Sketch Of A Proof Of The Riemann Hypothesis

  • Uploaded by: Werner Raab
  • 0
  • 0
  • May 2020
  • PDF

This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA


Overview

Download & View Sketch Of A Proof Of The Riemann Hypothesis as PDF for free.

More details

  • Words: 279
  • Pages: 1
Sketch of a proof of the Riemann hypothesis Werner Raab We consider the Euler series transformation ∞ X

u(s + k)(−t)k = f (s, t) =

k=0

∞ 1 X m t m ∆ u(s)( ) 1 + t m=0 1+t

(|t| < 1 or −1/2 respectively) with the finite differences m   X m ∆m u(s) = (−1)k u(s + k) = ∆m u(s − 1) − ∆m+1 u(s − 1) k k=0

of the function u(s) =

1 (s − 1)ζ(s)

(for poisitive real values of s). It follows from the convergence of the series ∞ X u(1/2 + k)

2k

k=0

= f (1/2, −1/2) = 2

∞ X

∆m u(1/2)(−1)m

m=0

n

that limn→∞ ∆ u(1/2) = 0, which is why u(1/2) = u(1/2) − lim ∆n u(1/2) = lim n→∞

= lim

n→∞

n−1 X

m

∆ u(3/2) =

m=0

n→∞

∞ X

m

= lim

t→∞

m=0

∆m u(3/2)(

(∆m u(1/2) − ∆m+1 u(1/2))

m=0

∆ u(3/2) =

m=0 ∞ X

n−1 X

∞ X m=0

∆m u(3/2) lim ( t→∞

t m ) 1+t

t m ) = lim (f (3/2, t)t) , t→∞ 1+t

due to Abel’s theorem of continuity for power series. Thus we can conclude that Z ∞ π u(3/2 − s) = ts−1 w(t) dt v(s) = sin(πs) 0 is holomorphic in the complex strip: 0 < <s < 1, as Riemann conjectured, since Z 1/2+i∞ ∞ X  1 w(t) = t−s v(s) ds = Ress=−k t−s v(s) = f (3/2, t) 2πi 1/2−i∞ k=0

has the properties w(t) = O(1) when t → 0 and w(t) = O(1/t) when t → ∞. 1

Related Documents


More Documents from ""