Signal Constellation

  • April 2020
  • PDF

This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA


Overview

Download & View Signal Constellation as PDF for free.

More details

  • Words: 1,413
  • Pages: 21
Modulation Principles • Almost all communication systems transmit digital data using a sinusoidal carrier waveform. – Electromagnetic signals propagate well – Choice of carrier frequency allows placement of signal in arbitrary part of spectrum

• Physical system implements modulation by: – – – –

Processing digital information at baseband Pulse shaping and filtering of digital waveform Baseband signal is mixed with signal from oscillator RF signal is filtered, amplified and coupled with antenna

Representation of Modulation Signals • We can modify amplitude, phase or frequency. • Amplitude Shift Keying (ASK) or On/Off Keying (OOK): 1 ⇒ A cos(2 π f c t ),0 ⇒ 0 • Frequency Shift Keying (FSK): 1 ⇒ A cos(2 πf1t ),0 ⇒ A cos(2 πf 0 t )

• Phase Shift Keying (PSK): 1 ⇒ A cos(2 πf ct )

0 ⇒ A cos(2 πf ct + π ) = − A cos(2 πf ct )

Representation of Bandpass Signals Bandpass signals (signals with small bandwidth compared to carrier frequency) can be represented in any of three standard formats: • Quadrature Notation s( t ) = x ( t ) cos(2 πf ct ) − y ( t ) sin(2 πf ct )

where x(t) and y(t) are real-valued baseband signals called the in-phase and quadrature components of s(t)

Representation of Bandpass Signals (continued) • Complex Envelope Notation

[

] [

s( t ) = Re ( x ( t ) + jy ( t ) )e − j 2 πf ct = Re sl (t )e − j 2 πf ct

where sl (t ) is the complex envelope of s(t). • Magnitude and Phase

]

s( t ) = a ( t ) cos(2πf ct + θ( t ))

2 (t ) + y 2 (t ) a ( t ) = x where is the magnitude of s(t),  y (t )  −1 and θ(t ) = tan  is the phase of s(t).   x (t ) 

Key Ideas from I/Q Representation of Signals • We can represent bandpass signals independent of carrier frequency. • The idea of quadrature sets up a coordinate system for looking at common modulation types. • The coordinate system is sometimes called a signal constellation diagram.

Example of Signal Constellation Diagram: BPSK •

x ( t ) ∈{± 1}, y ( t ) = 0

y( t )

X

X

x (t )

Example of Signal Constellation Diagram: QPSK •

x ( t ) ∈{± 1}, y ( t ) ∈{± 1}

y( t ) X

X

x (t ) X

X

Example of Signal Constellation Diagram: QAM •

x ( t ) ∈{− 3,−1,+1,+3}, y ( t ) ∈{− 3,−1,+1,+3}

y( t ) X

X

X

X

X

X

X

X

X

X

X

X

X

X

X

X

Interpretation of Signal Constellation Diagram • • • •

Axis are labeled with x(t) and y(t) Possible signals are plotted as points Signal power is proportional to distance from origin Probability of mistaking one signal for another is related to the distance between signal points • Decisions are made on the received signal based on the distance to signal points in constellation

New Way of Viewing Modulation • The I/Q representation of modulation is very convenient for some modulation types. • We will examine an even more general way of looking at modulation using signal spaces. • By choosing an appropriate set of axis for our signal constellation, we will be able to: – Design modulation types which have desirable properties – Construct optimal receivers for a given type of modulation – Analyze the performance of modulation types using very general techniques.

Vector Spaces • An n-dimensional vector v = [v1, v2 ,… , vn ] consists of n scalar components {v1, v2 ,… , vn } • The norm (length) of a vector v is given by: v =

n

2 v ∑ i

i =1

• The inner product of two vectors v1 = [v11, v12 ,… , v1n ] and v 2 = [v21, v22 ,… , v2n ] is given by: n

v1 ⋅ v 2 = ∑ v1i v2i i =1

Basis Vectors • A vector v may be expressed as a linear combination of it’s basis vectors {e1, e2 ,… , en } : n

v = ∑ vi ei i =1

where vi = ei ⋅ v • Think of the basis vectors as a coordinate system (xy-z... axis) for describing the vector v • What makes a good choice of coordinate system?

A Complete Orthornomal Basis • The set of basis vectors {e1, e2 ,… , en } should be complete or span the vector space ℜn . Any vector n can be expressed as v = ∑ vi ei for some {vi } i =1

• Each basis vector should be orthogonal to all others: ei ⋅ e j = 0, ∀i ≠ j

• Each basis vector should be normalized: ei = 1, ∀i • A set of basis vectors which satisfies these three properties is said to be a complete orthonormal basis.

Signal Spaces Signals can be treated in much the same way as vectors. • The norm of a signal x ( t ), t ∈[a , b] is given by: b

x( t ) =  ∫ x( t ) a

2

 dt  

1/ 2

= Ex

• The inner product of signals x1(t ) and x2 (t ) is: b

x1( t ), x2 ( t ) = ∫ x1( t ) x2∗ ( t ) dt a

• Signals can be represented as the sum of basis n functions: x (t ) = ∑ xk f k ( t ), xk = x ( t ), f k ( t ) i =1

Basis Functions for a Signal Set • One of M signals is transmitted: {s1( t ),… , s M ( t )} • The functions { f1( t ),… , f K ( t )} ( K ≤ M ) form a complete orthonormal basis for the signal set if – Any signal can be described by a linear combination: K si ( t ) = ∑ si , k f k (t ), i = 1,… , M k =1 – The basis functions are orthogonal to each other: b ∗ ( t ) dt = 0, ∀i ≠ j f ( t ) f ∫ i j a – The basis functions are normalized: b 2 f t dt = 1, ∀k ( ) ∫ k a

Example of Signal Space Consider the following signal signal set: s 2 (t )

s1(t )

+1

+1

t

t -1

1

2

-1

+1

+1

t -1

2

s 4 (t )

s 3 (t ) 1

1

2

-1

1

2

t

Example of Signal Space (continued) • We can express each of the signals in terms of the following basis functions: f 2(t )

f 1(t )

+1

+1

t

t -1

1

2

s1( t ) = 1 ⋅ f1( t ) + 1 ⋅ f 2 ( t ) s3 ( t ) = −1 ⋅ f1 ( t ) + 1 ⋅ f 2 ( t )

-1

1

2

s2 ( t ) = 1 ⋅ f1 ( t ) − 1 ⋅ f 2 ( t ) s4 ( t ) = −1 ⋅ f1 ( t ) − 1 ⋅ f 2 ( t )

• Therefore the basis is complete

Example of Signal Space (continued) • The basis is orthogonal: ∞

∗ ∫ f1( t ) f 2 ( t ) dt = 0

−∞

• The basis is normalized: ∞



2 f ( t ) dt f ( t ) dt = 1 = ∫ 1 ∫ 2

−∞

2

−∞

Signal Constellation for Example • We’ve seen this signal constellation before f2 (t ) X s (t ) 3

X s (t ) 1

f1(t ) X s (t ) 4

X

s2 (t )

Notes on Signal Spaces • Two entirely different signal sets can have the same geometric representation. • The underlying geometry will determine the performance and the receiver structure for a signal set. • In both of these cases we were fortunate enough to guess the correct basis functions. • Is there a general method to find a complete orthonormal basis for an arbitrary signal set? – Gram-Schmidt Procedure

Related Documents