ANALISIS ITEM Sampel : 40
n
H = 27% dari 40 = 10
2n = 20
L = 27% dari 40 = 10
n
No soal
n
Key
1
20
C
PH =
10 =1 10
P = -
PL =
5 = 0,5 10
∆ = -
H L
A
B
C
D
E
O
∑
5
-
10 5
-
-
-
10 10
PH PL -
-
P
r
∆
-
-
-
P
r
∆
-
-
-
r = -
Kesimpulan No. 1 : Menurut DP = Baik Sekali Menurut TK = Sedang No soal
n
Key
2
20
D
PH =
10 =1 10
10 PL = =1 10
H L
A
B
C
D
E
O
∑
-
-
-
10 10
-
-
10 10
P = r = ∆ = -
Kesimpulan No. 2 : Menurut DP = Baik Sekali Menurut TK = Mudah
PH PL -
-
No soal
n
Key
3
20
D
PH =
10 =1 10
P = -
PL =
10 =1 10
∆ = -
H L
A
B
C
D
E
O
∑
-
-
-
10 10
-
-
10 10
PH PL -
-
P
r
∆
-
-
-
P
r
∆
-
-
-
P
r
∆
39
42
14,1
r = -
Kesimpulan No. 3 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
4
20
B
PH =
10 =1 10
P = -
PL =
10 =1 10
∆ = -
H L
A
B
C
D
E
O
∑
-
10 10
-
-
-
-
10 10
PH PL -
-
r = -
Kesimpulan No. 2 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
5
20
E
H L
6 PH = = 0,6 = 60 10 PL =
2 = 0,2 = 20 10
A
B
C
D
E
O
∑
-
3 8
-
1 -
6 2
-
10 10
P = 39 r = 42 → baik sekali ∆ = 14,1 → sukar
Kesimpulan No. 5 : Menurut DP = Baik Sekali Menurut TK = Sukar
PH PL -
-
No soal
n
Key
6
20
A
PH =
7 = 0,7 = 70 10
PL =
H L
A
B
C
D
E
O
∑
PH PL
P
r
∆
10 7
3
-
-
-
-
10 10
70 -
30
50
40
13,0
PH PL
P
r
∆
-
-
-
P = 50 r = 40 → baik sekali
30 = 0,3 = 30 10
∆ = 13,0 → sedang
Kesimpulan No. 6 : Menurut DP = Baik Sekali Menurut TK = Sedang No soal
n
Key
7
20
E
PH =
5 = 0,5 10
P = -
0 =0 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
2
3
-
5 5
5 -
-
10 10
-
-
r = -
Kesimpulan No. 7 : Menurut DP = Buruk Menurut TK = Sukar No soal
n
Key
8
20
B
PH =
9 = 0,9 = 90 10
PL =
H L
3 = 0,3= 30 10
A
B
C
D
E
O
∑
PH PL
P
r
∆
-
9 7
1 2
1
-
-
10 10
90 -
81
30
9,5
P = 81 r = 30 → baik ∆ = 9,5 → mudah
Kesimpulan No. 8 : Menurut DP = Baik Menurut TK = Mudah
70
No soal
n
Key
9
20
D
PH =
7 = 0,7 10
PL =
H L
A
B
C
D
E
O
∑
PH PL
P
r
∆
-
1
-
7 7
3 2
-
10 10
70 -
70
70
00
10,9
PH PL
P
r
∆
-
-
-
P
r
∆
-
-
-
P = 70 r = 00 → buruk
7 = 0,7 10
∆ = 10,9 → sedang
Kesimpulan No. 9 : Menurut DP = Buruk Menurut TK = Sedang No soal
n
Key
10
20
E
PH =
10 =1 10
P = -
6 = 0,6 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
-
2
2
10 6
-
10 10
-
-
r = -
Kesimpulan No. 10 : Menurut DP = Baik Menurut TK = Sedang No soal
n
Key
11
20
E
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
-
-
-
10 10
-
10 10
r = -
Kesimpulan No. 11 : Menurut DP = Baik Sekali Menurut TK = Mudah
PH PL -
-
No soal
n
Key
12
20
A
PH =
8 = 0,8 10
P = -
6 = 0,6 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
PH PL
P
r
∆
8 6
1
1 -
1 1
10 2
-
10 10
80 -
60
-
-
-
PH PL
P
r
∆
-
-
-
P
r
∆
-
-
-
r = -
Kesimpulan No. 12 : Menurut DP = Baik Menurut TK = Sedang No soal
n
Key
13
20
C
PH =
10 =1 10
P = -
5 = 0,5 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
5
-
10 5
-
-
-
10 10
-
-
r = -
Kesimpulan No. 13 : Menurut DP = Baik Sekali Menurut TK = Sedang No soal
n
Key
14
20
C
PH =
10 =1 10
P = -
5 = 0,5 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
5
-
10 5
-
-
-
10 10
r = -
Kesimpulan No. 14 : Menurut DP = Baik Sekali Menurut TK = Sedang
PH PL -
-
No soal
n
Key
15
20
D
PH =
9 = 0,9 = 90 10
PL =
H L
A
B
C
D
E
O
∑
PH PL
P
r
∆
-
5
1
9 3
1 1
-
10 10
90 -
30
62
62
11,7
PH PL
P
r
∆
-
-
-
P
r
∆
-
-
-
P = 62 r = 62 → baik sekali
3 = 0,3 = 30 10
∆ = 11,7 → sedang
Kesimpulan No. 15 : Menurut DP = Baik Sekali Menurut TK = Sedang No soal
n
Key
16
20
B
PH =
0 =0 10
P = -
0 =0 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
3
-
1 6
4 -
5 1
-
10 10
-
-
r = -
Kesimpulan No. 16 : Menurut DP = Buruk Menurut TK = Sukar No soal
n
Key
17
20
C
PH =
10 =1 10
P = -
6 = 0,6 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
-
10 6
2
2
-
10 10
r = -
Kesimpulan No. 17 : Menurut DP = Baik Sekali Menurut TK = Sedang
PH PL -
-
No soal
n
Key
18
20
A
PH =
7 = 0,7 = 70 10
P = -
6 = 0,6 = 60 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
PH PL
P
r
∆
7 6
3 2
2
-
-
-
10 10
70 -
60
-
-
-
PH PL
P
r
∆
-
-
-
r = -
Kesimpulan No. 18 : Menurut DP = Sedang Menurut TK = Sedang No soal
n
Key
19
20
B
PH =
5 = 0,5 10
P = -
0 =0 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
3 5
5 -
3
2
2 -
-
10 10
-
0
r = -
Kesimpulan No. 19 : Menurut DP = Buruk Menurut TK = Sukar No soal
n
Key
20
20
A
PH =
7 = 0,7 10
PL =
5 = 0,5 10
H L
A
B
C
D
E
O
∑
PH PL
P
r
∆
7 5
-
3 3
1
1
-
10 10
70 -
60
21
12,0
P = 60 r = 21 → sedang ∆ = 12,0 → sedang
Kesimpulan No. 20 : Menurut DP = Sedang Menurut TK = Sedang
50
No soal
n
Key
21
20
E
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
-
-
-
10 10
-
10 10
PH PL -
-
P
r
∆
-
-
-
P
r
∆
-
-
-
P
r
∆
-
-
-
r = -
Kesimpulan No. 21 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
22
20
C
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
-
10 10
-
-
-
10 10
PH PL -
-
r = -
Kesimpulan No. 22 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
23
20
B
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
10 10
-
-
-
-
10 10
r = -
Kesimpulan No. 23 : Menurut DP = Baik Sekali Menurut TK = Mudah
PH PL -
-
No soal
n
Key
24
20
D
PH =
10 =1 10
P = -
9 = 0,9 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
-
-
10 9
1
-
10 10
PH PL -
-
P
r
∆
-
-
-
P
r
∆
-
-
-
P
r
∆
-
-
-
r = -
Kesimpulan No. 24 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
25
20
D
PH =
10 =1 10
P = -
6 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
2
-
2
10 6
-
-
10 10
PH PL -
-
r = -
Kesimpulan No. 25 : Menurut DP = Baik Sekali Menurut TK = Sedang No soal
n
Key
26
20
C
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
-
10 10
-
-
-
10 10
r = -
Kesimpulan No. 26 : Menurut DP = Baik Sekali Menurut TK = Mudah
PH PL -
-
No soal
n
Key
27
20
A
PH =
9 = 0,9 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
9 10
-
-
1 -
-
-
10 10
PH PL -
-
P
r
∆
-
-
-
P
r
∆
-
-
-
P
r
∆
44
50
13,6
r = -
Kesimpulan No. 27 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
28
20
D
PH =
9 = 0,9 10
P = -
6 = 0,6 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
1 2
2
9 6
-
-
10 10
PH PL -
-
r = -
Kesimpulan No. 28 : Menurut DP = Baik Menurut TK = Sedang No soal
n
Key
29
20
A
PH =
7 = 0,7 10
PL =
2 = 0,2 10
H L
A
B
C
D
E
O
∑
7 2
-
2 2
-
1 6
-
10 10
P = 44 r = 50 → baik sekali ∆ = 13,6 → sedang
Kesimpulan No. 29 : Menurut DP = Baik Sekali Menurut TK = Sedang
PH PL -
-
No soal
n
Key
30
20
E
PH =
0 =0 10
P = -
0 =0 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
1
-
1 4
9 5
-
-
10 10
PH PL 0 -
0
P
r
∆
-
-
-
P
r
∆
-
-
-
P
r
∆
-
-
-
r = -
Kesimpulan No. 30 : Menurut DP = Buruk Menurut TK = Sukar No soal
n
Key
31
20
A
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
10 10
-
-
-
-
-
10 10
PH PL -
-
r = -
Kesimpulan No. 31 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
32
20
B
PH =
9 = 0,9 10
P = -
6 = 0,6 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
1 4
9 6
-
-
-
-
10 10
r = -
Kesimpulan No. 32 : Menurut DP = Baik Menurut TK = Sedang
PH PL -
-
No soal
n
Key
33
20
B
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
10 10
-
-
-
-
10 10
PH PL -
-
P
r
∆
-
-
-
P
r
∆
-
-
-
P
r
∆
-
-
-
r = -
Kesimpulan No. 33 : Menurut DP = Baik Sekali Menurut TK = Mudah No soal
n
Key
34
20
A
PH =
10 =1 10
P = -
9 = 0,9 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
10 9
-
-
1
-
-
10 10
PH PL -
-
r = -
Kesimpulan No. 34 : Menurut DP = Baik Sekali Menurut TK = Sedang No soal
n
Key
35
20
B
PH =
10 =1 10
P = -
10 =1 10
∆ = -
PL =
H L
A
B
C
D
E
O
∑
-
10 10
-
-
-
-
10 10
r = -
Kesimpulan No. 35 : Menurut DP = Baik Sekali Menurut TK = Mudah
PH PL -
-