Koncentracija Napona

  • June 2020
  • PDF

This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA


Overview

Download & View Koncentracija Napona as PDF for free.

More details

  • Words: 1,337
  • Pages: 6
2.1 a) ZATEZANJE

 111   k111  nz F 25 kN  nz    6.9 2 b h 3.6 1 cm  p B  2 48   k 111  f  ;   f  ;   2.3  b b  32 36  kN  111  2.3 6.9  15.87 2 cm  121   k121  nz F 25 kN  nz    4.5 2 b h 5.6 1 cm  p B  4 68   k 121  f  ;   f  ;  2  b b  56 56  kN  121  2 4.5  9 2 cm __________________________________________________  211   k 211  nz F 4F 4 25 100 kN  nz  2  2    2.46 2 d  d  12.96  40.7 cm 4  p d  2 36   k 211  f  ;   f  ;   2.3  t D  6 48  D  d 48  36 t   6mm 2 2 kN  211  2.3 2.46  5.658 2 cm  221   k 221  nz 4F 4 25 100 kN  nz  2    1.016 2 d  31.36  98.47 cm  p d  4 56   k 221  f  ;   f  ;   2  t D  6 68  D  d 68  56 t   6mm 2 2 kN  221  2 1.016  2.032 2 cm _____________________________________________________

b) SAVIJANJE

 112   k112  nz M M 6M 6 14 kN  nz      6.48 2 2 2 W h b h b 1 12.96 cm 6  p b  2 48   k 112  f  ;   f  ;   2.2  b B  36 36  kN  112  2.2 6.48  14.256 2 cm M M 6M 6 14 kN  nz      2.67 2 2 2 W h b h b 1 31.36 cm 6  p b  4 68   k 122  f  ;   f  ;   1.9  b B  56 56  kN  122  1.9 2.67  5.073 2 cm  212   k 212  nz M M 32 M 32 14 kN  nz      3.058 2 3 3 W  d  d  46.656 cm 32  p d  2 36   k 212  f  ;   f  ;   2.2  t D  6 68  Dd t  6mm 2 kN  212  2.2 3.058  6.728 2 cm  222   k 222  nz M M 32 M 32 14 kN  nz      0.81 2 3 3 W  d  d  175.6 cm 32 p d   4 56   k 222  f  ;   f  ;   1.9  t D  6 68  kN  222  1.9 0.81  1.54 2 cm

c) UVIJANJE

 213   k 213  nt T 16 T 16 18 kN  nt     1.966 2 3 3  d  d  46.656 cm 16  p d  2 36   k 213  f  ;   f  ;   1.6  t D  6 48  kN  213  1.6 1.966  3.1456 2 cm  223   k 223  nt T 16 T 16 18 kN  nt     0.52 2 3 3  d  d  175.6 cm 16  p d  4 56   k 223  f  ;   f  ;   1.4  t D  6 68  kN  223  1.4 0.52  0.728 2 cm ____________________________________________________________ TABELARNI PRIKAZ REZULTATA PRORACUNA Broj Slike

Dimenzija

1

1 2 1 2

2

Zatezanje(1) 15.87 9 5.658 2.032

Vrste opterećenja Savijanje(2) 14.256 5.073 6.728 1.54

Uvijanje(3) 3.1456 0.728

2.2 a) ZARTEZANJE Re  390MPa  D ( 1) z  0.425 Rm  0.425 610  259.25MPa

 D (0) z  0.54 Rm  0.54 510  329.4 MPa   D (0) z   D ( 1) z   2  1  D ( 1) z   D (0) z  D (0) z  2   arctg 0.4259  23.07 0 _____________________________



259.25    2 1    0.4259   329.4 

tg z 



b) Savijanje Res  1.5Re  1.5 390  585MPa  D ( 1) s  0.47 Rm  0.47 610  286.7 MPa

 D (0) s  0.72 Rm  0.72 610  439.2 MPa   D (0) s   D ( 1) s   2  1  D ( 1) s   D (0) s  D (0) s  2   arctg 0.69  34.770 _______________________________ tg s 



286.7    2 1    0.694   439.2  

c) UVIJANJE Reu  0.7 Re  0.7 390  273MPa  D ( 1)u  0.325 Rm  0.325 610  198.25MPa

 D (0)u  0.38 Rm  0.38 610  231.8MPa   D (0)u   D ( 1)u   2  1  D ( 1) u   D (0)u  D (0)u  2   arctg 0.289  16.140 tg u 

 

198.25    2 1    0.289   231.8 

2.3 Dinamička idržljivost mašinskog dijela   D ( 1) M  D ( 1)e KD  D ( 1) M -dinamička izdržljivost mašinskog dijela

 D ( 1) e - dinamička izdržljivost epruvete KD - factor dinamička izdržljivost    1 0.84 0.95 1  1 2 3   0.433  K D  2.31 KD K 1.864  k  ( k  1) k  1 1  f (d  36)  0.85  2  0.95 3  1 k  0.72 p D 2 48  k  f ( ; )  f ( ; )  2.2 d d 36 36  k  (2.2  1) 0.72  1  1.864  D ( 1) e  0.47 Rm  286.7 MPa 286.7  124.11MPa 2.31 2    tg M  1  (1  D ( 1) e )  1 2 3  D (0) s k

 D ( 1) M 

 D (0) s  0.72 Rm  439.2 MPa 573.4 tg M  1  (1  ) 0.433  0.867 439.2 tg M  arctg 0.867  40.950 a)  sr  const.  130 MPa  DM   D ( 1) M   sr tg M  124.11  130 0.867  236.82 MPa b)  d  const.  125MPa   0.5 d tg M 124.11  62.5 0.867 178.29  DM  D ( 1) M    314.72 MPa 1  0.5tg M 1  0.5 0.867 0.5665

  63.40

c)  sr  0.3 g  ctg   sr  0.3 g

  73.30  DM 

 D ( 1) M 124.11   167.74MPa (1  ctg  tg M ) (1  0.3 0.867)

Related Documents