Bahasa Rakitan Pr 01

BAHASA RAKITAN (Jawaban PR 15 November 2009 )

Nama : Pemilik & Pengelola Joshaxis NIM : 200822*** Tgl. : 29 November 2009

Teknik Informatika XI

JAWABAN : 1). (a) Pengurangan Bilangan Biner 1 0 1 0 0 0 0(2) 1 1 1 1 1 1(2) 0 0 1 0 0 0 1(2)

1). (b) Pengurangan Bilangan Biner

Rincian :

1 1 0 1 1 0 0(2) 1 0 1 1 1 1(2) 0 1 1 1 1 0 1(2) Rincian :

= 1 x 21 = 2 2+0=2 2 – 1 = 1 , borrow 1

= 1 x 21 = 2 2+0=2 2 – 1 = 1 , borrow 1

Table Pengurangan Bil. Biner Bil. I Bil. II Hasil 1 0 1 0 0 0 1 1 0 0 1 1

Table Pengurangan Bil Biner Bil. I Bil. II Hasil 1 0 1 0 0 0 1 1 0 0 1 1

Atau dengan rincian berikut :

Atau dengan rincian berikut :

0 + 1borrow = 0 + 2 = 2 2–1=1

0 + 1borrow = 0 + 2 = 2 2–1=1

0 – 1borrow = 0 + 1borrow = 0 + 2 = 2 2 – 1borrow = 1 1–1=0

0 – 1borrow = 0 + 1borrow = 0 + 2 = 2 2 – 1borrow = 1 1–1=0

0 – 1borrow = 0 + 1borrow = 0 + 2 = 2 2 – 1borrow = 1 1–1=0

1 – 1borrow = 1 + 1borrow = 1 + 2 = 3 3 – 1borrow = 2 2–1=1

0 – 1borrow = 0 + 1borrow = 0 + 2 = 2 2 – 1borrow = 1 1–1=0

1 – 1borrow = 1 + 1borrow = 1 + 2 = 3 3 – 1borrow = 2 2–1=1

1 – 1borrow = 1 + 1borrow = 1 + 2 = 3 3 – 1borrow = 2 2–1=1

0 – 1borrow = 0 + 1borrow = 0 + 2 = 2 2 – 1borrow = 1 1–0=1

0 – 1borrow = 0 + 1borrow = 0 + 2 = 2 2 – 1borrow = 1 1–1=0

1 – 1borrow = 1 + 1borrow = 1 + 2 = 3 3 – 1borrow = 2 2–1=1

1 – 1borrow = 0

1 – 1borrow = 0

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BAHASA RAKITAN (Jawaban PR 15 November 2009 ) 1). (c) Perkalian Bilangan Biner

Rincian :

1 1 1 0 1 1 0(2) 1 1 1 0 1 1(2) x 1110110 1110110 0000000 1110110 1110110 1110110 + 1 1 1 1 1 0 1 0 1 0 1 1 1 0 0 1 0(2)

2). (a) Penambahan Bilangan Oktal

Table Perkalian Bil. Biner Bil. I Bil. II Hasil 0 0 0 1 0 0 0 1 0 1 1 1 Table Penjumlahan Bil. Biner Bil. I Bil. II Hasil 1 0 1 0 1 1 1 1 0 0 0 0

2). (b) Pengurangan Bilangan Oktal

5 4 7 6 5(8) 4 7 7 5 6(8) 3 6 7 7 2(8) +

6 5 4 0 0 1(8) 3 4 5 7 6 7(8) 1 7 3 7 7 6(8) -

1 6 3 7 3 4(8)

1 1 2 0 1 4(8)

Rincian :

Rincian :

5 + 6 = 11 + 2 = 13 13 – 8 = 4, carry 1

1 + 1borrow = 1 + 8 = 9 – 7 = 2 2 + 1borrow = 2 + 8 = 10 – 6 = 4

1carry + 6 = 7 + 5 + 7 = 19 19 – 8 = 11 – 8 = 3, carry 2

0 – 2borrow = 0 + 1borrow = 0 + 8 = 8 8 – 2borrow = 6 – 6 = 0 0 + 1borrow = 0 + 8 = 8 8–7=1

2carry + 7 = 9 + 7 + 7 = 23 23 – 8 = 15 – 8 = 7, carry 2 2carry + 4 = 6 + 7 + 6 = 19 19 – 8 = 11 – 8 = 3, carry 2 2carry + 5 = 7 + 4 + 3 = 14 14 – 8 = 6, carry 1

0 – 2borrow = 0 + 1borrow = 0 + 8 = 8 8 – 2borrow = 6 + 1borrow = 6 + 8 = 14 14 – 7 = 7 – 7 = 0 4 – 2borrow = 4 + 1borrow = 4 + 8 = 12 12 – 2borrow = 10 – 5 = 5 5–3=2

1carry = 1 5 – 1borrow = 4 – 4 = 0 0 + 1borrow = 0 + 8 = 8 8–7=1 6 – 1borrow = 5 – 3 = 2 2–1=1 [ Terima kasih \ Page 2 of 2

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