عرض تقديمي من Microsoft Powerpoint جديد.pptx
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−1 1 𝑃11 −2 −4 𝑃21 −1 0 = 0 −1
=Axẋ −1 −2 A= 1 −4 𝐴𝑇 P+PA=-I 𝑃12 𝑃11 + 𝑃22 𝑃21
𝑃12 −1 𝑃22 1
−2 −4
−1 1 𝑃11 −2 −4 𝑃21 −1 0 = 0 −1
=Axẋ −1 −2 A= 1 −4 𝐴𝑇 P+PA=-I 𝑃12 𝑃11 + 𝑃22 𝑃21
𝑃12 −1 𝑃22 1
−2 −4
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