Tkss Prelim 2009 Em P1 Answers

Tanjong Katong Sec School Sec 4 Preliminary Examination Mathematics Paper 1 Answer Key 1

(a) (b)

2

3 4

55 110 25 27 y

5

(a) (b) (a)

6

(b) (a)

(b) 7

12

(a) (b)

10 x2

27 2 x  5  33 x  2 1 2 5, 2 5:8

19 1, 0, 1

8

(a)

4.340  10 9

9

(b) (a)

241 4.2

13

(a) (b)

14

(a)

15

(b) (a)

16

(b) (a)

(b)

17

23 65

(i)

7 18

d

(ii)

1 5

2( P  an) n(n  1)

400 It represents the sum of the sequence (5 x  y )(2 x  3)

(2 p  q  3)(2 p  q  3) PQS  QSR (alt s) QPS  SQR (given) PQS and QSR are similar 15  B A

(i) 1, 2, 3,6, 9 (ii) 2 (iii) C is the set of multiples of 3

(a)

y (1, 9) 8

2 4

(b) (c) 10 (a) (b) 11 (a) (b) (c)

4.45 4.1 18 156.25  q  5    0  18 12 or 12

(b) (c)

x  1 y  8  2x  x 2

2

0

2

x

18 (a)

(b)

22

(i) p  q (ii) p + 2q 1 (iii) (p + 2q) 3   1  OM  OD 3 

(a) (b) (c)

143(  1 ) Point M- Bearing of M from A=090 Point P- Pt of intersection of bisector of BC & bisector of ABC

N A

 

OM is parallel to OD and O is common point, so O, M and D lie on a straight line

M P

B C

19 (a) (b) (c)

8.48 25.5 4  5

20 (a)

1 2 4:5 9.60 7 130 3.75, 13

(b) (c) (d) 21 (a) (b) (c)

562

Distance (m) 290

130 50 0

5

9

25

Time (s)