ORGANIC CHEMISTRY
TARGET : JEE (Main + Advanced) 2016 Course : VIJETA (JP)
NO. 12
Date : 25-05-2015 TEST IN FORMATI ON
DATE : 07.06.2015
CUMULATIVE TEST (CT) - 1 (ADVANCED)
Syllabus : Stereoisomerism & Organic reaction mechanisms-I & II, Cheminfo (Till date)
This DPP is to be discussed in the week (25-05-2015 to 30-05-2015)
DPP No. # 12 (JEE-ADVANCED) Total Marks : 58
Max. Time : 36 min.
Multiple choice objective ('–1' negative marking) Q.1 to Q.5 (4 marks, 2 min.) Comprehension ('–1' negative marking) Q.6 (i to iii) (3 marks, 2 min.) Matching List Type (Only One options correct) ('–1' negative marking) Q.7 (3 marks, 2 min.) Match the Following (no negative marking) Q.8 (8 marks, 6 min.) Integer Type Questions Q.9 to Q.10 (3 marks, 2 min.) ChemINFO : 4 Questions ('–1' negative marking) Q.11 to Q.14 (3 marks, 2 min.)
[20, 10] [09, 06] [03, 02] [08, 06] [06, 04] [12, 08]
1.
out of the followings which one is/ are correct
fuEu esa dkSu ,d ;k vf/kd lgh mÙkj gS
(A*) 1,
Sol.
(B*) 2,
(C*) 3 ,
(D*) 4,
gy-
–M group decreases electron density in benzene ring. –M çHkko cas thu oy; es a bysDVªkW u ?kuRo de dj ns rk gSA
2.
Which factor is responsible for the regioselective nature of the following reaction.
fuEu vfHkfØ;k esa dkSulk xq.k fjft;ksp;ukRed izd`fr ds fy, mÙkjnk;h gSA
Cl / FeCl
3 2
+
(A) – I effect of halogens
(B) + I effect of halogens
(C*) + M effect of halogens
(D) – M effect of halogens
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PAGE NO.- 1
dk – I izHkko (C*) gSykstu dk + M izHkko
dk + I izHkko (D) gSykstu dk – M izHkko
(A) gSykstu Sol.
The + m of Cl stabilizes the intermediate carbocation. Cl dk + m izHkko
3.
(B) gSykstu
e/;orhZ dkcZ/kuk;u dks LFkkbRo iznku djrk gSA
Friedel craft acylation is/are not observed in
fÝMy ØkW¶V ,lhyhdj.k vfHkfØ;k fuEu esa ls fdlesa@fduesa izsf{kr ugha gksrh gSA
(A) 4.
(B*)
(C)
(D*)
In which of following electrophilic aromatic substitution reaction takes place on left hand side phenyl ring.
fuEu esa ls fdlesa bysDVªkWu Lusgh ,sjksesfVd izfrLFkkiu vfHkfØ;k cka;h vksj dh Qsfuy oy; ij gksxhA
5.
(A)
(B*)
(C*)
(D*)
Which of the following electophilic substitution reaction represent correct product.
fuEu esa ls dkSulh bysDVªkWu Lusgh izfrLFkkiu vfHkfØ;k esa lgh mRikn n'kkZ;k x;k gSA
(A*)
(B*)
Br2 / FeBr3
Br2 / FeBr3
Br / FeBr
(C*)
3 2
(D)
Br2 / FeBr3
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PAGE NO.- 2
6.
Comprehension
(i)
In the following sequence of reaction number of electrophilic substitution is : fuEu vfHkfØ;k vuqØe esa] fdruh ckj bysDVªkWuLusgh izfrLFkkiu gksrh gS : (A) 1 (B*) 2 (C) 3 (D) 4 In above reaction sequence, the reaction 1 and 4 are electrophilic substitution. mijksDr vfHkfØ;k vuqØe esa] vfHkfØ;k 1 rFkk 4 bysDVªkWuLusgh izfrLFkkiu gSA
Sol.
(ii)
vuqP Nsn
W hat product will be obtained if 'W ' is treated with C 6H 5MgBr followed by D 3O +? ;fn 'W ' dks C6H5MgBr ds lkFk mipkfjr djkdj D3O+ ds lkFk vfHkfØ;k djkus ij fuEu esa
ls dkSulk mRikn cukrk
gS A (A)
(B)
(C*)
(D)
Ans.
(iii).
W hat product is obtained when R is reacted with KMnO 4 / H + ? R dks KMnO4 / H + ds lkFk vfHkfØ;k djkus ij iz kIr mRikn D;k gks xkA
(A)
Ans.
(B)
(C)
(D*)
KMnO / H
4
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PAGE NO.- 3
7.
Match List I (Group when attached to phenyl ring) with List II (Effect shown) and select the correct answer using the code given below the lists :
lwph I (tc lewg cSUthu oy; ij gks) dks lwph II ¼izHkko½ ls lqesfyr dhft, rFkk lwfp;ksa ds uhps fn;s x;s dksM dk iz;ksx djds lgh mRrj pqfu;s : List I
lwph I
List II (1)
+m&+I
–O
(2)
+m&–I
(R)
–CH2–CH3
(3)
dsoy only – I
(S)
– NH3
(4)
+ I & Hyperconjugation (vfrla;qXeu)
(P)
–Cl
(Q)
Codes
8.
lwph II
¼dksM½ : P
Q
R
S
(A)
1
3
2
4
(C)
4
2
3
1
Match the column-I with column-II : dkWye-I dks dkWye-II ls lqesfyr dhft, % Column-I dkWy e-I (A)
P
Q
R
S
(B)
3
4
2
1
(D*)
2
1
4
3
Column-II dkW ye -II (p) Gives Benzoic acid with hot alkaline KMnO 4
xje {kkjh; KMnO4 ds lkFk csUtksbd vEy nsrk gS (B)
(q) o/p directing and activating for electrophile o/p funsZ'kkadh
(C)
gS vkSj E ds fy;s lfØ; gS
(r) Gives fastest reaction with an electrophile
bysDVªkWu Lusgh ds lkFk rhoz vfHkfØ;k nsrk gSA
(D)
(s) Gives an ester on reductive ozonolysis
vipf;r vkstksuhdj.k ij ,LVj nsrk gSA Ans
(A) q, r, s
(B) p, q
(C) p, q
(D) p
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PAGE NO.- 4
9.
Complete the following reaction
fuEu vfHkfØ;k dks iw.kZ dhft,s& Br / Fe (1 eq.)
2
HNO / H SO (1 eq.)
4 3 2
At which position nitration takes place ?
dkSulh fLFkfr ij ukbVªhdj.k gksrk gSA Ans.
4
Sol.
10. Ans.
Sol.
How many substituted phenol are possible by the molecular formula C 8H 10O. v.kqlw=k C8H10O ds fdrus izfrLFkkih fQukWy lEHko gS\ 9
,
,
,
,
,
,
,
Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005 Website : www.resonance.ac.in | E-mail :
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PAGE NO.- 5
ChemINFO-1.6
Oxidation Oxidative Cleavage of vic. diol
Daily Self-Study Dosage for mastering Chemistry
Periodic acid (HIO4) or Lead tetra acetate (LTA) has action on those organic molecules which follows following structural similarity.
(i)
(ii)
(iii)
Note : 1. In cyclic 1,2-diol only cis-diol are oxidised. Trans diol are not oxidised easily. 2. Number of moles of HIO 4 = number of bonds cleaved. General Reactions : HIO 4
HIO 4
HIO 4
HIO 4
Ex.1
Ex.2
Ex.3
HIO 4
HIO 4 HCHO +
HIO 4
Ex.4
Ex.5
HIO 4
Ex.6
HIO 4
Memorize this theory as soon as you get the DPP. Revise it regularly and master this concept by practice. Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005 Website : www.resonance.ac.in | E-mail :
[email protected] Toll Free : 1800 200 2244 | 1800 258 5555| CIN: U80302RJ2007PTC024029
PAGE NO.- 6
11.
W hich of the following compound is resistant to periodic acid oxidation ?
(A)
12.
(B*)
(C)
(D)
Which of the following will be oxidised by HIO4 (I)
(II)
(III)
(IV)
(A) I, II, III
(B) I, III, IV
(C*) I, II, IV
(D) II, III, IV
(C)
(D)
13.
Product Product is -
(A*)
14.
(B)
HIO 4 Products ; Products are :
(A) HCHO + CH3CHO + CH3COOH
(B) HCHO + HCOOH + CH3–CHO
(C) HCHO + HCOOH + CH3–COOH
(D*) HCHO + CO2 + CH3–CHO
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PAGE NO.- 7
ChemINFO-1.6
Oxidation Oxidative Cleavage of vic. diol
Daily Self-Study Dosage for mastering Chemistry
ijvk;ksfMd vEy (HIO4) vkSj ysM VsVªk ,lhVSV (LTA) mu dkcZfud v.kqvksa ij fØ;k djrk gS ftudh lajpuk fuEufyf[kr v.kqvksa dh lajpuk ds leku gksrh gSA (i)
(ii)
Note : 1. pfØ; 1,2-MkbZvkWy
(iii)
esa dsoy lei{k&MkbZvkWy dk gh vkWDlhdj.k gksrk gSA foi{k&MkbZvkWy dk vklkuh ls vkWDlhdj.k ugha gks ikrk gSA
2. HIO4 ds
eksyksa dh la[;k = fonfyr ca/kksa dh la[;k lkekU; vfHkfØ;k,as: HIO 4
HIO 4
HIO 4
HIO 4
Ex.1
Ex.2
Ex.3
HIO 4
HIO 4 HCHO +
HIO 4
Ex.4
Ex.5
HIO 4
Ex.6
HIO 4
Memorize this theory as soon as you get the DPP. Revise it regularly and master this concept by practice. Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005 Website : www.resonance.ac.in | E-mail :
[email protected] Toll Free : 1800 200 2244 | 1800 258 5555| CIN: U80302RJ2007PTC024029
PAGE NO.- 8
11.
fuEu esa ls dkSuls ;kSfxd dk ijvk;ksfMd vEy ds }kjk vkWDlhdj.k ugha gksrk gS ?
(A)
12.
(B*)
(C)
(D)
fuEu esa ls dkSulk ;kSfxd HIO4 }kjk vkWDlhd`r ugha gksrs gSA (I)
(II)
(III)
(IV)
(A) I, II, III
(B) I, III, IV
(C*) I, II, IV
(D) II, III, IV
(C)
(D)
13.
mRikn
mRikn gS -
(A*)
(B)
HIO 4 mRikn
14.
mRikn gS : (A) HCHO + HCHO + CH3–CHO
(B) HCHO + HCOOH + CH3–CHO
(C) HCHO + CH3CHO + CH3COOH
(D*) HCHO + CO2 + CH3–CHO
Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005 Website : www.resonance.ac.in | E-mail :
[email protected] Toll Free : 1800 200 2244 | 1800 258 5555| CIN: U80302RJ2007PTC024029
PAGE NO.- 9