Bab 55kuy.docx
This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA
Overview
Download & View Bab 55kuy.docx as PDF for free.
More details
- Words: 1,236
- Pages: 13
4.1
Pengolahan Data 4.5.1. Menghitung ∑β ∑β = βB+ βC + βD + βE + βF + βG + βH = 221°26’ + 229°55’ + 248°6’ + 215°3’ + 252°40’ + 185°44’ + 183°30’ = 1896°5’ 4.5.2. Menghitung f α f α = (α AH - α AB) - ∑β + (n x 180°) = (129°32’ - 230°31’) - 1896°5’ + (9 x 180°) = 377°4’0’’ 4.5.3. Menghitung Besar Sudut β̅ fα ̅̅̅ βB = βB + n
= 221°26’ +
377°4’0" 7
= 167°5’
̅̅̅ βC = βC +
fα n
= 229°55’ +
377°4’0" 7
= 175°59’
̅β̅̅D̅ = βD +
fα n
= 248°6’ + = 194°11’
̅̅̅ βE = βE +
fα n
377°4’0" 7
377°4’0"
= 215°3’ +
7
= 161°8’
̅̅̅ βF = βF +
fα n
= 252°40’ +
377°4’0" 7
= 198°44’
̅̅̅ βG = βG +
fα n
= 185°44’ +
377°4’0" 7
= 131°49’
̅̅̅H̅ = βH + β
fα n
= 183°30’ +
377°4’0" 7
= 129°32’
4.5.4. Menghitung Azimuth ∝ ̅̅̅̅ = α AB + ̅̅̅ αBC βB - (180° x n) = 230°31’ + 167°5' – (180° x 2) = 141°58’ ̅̅̅̅ = αBC ̅̅̅̅ + ̅̅̅ αCD βC - (180° x n) = 141°58’ + 175°59’ – (180° x 1) = 145°58’ ̅̅̅̅ + ̅β̅̅D̅ - (180° x n) ̅̅̅̅ = αCD αDE = 145°58’ + 194°11’ - (180° x 1) = 131°46’ ̅̅̅̅ = αDE ̅̅̅̅ + ̅̅̅ αEF βE - (180° x n)
= 131°46’ + 161°8’ – (180° x 1) = 150°40’ ̅̅̅̅ = αEF ̅̅̅̅ + ̅̅̅ αFG βF - (180° x n) = 150°40’ + 198°44’ – (180° x 1) = 131°55’
̅̅̅̅ = αFG ̅̅̅̅ + ̅̅̅ αGH βG - (180° x n) = 131°55’ + 131°49’ – (180° x 3/2) = 270°5’ ̅̅̅̅ ̅̅̅̅ = αGH ̅̅̅̅ + β αAH H - (180° x n) = 270°5’ + 183°32’ – (180° x 1/2) = 230°31’
4.5.5. Menghitung Selisih Absis dan Ordinat ∆x AB = dAB sin α ̅̅̅̅ AB = 24 sin 230°31’ = -1.852342989 ∆x BC = dBC sin α ̅̅̅̅ BC = 36 sin 141°58’ = -22.17913507
∆x CD = dCD sin α ̅̅̅̅ CD = 24 sin 145°58’ = -13.43054992 ∆x DE = dDE sin α ̅̅̅̅ DE
= 17 sin 130°46’ = -12.67497529 ̅̅̅̅ ∆x EF = dEF sin α EF = 34 sin 150°40’ = -16.65994548 ̅̅̅̅ ∆x FG = dFG sin α FG = 19 sin 131°55’ = -14.13928263 ̅̅̅̅ ∆x GH = dGH sin α GH = 14 sin 270°5’ = 13.99997968 ∆x AH = dAH sin α ̅̅̅̅ AH = 11 sin 230°31’ = 8.489905366 ∆y AB = dAB cos α ̅̅̅̅ AB = 24 cos 230°31’ = -1.52605 ∆y BC = dBC cos α ̅̅̅̅ BC = 36 cos 141°58’ = -28.3564
∆y CD = dCD cos α ̅̅̅̅ CD = 24 cos 145°58’ = -19.8902 ∆y DE = dDE cos α ̅̅̅̅ DE
= 17 cos 131°46’ = -11.3289 ̅̅̅̅ ∆y EF = dEF cos α EF = 34 cos 150°40’ = -29.6386 ̅̅̅̅ ∆y FG = dFG cos α FG = 19 cos 131°55’ = -12.6918 ̅̅̅̅ ∆y GH = dGH cos α GH = 14 cos 270°5’ = 0.023853 ∆y AH = dAH cos α ̅̅̅̅ AH = 11 cos 230°31’ = - 6.99439
4.6.6 Menghitung Selisih Absis dan Ordinat yang sudah di koreksi ̅̅̅̅̅̅̅ = ∆XAB + 𝑑𝐴𝐵 x fα ∆XAB ∑𝑑 24
= -18.52342989 + 179 x 129.5833333 = - 5.984038642
𝑑𝐵𝐶 ̅̅̅̅̅̅̅ ∆XBC = ∆XBC + ∑ 𝑑 x fα 36
= -22.17913507 + 179 x 129.5833333 = 6.575437381 ̅̅̅̅̅̅̅ = ∆XCD + 𝑑𝐶𝐷 x fα ∆XCD ∑𝑑 24
= -13.43054992 + 179 x 129.5833333 = 3.405831713 𝑑𝐷𝐸 ̅̅̅̅̅̅̅ ∆XDE = ∆XDE + ∑ 𝑑 x fα 17
= -12.67497529 + 179 x 129.5833333 = 1.005795 𝑑𝐸𝐹 ̅̅̅̅̅̅̅ ∆XEF = ∆XEF + ∑ 𝑑 x fα
= -16.65994548 +
34 179
x 129.5833333
= 6.241595 ̅̅̅̅̅̅̅ = ∆XFG + 𝑑𝐹𝐺 x fα ∆XFG ∑𝑑 19
= -14.13928263 + 179 x 129.5833333 = -6.93548 𝑑𝐺𝐻 ̅̅̅̅̅̅̅̅ ∆XGH = ∆XGH + ∑ x fα 𝑑
14
= -13.999999 + 179 x 129.5833333 = -16.3712 ̅̅̅̅̅̅̅̅ = ∆XHA + 𝑑𝐻𝐴 x fα ∆XHA ∑𝑑 11
= 8.4899 + 179 x 129.5833333 = 12.08158
24 ̅̅̅̅̅̅̅ ∆YAB = ∆YAB + ∑ 𝑑 x fα 24
= -1.52605 + 179 x 129.5833333 = 13.27652 ̅̅̅̅̅̅̅ = ∆YBC + 𝑑𝐵𝐶 x fα ∆YBC ∑𝑑 36
= -28.3564 + 179 x 129.5833333 = 4.847445 𝑑𝐶𝐷 ̅̅̅̅̅̅̅ ∆YCD = ∆YCD + ∑ 𝑑 x fα 24
= -19.8902 + 179 x 129.5833333 = 1.912363 ̅̅̅̅̅̅̅ = ∆YDE + 𝑑𝐷𝐸 x fα ∆YDE ∑𝑑 17
= -11.3289+ 179 x 129.5833333 = -4.84379 𝑑𝐸𝐹 ̅̅̅̅̅̅̅ ∆YEF = ∆YEF + ∑ 𝑑 x fα 34
= -29.6386 + 179 x 129.5833333 = -7.26829 ̅̅̅̅̅̅̅ = ∆YFG + 𝑑𝐹𝐺 x fα ∆YFG ∑𝑑 19
= -12.6918 + 179 x 129.5833333 = -0.97306 ̅̅̅̅̅̅̅̅ = ∆YGH + 𝑑𝐺𝐻 x fα ∆YGH ∑𝑑 14
= 0.023853 + 179 x 129.5833333
= 8.658685 ̅̅̅̅̅̅̅̅ = ∆YHA + 𝑑𝐻𝐴 x fα ∆YHA ∑𝑑 11
= -6.99439 + 179 x 129.5833333 = -0.20988
4.5.6. Menghitung Koordinat Tiap Titik
XA = 0 XB = XA + ∆x AB = 0+ (-5.984038642 )
= -5.984038642 XC = XB + ∆x BC = (-5.984038642) + 6.828410655 = 0.844372
XD = XC + ∆x CD = 0.844372 + 3.405831713 = 4.250204
XE = XD + ∆x DE 4.250204 + 6.005795033
= 10.256
XF = XD + ∆x EF = 10.256 + 2.241595157 = 12.49759
XG = XF + ∆x FG = 12.49759 + (-1.935480505) = 10.56211
XH = XG + ∆x GH = 10.56211+ (-4.371242938) = 6.19087
AH = XH + ∆x AH = 6.19087+ (-6.19087) =0
YA= 0 YB = YA + ∆y AB = 0 + 13.27652 = 13.27652 YC = YC + ∆y BC = 13.27652 + 4.847445 = 18.12396566
YD = YC + ∆y CD = 18.12396566 + 1.91239
= 20.0363558 YE = YD + ∆y DE = 20.0363558 + 5.156208 = 25.19253675
YF = YE + ∆y EF = 25.19253675 + (-5.26829) = 19.92425046 YG = YF + ∆y FG =19.92425046 + (-7.71989) = 12.20436392
YH = YG + ∆y GH = 12.20436392 + -4.61098 = 7.593384421
YA = YH + ∆y HA = 7.593384421 + (-7.593384421) =0
Koordinat x,y
A = (0,0) B = (-5.984038642 ,13.27652) C = (0.844372 , 18.12396566) D = (4.250204, 20.0363285) E = (10.256 , 25.19253675) F = (12.49759, 19.92425046) G = (10.56211, 12.20436392) H = (6.19087, 7.593384421) A = (0,0)
5.7 Kesimpulan Dari praktikum pemetaan lahan terapan yang telah dilaksanakan, dapat ditarik kesimpulan antara lain : 1.
Pengukuran yang digunakan adalah pengukuran theodolit tertutup.
2.
Dari data praktikum theodolit dapat diambil beberapa hal, yaitu : sudut, jarak dan azimut dai suatu daerah.
3.
Dari azimut yang didapatkan dapat diketahui koordinat titik – titik theodolit yang akan diplotkan ke kertas gambar.
4.
Kesalahan perhitungan theodolit dapat disebabkan oleh 3 faktor yaitu : faktor manusia (human error), faktor alat dan faktor alam.
5.
Berikut adalah nilai X dan Y yang telah didapat:
XA
=0
XB
= -5.98404
XC
= 0.844372
XD
= 4.250204
XE
= 10.256
XF
= 12.49759
XG
= 10.56211
XH
= 6.19087
XA
= 0
YA
=0
YB
= 13.27652074
YC
= 18.12396566
YD
= 20.0363285
YE
= 25.19253675
YF
=19.92425046
YG
= 12.20436392
YH
= 7.593384421
YA
=0
Pengolahan Data 4.5.1. Menghitung ∑β ∑β = βB+ βC + βD + βE + βF + βG + βH = 221°26’ + 229°55’ + 248°6’ + 215°3’ + 252°40’ + 185°44’ + 183°30’ = 1896°5’ 4.5.2. Menghitung f α f α = (α AH - α AB) - ∑β + (n x 180°) = (129°32’ - 230°31’) - 1896°5’ + (9 x 180°) = 377°4’0’’ 4.5.3. Menghitung Besar Sudut β̅ fα ̅̅̅ βB = βB + n
= 221°26’ +
377°4’0" 7
= 167°5’
̅̅̅ βC = βC +
fα n
= 229°55’ +
377°4’0" 7
= 175°59’
̅β̅̅D̅ = βD +
fα n
= 248°6’ + = 194°11’
̅̅̅ βE = βE +
fα n
377°4’0" 7
377°4’0"
= 215°3’ +
7
= 161°8’
̅̅̅ βF = βF +
fα n
= 252°40’ +
377°4’0" 7
= 198°44’
̅̅̅ βG = βG +
fα n
= 185°44’ +
377°4’0" 7
= 131°49’
̅̅̅H̅ = βH + β
fα n
= 183°30’ +
377°4’0" 7
= 129°32’
4.5.4. Menghitung Azimuth ∝ ̅̅̅̅ = α AB + ̅̅̅ αBC βB - (180° x n) = 230°31’ + 167°5' – (180° x 2) = 141°58’ ̅̅̅̅ = αBC ̅̅̅̅ + ̅̅̅ αCD βC - (180° x n) = 141°58’ + 175°59’ – (180° x 1) = 145°58’ ̅̅̅̅ + ̅β̅̅D̅ - (180° x n) ̅̅̅̅ = αCD αDE = 145°58’ + 194°11’ - (180° x 1) = 131°46’ ̅̅̅̅ = αDE ̅̅̅̅ + ̅̅̅ αEF βE - (180° x n)
= 131°46’ + 161°8’ – (180° x 1) = 150°40’ ̅̅̅̅ = αEF ̅̅̅̅ + ̅̅̅ αFG βF - (180° x n) = 150°40’ + 198°44’ – (180° x 1) = 131°55’
̅̅̅̅ = αFG ̅̅̅̅ + ̅̅̅ αGH βG - (180° x n) = 131°55’ + 131°49’ – (180° x 3/2) = 270°5’ ̅̅̅̅ ̅̅̅̅ = αGH ̅̅̅̅ + β αAH H - (180° x n) = 270°5’ + 183°32’ – (180° x 1/2) = 230°31’
4.5.5. Menghitung Selisih Absis dan Ordinat ∆x AB = dAB sin α ̅̅̅̅ AB = 24 sin 230°31’ = -1.852342989 ∆x BC = dBC sin α ̅̅̅̅ BC = 36 sin 141°58’ = -22.17913507
∆x CD = dCD sin α ̅̅̅̅ CD = 24 sin 145°58’ = -13.43054992 ∆x DE = dDE sin α ̅̅̅̅ DE
= 17 sin 130°46’ = -12.67497529 ̅̅̅̅ ∆x EF = dEF sin α EF = 34 sin 150°40’ = -16.65994548 ̅̅̅̅ ∆x FG = dFG sin α FG = 19 sin 131°55’ = -14.13928263 ̅̅̅̅ ∆x GH = dGH sin α GH = 14 sin 270°5’ = 13.99997968 ∆x AH = dAH sin α ̅̅̅̅ AH = 11 sin 230°31’ = 8.489905366 ∆y AB = dAB cos α ̅̅̅̅ AB = 24 cos 230°31’ = -1.52605 ∆y BC = dBC cos α ̅̅̅̅ BC = 36 cos 141°58’ = -28.3564
∆y CD = dCD cos α ̅̅̅̅ CD = 24 cos 145°58’ = -19.8902 ∆y DE = dDE cos α ̅̅̅̅ DE
= 17 cos 131°46’ = -11.3289 ̅̅̅̅ ∆y EF = dEF cos α EF = 34 cos 150°40’ = -29.6386 ̅̅̅̅ ∆y FG = dFG cos α FG = 19 cos 131°55’ = -12.6918 ̅̅̅̅ ∆y GH = dGH cos α GH = 14 cos 270°5’ = 0.023853 ∆y AH = dAH cos α ̅̅̅̅ AH = 11 cos 230°31’ = - 6.99439
4.6.6 Menghitung Selisih Absis dan Ordinat yang sudah di koreksi ̅̅̅̅̅̅̅ = ∆XAB + 𝑑𝐴𝐵 x fα ∆XAB ∑𝑑 24
= -18.52342989 + 179 x 129.5833333 = - 5.984038642
𝑑𝐵𝐶 ̅̅̅̅̅̅̅ ∆XBC = ∆XBC + ∑ 𝑑 x fα 36
= -22.17913507 + 179 x 129.5833333 = 6.575437381 ̅̅̅̅̅̅̅ = ∆XCD + 𝑑𝐶𝐷 x fα ∆XCD ∑𝑑 24
= -13.43054992 + 179 x 129.5833333 = 3.405831713 𝑑𝐷𝐸 ̅̅̅̅̅̅̅ ∆XDE = ∆XDE + ∑ 𝑑 x fα 17
= -12.67497529 + 179 x 129.5833333 = 1.005795 𝑑𝐸𝐹 ̅̅̅̅̅̅̅ ∆XEF = ∆XEF + ∑ 𝑑 x fα
= -16.65994548 +
34 179
x 129.5833333
= 6.241595 ̅̅̅̅̅̅̅ = ∆XFG + 𝑑𝐹𝐺 x fα ∆XFG ∑𝑑 19
= -14.13928263 + 179 x 129.5833333 = -6.93548 𝑑𝐺𝐻 ̅̅̅̅̅̅̅̅ ∆XGH = ∆XGH + ∑ x fα 𝑑
14
= -13.999999 + 179 x 129.5833333 = -16.3712 ̅̅̅̅̅̅̅̅ = ∆XHA + 𝑑𝐻𝐴 x fα ∆XHA ∑𝑑 11
= 8.4899 + 179 x 129.5833333 = 12.08158
24 ̅̅̅̅̅̅̅ ∆YAB = ∆YAB + ∑ 𝑑 x fα 24
= -1.52605 + 179 x 129.5833333 = 13.27652 ̅̅̅̅̅̅̅ = ∆YBC + 𝑑𝐵𝐶 x fα ∆YBC ∑𝑑 36
= -28.3564 + 179 x 129.5833333 = 4.847445 𝑑𝐶𝐷 ̅̅̅̅̅̅̅ ∆YCD = ∆YCD + ∑ 𝑑 x fα 24
= -19.8902 + 179 x 129.5833333 = 1.912363 ̅̅̅̅̅̅̅ = ∆YDE + 𝑑𝐷𝐸 x fα ∆YDE ∑𝑑 17
= -11.3289+ 179 x 129.5833333 = -4.84379 𝑑𝐸𝐹 ̅̅̅̅̅̅̅ ∆YEF = ∆YEF + ∑ 𝑑 x fα 34
= -29.6386 + 179 x 129.5833333 = -7.26829 ̅̅̅̅̅̅̅ = ∆YFG + 𝑑𝐹𝐺 x fα ∆YFG ∑𝑑 19
= -12.6918 + 179 x 129.5833333 = -0.97306 ̅̅̅̅̅̅̅̅ = ∆YGH + 𝑑𝐺𝐻 x fα ∆YGH ∑𝑑 14
= 0.023853 + 179 x 129.5833333
= 8.658685 ̅̅̅̅̅̅̅̅ = ∆YHA + 𝑑𝐻𝐴 x fα ∆YHA ∑𝑑 11
= -6.99439 + 179 x 129.5833333 = -0.20988
4.5.6. Menghitung Koordinat Tiap Titik
XA = 0 XB = XA + ∆x AB = 0+ (-5.984038642 )
= -5.984038642 XC = XB + ∆x BC = (-5.984038642) + 6.828410655 = 0.844372
XD = XC + ∆x CD = 0.844372 + 3.405831713 = 4.250204
XE = XD + ∆x DE 4.250204 + 6.005795033
= 10.256
XF = XD + ∆x EF = 10.256 + 2.241595157 = 12.49759
XG = XF + ∆x FG = 12.49759 + (-1.935480505) = 10.56211
XH = XG + ∆x GH = 10.56211+ (-4.371242938) = 6.19087
AH = XH + ∆x AH = 6.19087+ (-6.19087) =0
YA= 0 YB = YA + ∆y AB = 0 + 13.27652 = 13.27652 YC = YC + ∆y BC = 13.27652 + 4.847445 = 18.12396566
YD = YC + ∆y CD = 18.12396566 + 1.91239
= 20.0363558 YE = YD + ∆y DE = 20.0363558 + 5.156208 = 25.19253675
YF = YE + ∆y EF = 25.19253675 + (-5.26829) = 19.92425046 YG = YF + ∆y FG =19.92425046 + (-7.71989) = 12.20436392
YH = YG + ∆y GH = 12.20436392 + -4.61098 = 7.593384421
YA = YH + ∆y HA = 7.593384421 + (-7.593384421) =0
Koordinat x,y
A = (0,0) B = (-5.984038642 ,13.27652) C = (0.844372 , 18.12396566) D = (4.250204, 20.0363285) E = (10.256 , 25.19253675) F = (12.49759, 19.92425046) G = (10.56211, 12.20436392) H = (6.19087, 7.593384421) A = (0,0)
5.7 Kesimpulan Dari praktikum pemetaan lahan terapan yang telah dilaksanakan, dapat ditarik kesimpulan antara lain : 1.
Pengukuran yang digunakan adalah pengukuran theodolit tertutup.
2.
Dari data praktikum theodolit dapat diambil beberapa hal, yaitu : sudut, jarak dan azimut dai suatu daerah.
3.
Dari azimut yang didapatkan dapat diketahui koordinat titik – titik theodolit yang akan diplotkan ke kertas gambar.
4.
Kesalahan perhitungan theodolit dapat disebabkan oleh 3 faktor yaitu : faktor manusia (human error), faktor alat dan faktor alam.
5.
Berikut adalah nilai X dan Y yang telah didapat:
XA
=0
XB
= -5.98404
XC
= 0.844372
XD
= 4.250204
XE
= 10.256
XF
= 12.49759
XG
= 10.56211
XH
= 6.19087
XA
= 0
YA
=0
YB
= 13.27652074
YC
= 18.12396566
YD
= 20.0363285
YE
= 25.19253675
YF
=19.92425046
YG
= 12.20436392
YH
= 7.593384421
YA
=0
Related Documents
Bab
April 2020 88
Bab
June 2020 76
Bab
July 2020 76
Bab
May 2020 82
Bab I - Bab Iii.docx
December 2019 87
Bab I - Bab Ii.docx
April 2020 72More Documents from "Putri Putry"
Cover Praktikum Hidraulika.docx
May 2020 9
Pjr Kaji.docx
May 2020 2
Bab 55kuy.docx
May 2020 3
Buku 1 Lur.xlsx
May 2020 3
