS IN THE CENTRE

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A and B start walking in opposite directions. A covers 3 km and B covers 4 km. Then A turns right and walks 4 km while B turns left and walks 3 km. How far is each from the starting point? • A is 3 KM in one direction and 4 KM in right. Applying pythogorus, we find that A is 5 KM from the starting point. Similarly B is also 5 KM from the starting point. Ans. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Ram walks 10 m south from his house, turns left and walks 25 m, again turns left and walks 40 m, then turns right and. walks 5 m to reach to school. In which direction the school is from his house? • Draw a map and get the answer = northeast. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

In a class of 35 students Kiran is placed 7th from the bottom whereas Sohan is placed 9th from the top. Mohan is placed exactly in between the two. What is Kiran’s position from Mohan? • 10th • From 9th to the top and 7th to the bottom, we have 21 candidates (35-(6+8) ). Mohan is just in the centre. So from Mohan, Kiran is at 10th place. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A watch reads 4 If the minute hand points towards the East, in which direction does the hour hand point? • The hour hand is towards South West.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Puzzle • Goti and I started walking towards each other from two places lOO m apart. After walking 30m, Goti turns left and goes lO m, then he turns right and goes 20m then turns right again and comes back to the road and starts walking. If we walk with the same speed, what is the distance between us at this point of time www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • (Goti walks 70 meters in all), so I walk 70 meters towards Goti’s starting point and now I am 30 meters from that. Goti takes only 30+20 meters on the road. Thus Goti is 50 meters from my starting point. Thus there is a gap of 20 meters between me and Goti. Answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Sum of 1st to 30th terms of a series in arithmetic progèssion is 150. if the first term is A, what is 30th term of the series? • • • •

Sum = 30/2 (2a + (29)D) = 150 2a + 29d =150*2/30 = or 29 D = 10 – 2A 30th term = A + 29D 29 D = 10 – 2A, putting the value, we get the answer = 10 – A answer www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Question on number system • Convert 252 into binary system • 252 / 2 = 126 / 2 = 63/2 = 31/2 = 15/2 = 7/2 = 3/2 =1 (starting from last remainder to the first) • 11111100 answer. • Convert it again to decimal system: • 1*2^7+1*2^6+1*2^5+1*2^4+1*2^3+1*2^2+ 0*2^1+0*2^0 = 128+64+32+16+8+4 = 252 www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Multiply 12 to 13 ( note - both are octal numbers, your outcomes must also be in octal numbers)? • Let us first convert them into decimal numbers: 12= 1*8^1 + 2*8^0 =10 • 13 = 1*8^1 + 3*8^0 =11 • Now multiply 10 to 11 = 110 • Now convert it into octal number: • 110/8 = 13 / 8 • =156 •www.afterschoool.tk Test = now convert 156MATERIAL to decimal AFTERSCHO☺OL's FOR PGPSE PARTICIPANTS number

Convert 156 (octal) to decimal number ….. • 1*8^2 + 5*8^1 + 6*8^0 • =64+40+6 • =110 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Multiply 5 (base 16) to 12 (base 7) and get the outcome in binary? • • • •

(5*16^0 ) * (1*7^1 +2*7^0) 5 *9 = 45 45/2 = 22/2 = 11/2 = 5/2 =2/2 1 =101101 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

78.8% of a common medicine for stomach-upsets is absolute alcohol; 3.3% of it is mentha oil; 0.07% spear mint oil; and 0.177% chloroform. How much of each of these compounds is there in a pack of 30 ml? solution alchol = 23.6 ml, 1 ml of menthol oil and so. On. www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the sum of cubes of the first 5 natural numbers? • • • •

Formula = [N (N+1)/2 ]^2 = [5*6 / 2 ]^2 =225 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is the sum of squares of the first 13 natural numbers? • • • •

Formula =[n(n+1)(2n+1) ] /6 =(13*14*27)/6 =819 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

In a Class of 80 pupils, the number of boys is three-fifths the number of girls. Determine the number of girls in the class. • • • • •

Let the number of girls be X X + 3/5X = 80 8/5 X = 80 X = 80 *5/8 X = 50 (the number of girls is 50, boys are 30) answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

The difference between two numbers is 30. On dividing the greater by the smller the quotient is 3. Find the numbers. • • • •

Let the smaller number be X. 3X – X = 30 2X =30; X = 15, Thus 2 numbers are 15 and 45 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Gunpowder contains 75% nitre and 10% sulphur. The rest of it is charcoal. What is the amount of charcoal in 9 kg of gunpowder. • • • •

Charcoal is (100 – 75 – 10) = 15% 9 KG = 9000 Grams 9000*15/100 =1350 grams answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Question on profit • At what percentage alove the Cost price must an article be marked so as to gain 33% after allowing the customer a discount of 5%? • (a) 48% (b) 43% • (c) 40% (d) 38% • (e) None of the above www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution … • Let the cost be 100 • Final price being realised 133 • It is after discount, so price before discount (marked price) is : • 133*100/95 =140 , so 40 is the answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

A vertical pole PO is standing at the centre 0 of a square ABCD. If AC subtends an angle 90° at point P of the pole then the angle subtended by a side of the square at Pis (a) 35° (b) 45° (c) 30° (d) 60° (e) None of the above www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • When diagonal (in a square) makes angle of 90 degree in a pyrimidical shape, then sides make angles of 60 degree. (rule). • So answer is 60 degrees.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Find the per cent of pure gold in 22 carat gold, if 24 carat gold is cent per cent pure gold. • 22/24 *100 • =91.67 % answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

In the diagram the two circles pass through each other’s centre. If the radius of each circle is 2, what is the perimeter of the region marked B?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Permieter of one circle is 2/3 now because, it is being cut by other circle. • Thus 2/3 + 2/3 of perimeters added : • 2 * 2/3 * (formula of perimeter = 2pi *r) • =(8 * pi * r) /3 answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is angle C?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • Angle O is double the angle A. Thus it is 100 degree. Thus C is (180 -100)/2 = 40 degrees answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

What is angle a?

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Solution • • • • • • • •

Angles from D and C are equal . 180 – 60 – 37 – x =83 – x Let us sum up for two angles: (180+180 ) = 360 83-x + 83 – x + 180+2X = 360 2Y +2X = 180 let us assume Y = 53 2X = 72 or X = 36 answer (solve by options, so angle A = 53 ) answer.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

ABOUT AFTERSCHO☺OL Afterschoool conducts three year integrated PGPSE (after class 12th along with IAS / CA / CS) and 18 month PGPSE (Post Graduate Programme in Social Entrepreneurship) along with preparation for CS / CFP / CFA /CMA / FRM. This course is also available online also. It also conducts workshops on social entrepreneurship in schools and colleges all over India – start social entrepreneurship club in your institution today with the help from afterschoool and help us in developing society.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Why such a programme? • To promote people to take up entrepreneurship and help develop the society • To enable people to take up franchising and other such options to start a business / social development project • To enable people to take up social development as their mission • To enable people to promote spirituality and positive thinking in the world www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Who are our supporters? • Afterschoolians, our past beneficiaries, entrepreneurs and social entrepreneurs are supporting us. • You can also support us – not necessarily by money – but by being promotor of our concept and our ideas.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

About AFTERSCHO☺OL PGPSE – the best programme for developing great entrepreneurs • • • • •

Most flexible, adaptive but rigorous programme Available in distance learning mode Case study focused- latest cases Industry oriented practical curriculum Designed to make you entrepreneurs – not just an employee • Option to take up part time job – so earn while you learn • The only absolutely free course on internet www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Workshops from AFTERSCHO☺OL • • • • • • • • •

IIF, Delhi CIPS, Jaipur ICSI Hyderabad Branch Gyan Vihar, Jaipur Apex Institute of Management, Jaipur Aravali Institute of Management, Jodhpur Xavier Institute of Management, Bhubaneshwar Pacific Institute, Udaipur Engineering College, Hyderabad

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Flexible Specialisations: • • • • • • • • • •

Spiritualising business and society Rural development and transformation HRD and Education, Social Development NGO and voluntary work Investment analysis,microfinance and inclusion Retail sector, BPO, KPO Accounting & Information system (with CA / CS /CMA) Hospital management and Health care Hospitality sector and culture and heritage Other sectors of high growth, high technology and social relevance

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Salient features: • The only programme of its kind (in the whole world) • No publicity and low profile course • For those who want to achieve success in life – not just a degree • Flexible – you may stay for a month and continue the rest of the education by distance mode. / you may attend weekend classes • Scholarships for those from poor economic background • Latest and constantly changing curriculum – keeping pace with the time • Placement for those who are interested • Admissions open throughout the year • Latest and most advanced technologies, books and study material www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Components • • • • • • • • • • • • • •

Pedagogy curriculum and approach based on IIM Ahmedabad and ISB Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad) Meditation, spiritualisation, and self development EsGotitial softwares for business Business plan, Research projects Participation in conferences / seminars Workshops on leadership, team building etc. Written submissions of research projects/articles / papers Interview of entrepreneurs, writing biographies of entrepreneurs Editing of journals / newsletters Consultancy / research projects Assignments, communication skill workshops Participation in conferences and seminars Group discussions, mock interviews, self development diaryng Mind Power Training & writing workshop (by Dr. T.K.Jain)

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Pedagogy • • • • • • • • •

Case analysis, Articles from Harvard Business Review Quiz, seminars, workshops, games, Visits to entrepreneurs and industrial visits PreGotitations, Latest audio-visuals Group discussions and group projects Periodic self assessment Mentoring and counselling Study exchange programme (with institutions out of India) • Rural development / Social welfare projects www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Branches • AFTERSCHO☺OL will shortly open its branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Case Studies • We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

Basic values at AFTERSCHO☺OL • • • • • •

Share to learn more Interact to develop yourself Fear is your worst enemy Make mistakes to learn Study & discuss in a group Criticism is the healthy route to mutual support and help • Ask fundamental questions : why, when, how & where? • Embrace change – and compete with yourself only www.afterschoool.tk

AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

www.afterschoool.tk social entrepreneurship for better society

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AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS