Jp Xii Organic Chemistry (20).pdf

ORGANIC CHEMISTRY

TARGET : JEE (Main + Advanced) 2016 NO. 24

Course : VIJETA (JP)

This DPP is to be discussed in the week (10.08.2015 to 15.08.2015)

DPP No. # 24 (JEE-MAIN) Total Marks : 60

Max. Time : 40 min.

Single choice Objective ('–1' negative marking) Q.1 to Q.20

1.

NaOH

 X , X is :X gS + C2H5I  (A*) C6H5OC2H5

Sol.

3.

(A*) Na2S (B) Sn/HCl It is selective reduction of –NO2 group ;g –NO2 lewg dk p;ukRed vip;u gSA

(D) C6H5I

(C) LiAIH4

(D) All of these (mijksDr

(C) Benzyl chloride

(D) p- aminophenol

(C) csfUty

(D) p- ,ehuksfQukWy

lHkh)

+ CHCl3 + KOH  Product is :

+ CHCl3 + KOH  mRikn (A*) Qsfuy

5.

(C) C6H5OC6H5

X is (X gS)



(A*) Phenyl isocyanide (B) Benzyl amine

4.

[60, 40]

%

(B) C2H5OC2H5

x

2.

(3 marks, 2 min.)

gS %

vkblkslk;ukbM (B) csfUty ,ehu

DyksjkbM

Benzenediazonium chloride on treatment with KCN in presence of copper powder gives : (A) Benzoic acid (B) Aniline (C) Benzene (D*) Benzene carbonitrile csfUty MkbZ,tksfu;e DyksjkbM rkEcs ds pw.kZ dh mifLFkfr esa KCN ds lkFk mipkfjr djus ij nsrk gS (A) csUtksbd vEy (B) ,fuyhu (C) csUthu (D*) csUthu dkcksZukbVªhbZy

%

Reaction of benzenediazonium chloride with alkaline phenol gives an azo dye. This is an example of (A*) Electrophilic subsitution (B) Nucleophilic subsitution (C) Oxidative coupling (D) Free-radical reaction

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csUthu MkbZ,tksfu;e DyksjkbM dh vfHkfØ;k {kkjh; fQukWy ds lkFk djkus ij ,d ,stks jaatd izkIRk gksrk gSA ;g ,d mnkgj.k gS % (A*) bysDVªkWuLusgh izfrLFkkiu (B) ukfHkdLusgh izfrLFkkiu (C) vkWDlhdkjh ;qXeu (D) eqDr&ewyd vfHkfØ;k 6.

The most activated ring is available in :

(A)

in CCl4

(B*)

in dil NaOH

(C)

in dil HCl

(D)

in dil HCl

fuEu esa ls dkSulk ;kSfxd vf/kdre~ lfØ;dkjh oy; j[krk gS % (A) CCl4 esa

(B*) ruq NaOH esa

NaOH

Maximum + I & + M group.

NaOH

vf/kdre + I rFkk + M lewg

Sol.

  

gy

  

7.

(D) ruq HCl esa

Nitrobenzen can be prepared from benzene by using a mixture of conc. HNO 3 and conc. H2SO4. In the mixture, nitric acid acts as a/an (A) Catalyst (B) Reducing agent (C) Acid (D*) Base lkUnz HNO3 vkSj lkUnz H2SO4 ds ,d feJ.k dk mi;ksx dj csUthu ls ukbVªkscsUthu cukrs gSA feJ.k esa ukbfVªd vEy

ds :i esa dk;Z djrk gS % (A) mRizsjd (B) vipk;d 8.

(C) ruq HCl esa

(C) vEy

For the given reaction consider the statement 1,2 and 3 : fuEu vfHkfØ;k dk iz{ks.k djds dFku 1, 2 ,oa 3 dk fu/kkZj.k dhft,

+

(D*) {kkj

%



(I) (II) (1) Presence of –NO 2 group in aromatic ring I will increase the rate of reaction. (2) Presence of –NO2 group in aromatic ring II will increase the rate of reaction. (3) In this reaction a Wheland intermediate ( complex) is formed. (1) ,sjkseSfVd oy; I ij –NO2 lewg dh mifLFkfr vfHkfØ;k dh nj dks c<+krh gSA (2) ,sjkseSfVd oy; II ij –NO2 lewg dh mifLFkfr vfHkfØ;k dh nj dks c<+rh gSA (3) bl vfHkfØ;k esa fOgyS.M e/;orhZ ¼ ladqy½ curk gSA (A) TTT (B) FFF (C*) FTT (D) FTF 9.

Which of the following compounds does not couple with benzenediazonium chloride to form an azo dye ? (A) Phenol (B*) Toluene (C) Aniline (D) -naphthol

fuEu esa ls dkSuls ;kSfxd ,d ,tksjatd ds cukus ds fy;s csUthu Mkb,tksfu;e DyksjkbM ds lkFk ;ksx ugha djrs gS\ (A) fQukWy (B*) VkWywbZu (C) ,uhyhu (D) -uS¶FkkWy Sol.

Toluene is not active enough to couple with diazonium salts.

VkWywbZu] Mkb,tksfu;e yo.kksa ds lkFk ;qXeu ugha djrk gSA Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005 Website : www.resonance.ac.in | E-mail : [email protected] Toll Free : 1800 200 2244 | 1800 258 5555| CIN: U80302RJ2007PTC024029

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10.

In the given reaction sequence the reactant X is

X

Y

Z

fuEu vfHkfØ;k vuqØe esa vfHkdkjd X gksxk :

(A)

(B)

(C)

(D*)

Sol.

11.

The end product of following reaction is :

fuEu vfHkfØ;k dk vfUre mRikn gS %

aq. NaOH (2)

   

(A)

(B)

(C)

(D*)

Sol.

CH3CHO + N2 +

12.

If Y is a yellow solid, then Z is :

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;fn Y ,d ihyk Bksl gS] rks Z gksxk : (A*)

(B)

(C)

(D)

Sol.

13.

Gabriel phthalimide synthesis is used in the preparation of : (A*) Primary amines

(B) Secondary amines

(C) Tertiary amines

(D) Mixture of all the three

xSfczy FkSysekbM la'ys"k.k fdlds fuekZ.k esa mi;ksxh gS % (A*) izkFkfed ,ehu (B) f}rh;d ,ehu (C) r`rh;d ,ehu (D) rhuks dk feJ.k 14.

The final product in the following sequence of reaction is

fuEu vfHkfØ;k vuqØe esa vfUre mRikn gS& NaNO 2 / HCl C6H6 / NaOH C6H5NH2    A    B 273  278 K

(A) C6H5N2Cl 15.

(B) C6H5OH

(C*) C6H5–C6H5

(D) C6H5N = NOH

Identify the end product in the given reaction :

nh xbZ vfHkfØ;k esa vfUre mRikn igpkfu;s % 2H2SO4 NaOH,270C C6H6   A  B

(A)

(C*)

CH2N2    Product is : mRikn

16.

(A)

17.

(B)

(B)

(D)

gS %

(C)

(D*)

The structure of the compound that gives a tribromo derivative on treatment with bromine water is :

fuEu esa ls dkSulk ;kSfxd czksehu ty ds lkFk mipkfjr djus ij VªkbZ czkseks O;qRiUu nsrk gS \

(A*)

(B)

(C)

(D)

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18.

Aniline in a set of reactions yield a product D. The structure of the product D would be : (,fuyhu fuEu vfHkfØ;k vuqØe }kjk mRikn D nsrk gSA mRikn D dh lajpuk D;k gksxh %)

NaNO

CuCN HNO2 2 H2    A    B   D  C   HCl

(A) C6H5CH2NH2

(B) C6H5NHCH2CH3

NaNO

2  

Sol.

19.

Ni

(C) C6H5NHOH H

2  

CuCN

 

HCl

(D*) C6H5CH2OH

HNO

2  

Ni

Diazocoupling reaction in aromatic compounds is an electrophilic substitution reaction. In which of the following reaction the ring subsitution is most suitable for diazocoupling reaction?

,sjkseSfVd ;kSfxdksa esa MkbZ,tks;Xq eu vfHkfØ;k ,d bysDVªkWuLusgh izfrLFkkiu vfHkfØ;k gksrh gSA fuEu esa ls dkSulh vfHkfØ;k esa oy; izfrLFkkiu MkbZ,tks;qXeu vfHkfØ;k ds fy, vf/kd mi;qDr gS\

Sol.

(A)

+

(B)

(C*)

+

(D)

+

+

The aryl diazonium ion (ArN2+ ) functions as electrophile, so presence of electron withdrawing group (–SO3H) increases its electrophilicity. Diazocoupling is possible only in strongly activated rings. ,fjy MkbZ,tksfu;e vk;u (ArN2+ ) bysDVªkWuLusgh dh rjg dk;Z djrs gSA blfy, e– vkd"khZ lewg (–SO3H) dh mifLFkfr

ds dkj.k bldh bysDVªkWuLusfgrk c<+rh gSA MkbZ,tks;qXeu dsoy izcy :i ls lfØ; oy;ksa ds fy;s lEHko gSA

Aq.NaNO2   A , A is :

20.

HCl ( 0C )

(A)

Sol.

(B)

Aq.NaNO2   HCl ( 0C )

A

gS :

(C)

(D*)



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