papercollection
Jabatan Pelajaran Negeri Pahang (JPNP) 2009 Answer Scheme Trial Exam 2009 Physics Paper 1
1 2 3 4 5 6 7 8 9 10
C A D A D C C A B C
11 12 13 14 15 16 17 18 19 20
B D A D B D C D C C
21 22 23 24 25 26 27 28 29 30
A D C A B C B B B D
31 32 33 34 35 36 37 38 39 40
D C A B B A B D C D
41 42 43 44 45 46 47 48 49 50
C D A C A A C C D D
papercollection
PHYSICS Paper 2 (MARKING SCHEME) - Trial Examination F5 2009 JPN Pahang. Q1 (a) (b)(i) (ii) (c)
Q2 (a) (b) (c) (d) (e)
Q3 (a) (b)(i) (ii) (c)
Q4 (a) (b ) (c )(i )
(c)
(d )
Marking scheme 5 kPa Perpendicular to the scale of Bourdon Gauge 165 kPa increase TOTAL
Marks 1 1 1 1 4
EXPLANATION Tendency of object to remain at rest or moving with uniform velocity Mass in 2.1(a)<2.1(b) Inertia in 2.1(a)<2.1(b) Inertia of crate to remain at rest Shake bottle up and down, source comes out TOTAL
MARKS 1 1 1 1 1 5
Marking scheme Electromotive force // e.m.f. i- number of turns : 3.1 (a) < 3.1(b) ii-deflection of galvanometer : 3.1(a) < 3.1(b) - Rate of change of flux increase - Induce emf increases Faradays’ Law
1 1 1 1 1 1
TOTAL
6 EXPLANATION
2V Internal resistance// R = V/I = 1.5/0.3 =5 Ω r = E-V I =2.0-1.5 0.3 =1.67Ω I=E/(R+r) = 2.0/(2.5+1.67) =0.5 A
Marks
MARKS 2 2 2
1
V=E-IR Q5 (a )
TOTAL EXPLANATION Measure mass of ice melted by heat from surrounding
7 MARKS 1
papercollection
(b )
168 g
(c)
Latent Heat
2
(d )
L = H/m = 56800/0.168 = 338 095 Jkg-1 Heat loss to surrounding Wrap filter funnel with wool TOTAL
1 1 1 1 1 8
(e) (f)
Q6 (a) (b) (i) (b) (Ii) (c) (i) (c) (ii) (iii)
Marking scheme X: Microwave Y: Radio wave Wavelength X < wavelength Y Frequency X > Frekuensi Y Radiowave , Microwave , Infrared ray The same -
Transfer energy Transverse waves Travel in vacum
TOTAL Q7
(c) (d)
(e)
(f) (g) (h)
Marking scheme
Marks 1 1 1
1500 N
1
Time of impact 7.1(a)> 7.1(b) Impulsive force 7.1(a)<7.1(b)
1 1 1
Pain in 7.1(a)< in 7.1(b) Time of impact increase, impulsive force decrease, pain decrease Put on thick sock// wool sock
TOTAL EXPLANATION Q8 (a)
1
8
Rate of change of momentum F= m(v-u)/t = 1.5 (20-0)/0.2 = 150 N
(a) (b)
Marks 1 1 1 1 1 1
1 1 1
10 MARKS
Unstable isotope 1
papercollection
(b)
(c)(i)
D : Reading of rate meter increase 226
88
Ra
2
222
Rn = 4He 86 2
2
(c )(i i )
(d )
Sodium: 45/3=15 hrs Cobalt 60: 15.9/3 = 5.3 yrs Radium : 4860/3 = 1620 yrs Sodium 24 : short half life Emit beta, can penetrate soil
4
1 1 1
TOTAL
Q9
12
Marking scheme
(a) (b)
deflected -in 9(a) incident angle equal reflected angle -incident angle 9(a) < 9(b) -reflected angle9(a)< 9(b) Relate : incident angle increase, reflected angle increase Physics concept : incident angle = reflected angle Name : Law of reflection
(c)
Bottom edge of mirror from floor = 150 cm /2 = 75 cm Height of mirror =160 cm /2 = 80 cm
(d)
modification
explanation
Device : periscope
Cheaper than CCTV
2 plane mirrors // 2 prisms
Reflect light from object
Mirrors are arranged Parallel
Light from first mirror will be reflected into second mirror Light from second mirror is reflected into the observer’s eyes easier to handle periscope
Tube or casing to hold mirror Mirrors are at 45° angle Diagram also accepted
Marks 1 1 1 1 1 1 2 2
10 (max)
papercollection
TOTAL
Q10 (a) (b)
20
EXPLANATION Work done to transfer 1 C charges from one point to another o Electrical power is generated at high current and low voltage
MARKS 1
o Before transmission, current passes through step up transformer o During transmission, electrical power is at low current and high
5
voltage to reduce power loss o At reception point, current passes through step down transformer o At reception, electrical power is at low voltage and high current (c)
o Nonrenewable resources : natural gas, petroleum o
: will be depleted
o
: pollute the environment
o Renewable resources : hidro, solar & wind o
Will not be depleted
o
: does not pollute environment
4(Max)
(d ) (i) Characteristic Material: steel alloy
Explaination Strong, will not breake easily
U shape steel alloy
Not too heavy
Trust and support join
Can support bigger weight
Large diameter cable
Less resistance
made from small diameter and laminated wire
Reduce eddy current
Cable made from low density material
Cable is not heavy
10 (max)
*Accept any relevant answers
TOTAL
20
papercollection
Q11
11 (a) (b)
(c)
(d)
Marking Scheme
Power is rate of work done -low mass-more agile -high height-easy to shoot goal -responding time fast – easy to catch ball -power high(short time to move brick)-will not tire easily// more energy -small time to complete 100m run- can run fast Choose C: low mass, tall, respond fast, high power & can run fast -runner has Inertia -to continue moving forward -the legs stop, body continue moving forward -Unstable and fall
Marks 1 10
1 1 1 1
Student 1 : power = mgh/t = 55 x 10 x 10/ 12 =458 W
1
Student 2: power = 60 x 10 x 10 / 14 =428 W
1 1
1
Student 1 has higher power
12(a)
(b)
(c)
-intrinsic semiconductor such as silicon atom -doped with pentavalent atom such as phosphorous - each pentavalent atom contribute one free electron
(i) (ii) -
1 1
Bulb 12.2
1
Electron from n-type drift to p-n junction Holes from p-type drift to p-n junction At the junction electrons and holes combines to ensure continuous current flow. Bulb light up
1 1 1
(i) Ratio Np: Ns =Vp:Vs =240V:24V =100 ( to get 24 V output) (ii)type of core :Laminated soft iron core (reduce power loss due to eddy current in the core) (iii)full wave rectification: (less power loss & continuous current)
(d)(i)
1
2 2
2
Full wave rectification circuit diagram
2
papercollection
1
v t 1 Input signal – alternating current v t Output signal – full wave rectification
(ii)
Why How -
To smoothen the current
1
When current increases in circuit capacitor stores charges When current decreases in the circuit capacitor discharges (supply charges to the circuit) Make the current flow more stable
1 1 1
TOTAL
20
papercollection
4531
SULIT 4531 Fizik September 2009
PERSIDANGAN KEBANGSAAN PENGETUA-PENGETUA SEKOLAH MENENGAH NEGERI PAHANG
PEPERIKSAAN PERCUBAAN SPM 2009
PHYSICS PERATURAN PEMARKAHAN
Peraturan pemarkahan ini mengandungi 17 halaman bercetak 4531
papercollection
2 PHYSICS Paper 3 SECTION A Question 1 1 (a) 1
(i)
1
State the correct manipulated variable Length / L
(ii)
1
1
State the correct responding variable Resistance / R // Potential difference / V
(iii)
1
1
State one fixed variable correctly Diameter of the wire // Cross-sectional area of the wire // Type of wire //current
6
(c)
6
Tabulate L, I, V and R correctly Give a tick () based on the following: A Columns L, I, V and R B
Correct units for I, V and R
C All values of L correct
D All values of I correct
E
All values of V correct
F
All values of V consistent to 1 or 2 d.p.
G All values of R correct
H All values of R consistent to 1, 2,3 or 4 d.p. L / cm 20.0 30.0 40.0 50.0 60.0
I/A 0.2 0.2 0.2 0.2 0.2
V/V 0.5 0.7 0.9 1.1 1.3
R/Ω 2.5 3.5 4.5 5.5 6.5
Note for G : Accept e.c.f. from E Marks awarded : Number of 8 6-7 4-5 3 2 1 Total marks : 6 Question 1 (continued)
Marks 6 5 4 3 2 1
papercollection
3 5
(d)
5
Draw correctly a graph of R against L Give a tick () based on the following: A
R at the y-axis, L at the x-axis
B
Correct units at both axes
C
Uniform scale at both axes
D
5 points plotted correctly
[Note : 3 or 4 points plotted correctly : ] E
Best straight line
F
Minimum size of graph 5 x 4 big squares (Big square : 2 cm x 2 cm) (From the origin to the last point)
Marks awarded : Number of 7 5-6 3-4 2 1
Marks 5 4 3 2 1
Total marks : 5 1
(e)
1
State the correct relationship based on the straight line drawn For a straight line with positive gradient passing through the origin, Resistance is directly proportional to length / R directly proportional to L / R ∝ L For a straight line with positive gradient that does not pass through the origin, Resistance increases linearly with length
1
(f)
1
State one suitable precaution Check the voltmeter for zero error and make zero adjustment // Position of the eye such that the image of the pointer in the mirror is blocked by the pointer to avoid parallax error
16
Question 2
papercollection
4 Question 2 2 a(i) 2
1
Draw the extrapolation line from t = 1 min to the y-axis
2
State the correct value of Ɵ 25°C
1
(ii)
1
State the correct relationship of Ɵ and t Ɵ increases linearly with t
3
(iii)
1
Construct a sufficiently large triangle (4x4)
2
Make the correct substitution 69-37 5-1
3
State the correct value with unit 8.0°C min-1
2
3
1
12
b(i)
(ii)
c
1
Make correct substitution E=P x t = 200 x 5 x 60
2
State correct answer with unit 60 000 J
1
Make the correct substitution C = 60 P = 60 x 200 mM 8 x 0.4
2
State the correct answer 3750
3
State the correct unit J kg-1°C-1
1
State one suitable precaution -Eye perpendicular to scale of thermometer to avoid parallax error -Repeat experiment 4 times and calculate average -Stir cooking oil before taking thermometer reading to get uniform temperature
papercollection
5 Section B Question 3 1
3(a)
1
1
(b)
1
10
(c)
(i)
1
(ii)
2
3 (iii)
4
(iv)
5
(v)
6 7
8
(vi)
9
10 12
Write a suitable inference The object distance affects the size of the image Write a suitable hypothesis The greater the object distance, the smaller the size of the image State the aim of the experiment To investigate the relationship between the object distance and the size of the image State the manipulated variable and responding variable Manipulated variable : object distance, u Responding variable : size of the image, H State the fixed variable Focal length of the lens / type of lens State the list of apparatus and materials Convex lens with holder, light bulb with power supply, screen, metre rule Draw a functional arrangement of the apparatus Light bulb in holder connected to power supply// Cross-wire as the object in front of the bulb, convex lens in holder and screen – all align. State how the manipulated variable is controlled The convex lens is placed at distance of, u = 15 cm from the object State how the responding variable is measured The screen is adjusted until a sharp image is formed on it. The size of the image, H is measured. State how the procedure is repeated to obtain at least 5 sets of results The procedure is repeated with values of u = 20 cm, 25 cm, 30 cm, 35 cm and 40 cm. State how the data is tabulated u / cm H / cm 15 20 25 30 35 40 State how the data is analysed A graph of H against u is drawn
papercollection
6 Question 4 1
4(a)
1
1
(b)
1
10
(c)
(i)
1
(ii)
2
3 (iii)
4
(iv)
5
(v)
6
7
8
(vi)
9
10 12
Write a suitable inference depth affects wavelength Write a suitable hypothesis Depth increases, wavelength increases Write the aim of the experiment To investigate the relationship between depth and wavelength State the manipulated variable and responding variable Manipulated variable : depth, h Responding variable : wavelength, λ State the fixed variable frequency State the complete list of apparatus and materials D.c. power supply, ripple tank and accessories, lamp, metre rule, white paper, 5 pieces of perspecs/glass, stroboscope Draw a functional diagram of the apparatus State how the manipulated variable is controlled The current was switched on. The put one piece of perspecs in the ripple tank State how the responding variable is measured Mark the position of wave on the white paper as seen through the stroboscope Measure the wavelength State how the procedure is repeated to obtain at least 5 sets of results The procedure was repeated for different depth by putting pieces of perspecs on top of the previous perspecs in the ripple tank; 2,3,4 and 5 number of perspecs. State how the data is tabulated Depth/ number of Wavelength / cm perspecs 1 2 3 4 5
State how the data is analysed A graph of depth against wavelength is drawn