Lab Molar Mass

  • October 2019
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Pre- Lab Questions 1.

.001 mol. H2 (g) P1=(RT/V) P=592.9 torr

2. P1V1/T1=P2V2/T2 (5929 torr)(.031 L)/ 295 K=760 torr(x)/273 K X= .023 L 3. Mg + 2HCl

Mg Cl2 + H2

.28 g Mg /1 x 1 mol Mg /24.3 g Mg x 1 mol H2 / 1 mol Mg = .00110 mol H2 4. .02741 L / .00115 mol = 23.835 L/mol

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