JABATAN PELAJARAN NEGERI MELAKA PEPERIKSAAN PERCUBAAN SPM 2008 PHYSICS PAPER 1 SKEMA JAWAPAN 1 2 3 4 5
B A B C B
6 7 8 9 10
D C A C D
11 12 13 14 15
D B B B D
16 17 18 19 20
B A A C C
21 22 23 24 25
C A A C B
26 27 28 29 30
D D A D B
31 32 33 34 35
D A C D C
36 37 38 39 40
C A A B B
41 42 43 44 45
A D D A A
46 47 48 49 50
A C C B E
PEPERIKSAAN PERCUBAAN MELAKA 2008 MARKING SCHEME : PAPER 2 1(a)
Racet
1
(b)
The ratchet knob prevents over tightening // avoid extra pressure
1
(c)
1st : 1.5 + 0.35 = 1.85 mm 2nd : 1.85 – (- 0.02) = 1.87 mm
1 1 TOTAL
4
2(a)(i)
Bernoulli’s principle
1
(a)(ii)
Y
1
(b)
The air moves with a high speed
1
(c)
1st: The atmospheric pressure which is higher pushes the liquid up through the narrow tube. 2nd : The jet air will force the liquid to be sprayed as fine spray liquid
1
TOTAL
1 5
3(a)
Velocity = displacement Time
1
(b)
Region AB
1
(c)(i)
a = 10 – 0 10 – 0 = 1 ms-2
1
s = ½ (10)(10) + (10)(10) = 150 m
1 1
(c)(ii)
1
TOTAL 4(a)(i) (a)(ii)
(b)
6
α/β/γ 1st: The radioactive emission enters the tube through the mica window 2nd :ionizes the neon gas. 3rd : The electron and positive ion are attracted towards the anode and cathode respectively thus produces a pulse of current. Any two marks
1 1
Background readings // natural radioactivity in the ground, bricks or buildings and
1
2
cosmic radiation.
(c)
1st : show on the graph 2nd : half life = 4 hours
2
(d)
Industries : smoke detectors / detect thickness of papers / detect leaks in underground pipe water Medicine : radioactive tracers/ sterilization,/cancer treatment
1
TOTAL
7
5(a)
Attraction force
1
(b)(i)
same magnitude // opposite direction
1
(b)(ii)
Same forces / equal in magnitudes // opposite direction
1
(c)(i)
Zero
1
(c)(ii)
Equal
1
(d)(i)
1st : The nett force is zero, the object is stationary 2nd : The nett force is zero, moves with uniform velocity
1 1
(d)(ii)
Equilibrium of forces
1 TOTAL
8
6(a)
Heat is a form of energy
1
6(b)(i)
Diagram 6.2 is higher // vice versa
1
(b)(ii)
The temperature in Diagram 6.2 is higher // vice versa
1
(b)(iii)
Volume
1
(b)(iv)
When volume is higher, the temperature is higher // directly proportional
1
(c)
Charles Law
1
(c)(i)
θ = absolute zero
1
(c)(ii)
Volume of air is zero // the air molecules is at rest //kinetic energy is zero
1 TOTAL
8
7(a)(i)
Transverse wave // mechanical wave
1
(a)(ii) (b)
The gap is bigger than the wavelength 1st : smaller amplitude 2nd : same wavelength 1st : made of concrete 2nd : because concrete is strong
1 2
(c)(ii)
1st : make many holes on the wall 2nd : diffraction // spread of energy
2
(d)
1st : The water is shallow 2nd : load and unload by using small boats
2
(c)(i)
2
TOTAL 10 8(a)
Power = the rate of work done / the rate of energy transformed @P=W T State the meaning of symbols
1
(b)(i)
1st : R2 is located at the base terminal 2nd : to limit the base current
1 1
(b)(ii)
1st : R1 and LDR are in series 2nd : to function as potential divider
1 1
(b)(iii)
1st : the collector terminal is connected to positive terminal of the battery 2nd : reverse bias
1 1
(c)
Circuit K
1
(d)
Light controlled switch/ switches on the bulb at night, switches off the bulb at daytime.
1
(e)(i)
5V
1
(e)(ii)
VRY =
Ry x V ( Rx + Ry)
1000 6 R 1000 R = 6000 – 1000 = 5000 Ω
1
1
1 TOTAL 12
9(a)(i)
Magnetic field is a region of magnetic force.
1
(a)(ii)
1st : The direction of the magnetic field on the left coil is counter/anti clockwise, /diagram 2nd : The direction of the magnetic field on the right coil is clockwise // diagram
1 1
3rd : As the result the magnetic fields in the middle of the coil are in the same direction, upward. So the magnetic field will be stronger in the middle
1
1st : Both diagram 9.2 and diagram 9.3 have the same pattern of the magnetic field,ie, circular with the wire in the middle 2nd: The direction of the magnetic field for Diagram 9.2 is clockwise, while in Diagram9.3 is counter clockwise/ anti-clockwise.
1
(b)(ii)
The pattern of the magnetic field in Diagram 9.4 is not uniform compared to Diagram 9.2 and Diagram 9.3
1
(b)(iii)
The resultant force acting on the left wire is downward while the resultant force acting on the right wire is upward / opposite to each other.
1
(b)(iv)
1st : Instrument which uses the same principle is electrical motor. 2nd : The electric motor has 2 forces acting on the opposite side caused by the counter react between a current carrying conductor in a magnetic field/ diagram
1 1
(c)(i)
1st : The shape of the magnet is cylindrical 2nd : It will produce uniform magnetic field
1 1
(c)(ii)
1st : The coil is placed surrounding/fit to the magnet and it is attached to a cone 2nd : to increase the effectiveness of the counter react between the magnetic fields .
1 1
(b)(i)
1
(c)(iii)
1st : The cone is made from a light material / paper 2nd : It can easily vibrate
2
(c)(iv)
1st : Type of electrical supply is alternate current power supply 2nd: The audio signal varies with the current.
2
(c)(v)
1st : material used for the body of the loudspeaker is metal / wood 2nd : to ensure the loudspeaker is strong
2 TOTAL 20
10(a)(i) Real image is an image which can be seen on a screen. (a)(ii)
(b)
(c)(i)
1st : the object distance in diagram 10.1 is longer than diagram 10.2 2nd : the image distance in diagram 10.2 is longer than diagram 10.1 3rd : the size of the image in diagram 10.2 is larger 4th : the longer the image distance, the bigger the size of the image 5th : The smaller the object distance the larger the size of the image / the object distance is inversely proportional to size of the image. 1st : The convex lens with its holder is aimed at a distant object like a tree. 2nd : Adjust a screen until you see a very sharp and clear image of the distant object. rd 3 :When parallel light rays from a distant object pass through a convex lens, they will converge to a point called focal point/ label on a diagram th 4 : Measure the distance between the convex lens and screen./ label on a diagram 1st : draws the objective and eyepiece lenses. 2nd : correct label of objective and eyepiece 3rd : label fO and fe correctly 4th : draw the correct position for the object ( fo < u1 < 2fo) 5th : draw ray diagrams to show the position of image 1 6th : draw ray diagrams to show the final image
1
5
4
6
(c)(ii)
1st : Use a concave mirror 2nd : converge light to the microscope.
2
(c)(iii)
1st : Decrease the object distance / decrease the focal length of the eyepiece lens / decrease the focal length of the objective lens. 2nd : increase the magnification factor.
2
TOTAL 20 11(a)(i) “240 V, 80 W” means the bulb transforms energy of 80 J/s if connected to 240 V power supply. (a)(ii)
(b)(i)
(b)(ii)
1st : the resistance of metal Z is constant / The resistance of metal Y is increasing 2nd : The suitable material to be used as filament of the bulb is metal Y 3rd : resistance increases as the temperature increases 4th : the higher the resistance the brighter the bulb. 1st : The cross-sectional area is small 2nd : because it can release more heat/ resistance is higher 3rd : Melting point is high 4th : so it cannot be melt easily at high temperature. 5th : The specific heat capacity is low 6th : so it can release heat in a shorter time 7th : length of the heating element is long 8th : it can be shaped as a coil and release more heat. 1st : The best heating element is L 2nd : It has a small cross-sectional area, high melting point, low specific heat capacity and long.
1
4
8
2
(c) (i)
(c) (ii)
1
1 1 1 R 3 3 R 1.5
1
2 )6 4 V 2 1 V 2 42 2 2 P = I R (2) (2) / P = R 2 =8W I2
6 2A / 3
1
V= (
1 1
TOTAL 20 12(a)
Buoyant force is an upward force resulting from an object being wholly or partially immerse in fluid.
(b)
1st : When the ballast tank is filled with water, 2nd: The buoyant force is smaller than the weight of the submarine. It will sink/submerges rd 3 : When the ballast tank is filled with air / when the water pumps out, 4th : the buoyant force is larger than the weight of the submarine, and it will float.
1
4
(c)
1st : Horizontal cross section: front side is narrow and pointed 2nd : reduce the water resistance 3rd : The hull material is made of aluminium 4th : It is lighter and strong 5th : Hull ability : hydrodynamic 6th : The ability to withstand shock waves, weather collisions and groundings. 7th : Fuel used is diesel 8th : The cost is cheaper 9th : The best watercraft is Q 10th : because the horizontal cross section of front side is narrow and pointed, the hull material is made of aluminium, the hull ability is hydrodynamic and the fuel used is diesel.
1 1 1 1 1 1 1 1 1 1
(d)(i)
W = mg = (200) (10) = 2000 N
1 1
(d)(ii)
W (boat) + W(load) = ρVg 2000 + W = (1000) (4) (10) W = 38 000 N m = 3,800 kg
1 1 1 TOTAL 20
END OF MARKING SCHEME
Marking Scheme K3 Fizik Peperiksaan Percubaan SPM 2008 No 1
Marking Criteria (a)
(b)
Mark 1
(i)
Mass//m
(ii)
Temperature// θ2 //Δθ
1
(iii)
Type of liquid// time
1
m/g
1/m/g-1
θ2/0C
Δθ/0C
50 100 150 200 250
0.020 0.010 0.007 0.005 0.004
46.0 38.0 35.5 34.0 33.0
16.0 8.0 5.5 4.0 3.0
1. label for all the quantities 2. state the unit for m, 1/m, θ2 and Δθ 3. all value for 1/m correct 4. all value for θ2 correct 5. all value for Δθ correct 6. value for 1/m, θ2, and Δθ consistent decimal point (c)
(d) (e)
1. Δθ at axis-y and at 1/m axis-x 2 correct unit for both axes 3. suitable scale – both axes start from zero and uniform scale 4. all the values plotted correctly 5 or 4 values plotted correctly 5. best straight line 6. size – min scale (10 x 8 ) cm 7 ticks 5-6 ticks 3-4 ticks 2 ticks 1 tick
1 m Stir the water constantly// position of the eye perpendicular to the scale of thermometer
Δθ is directly proportional to
1 1 1 1 1 1 Total 6 √ √ √√ √ √ √ 5 4 3 2 1 Total 5 1 1
No 2
Total 16 Mark
Marking Criteria (a)
(i)
A1
1
(ii)
A2
1
(i)
IB = 0
1
(ii)
Ic = 0
1
(c)
IB is directly proportional to IC
1
(d)
Show on the graph
1
64 mA
1
Draw a large triangle min (4 x 5) cm
1
Correct substitution (follow student’s triangle) 80 x 10-3 0.5 x 10-6
1
State the answer without unit 1.6 x 105
1
1. Eyes must be perpendicular to the scale of ammeter
1
2. Switch off the circuit when not taking any reading
1
(b)
(e)
(f)
Total 12
No 3 (a) (b) (c)(i)
Marking Criteria The length of catapult rubber depends on the force
Mark 1
The bigger the force, the longer the extension of the catapult rubber To investigate the relationship between the force and extension of a spring
1
1
(ii)
Manipulated variable : Force Responding variable : Extension 1 Constant variable : Length of the spring//diameter of the spring //type of spring 1
(iii)
Spring, retort stand, ruler, slotted weight
1
(iv) (v)
State a functionable arrangement of the apparatus Measure the initial length of the spring, l1 Put one slotted mass, 20 g/m1 at the end of the spring.
1
(vi)
(vii)
Measure the length of the spring, l2 Calculate extension of the spring, x = l2 – l1 Repeat the experiment for the mass 40 g, 60 g, 80 g, 100 g. (Repeat at least 4 times)
1
1 1
(viii) Tabulate the data Force(N)/Mass(g)
Extension(cm)/Length of the spring (cm)
(ix)
1
1 Plot graph of extension /length of spring against force/mass//graph Extension (cm)
Total 12
Force(N)
No 4 (a) (b) (c)(i) (ii) (iii) (iv)
(v)
Marking Criteria The amount of lifted scrap metal depends on the current The higher the current, the stronger the electromagnetism. To investigate the relationship between the current and the electromagnetism. Manipulated variable : Current Responding variable : Electromagnetism Constant variable : Number of turns Copper wire, soft iron, ammater, rheostat, batteries, pins/paper clips
Mark 1 1 1 1 1 1
State a functionable arrangement of the apparatus
1
(vi) Adjust the rheostat to supply a current, I1 / 0.1A (vii) Count the number of pins/paper clips attract by the electromagnet (viii) Adjust the rheostat for 4 different current 0.2A, 0.3A, 0.4A and 0.5A.(Repeat at least 4 times) Tabulate the data Current(A) Number of pins/paper clips
(ix)
Plot graph of number of pins against current // graph Number of pins
1 1 1
1
1
Total 12
Current(A)