Jan 2005 U1

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GCE Edexcel GCE Biology / Biology (Human) (6101)

January 2005

Biology / Biology (Human) (6101)

Edexcel GCE

Mark Scheme

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

General Principles Symbols used in the mark scheme Symbol ; semi colon eq / oblique {} curly brackets () round brackets [] square brackets

Meaning of symbol Indicates the end of a marking point. Indicates that credit should be given for other correct alternatives to a word or statement, as discussed in the Standardisation meeting. It is used because it is not always possible to list every alternative answer that a candidate may write that is worthy of credit. Words or phrases separated by an oblique are alternatives to each other. Indicate the beginning and end of a list of alternatives (separated by obliques) where necessary to avoid confusion. Words inside round brackets are to aid understanding of the marking point but are not required to award the point. Words inside square brackets are instructions or guidance for examiners.

Crossed out work If a candidate has crossed out an answer and written new text, the crossed out work can be ignored. If the candidate has crossed out work but written no new text, the crossed out work for that question or part question should be marked, as far as it is possible to do so. Spelling and clarity In general, an error made in an early part of a question is penalised when it occurs but not subsequently. The candidate is penalised once only and can gain credit in later parts of the question by correct reasoning from the earlier incorrect answer. No marks are awarded specifically for quality of language in the written papers, except for the essays in the synoptic paper. Use of English is however taken into account as follows: • the spelling of technical terms must be sufficiently correct for the answer to be unambiguous e.g. for amylase, ‘ammalase’ is acceptable whereas ‘amylose’ is not e.g. for glycogen, ‘glicojen’ is acceptable whereas ‘glucagen’ is not e.g. for ileum, ‘illeum’ is acceptable whereas ‘ilium’ is not e.g. for mitosis, ‘mytosis’ is acceptable whereas ‘meitosis’ is not • candidates must make their meaning clear to the examiner to gain the mark. • a correct statement that is contradicted by an incorrect statement in the same part of an answer gains no mark – irrelevant material should be ignored.

Page 2

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 1

Maximum mark

Name of biological molecule

Smaller molecules from which it is made Fatty acids and glycerol ;

Cellulose / polysaccharide / disaccharide ;

Name of bond joining the smaller molecules Ester ; (1, 4) Glycosidic ; Peptide ; Total 5 marks

Page 3

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 2

Maximum mark

Nuclear {membrane / envelope} / nucleolus ; Centrioles ; Metaphase ; Centromeres / kinetochore / chromosome ; Anaphase ; 5 marks

Page 4

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 3

Maximum mark

(a) (i)

Hydrogen ; Ionic ; Disulphide ; 2 marks

(ii)

It has two (polypeptide) chains / an A and a B chain / more than one (polypeptide) chain ; 1 mark

(b) (i)

{Sequence / order} of amino acids ; 1 mark

(ii) 1. Reference to bonds between R groups ; 2. The R groups are always in the same position ; 3. {Bonds / named bonds} will always form in the same place ; 4. Reference to {hydrophilic groups on outside / hydrophobic groups on inside} ; 2 marks Total 6 marks

Page 5

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 4

Maximum mark

(a) (i)

A

Flagellum ;

B

DNA / bacterial chromosome ; 2 marks

(ii)

Glycogen ; 1 mark

(iii)

Made of {peptidoglycan / murein} / does not contain cellulose ; 1 mark

(b)

Correct measurement: {80 / 81} mm ; Correct division: ÷ 6000 ; Correct conversion to µm ; [Only award all 3 marks if answer is correct: 13.3 / 13.5] 3 marks Total 7 marks

Page 6

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 5

Maximum mark

(a) (i)

(Inner) membrane of mitochondrion {is folded / forms cristae} ; (Inner) membrane of mitochondrion has {ATPase / stalked particles / electron carriers} ; Nuclear membrane has pores ; (Outer) nuclear membrane is continuous with the endoplasmic reticulum ; (Outer) nuclear membrane has ribosomes ; 2 marks

(ii)

Chloroplast ; 1 mark

(b)

1. Cylindrical ; 2. Occur in pairs ; 3. Lie at 90˚ to each other ; 4. Made of microtubules ; 5. Arranged in {triplets / nine groups} ; [Maximum 2 marks from marking points 1-5] 6. Reference to spindle formation / organisation ; 7. Reference to {microtubule organising centre / assembling the tubulin} ; 3 marks Total 6 marks

Page 7

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 6

Maximum mark

(a)

(Fluid because) phospholipids move (around membrane) ; (Mosaic because) membrane contains {proteins / glycoproteins} (amongst phospholipids) ; 2 marks

(b)

(c)

To remove the red pigment released by the cells {cut open / damaged} during preparation ; 1 mark

1. (Increasing bile salt concentration) results in increase of red coloration ; 2. No further increase in red coloration {between 1.6% and 2.0% / after 1.6%} ; 3. Reference to linear relationship between red coloration and bile salt concentration up to 0.6% ; 4. Reference to change in gradient after 0.6% ; 5. Manipulation of figures to compare gradients before and after 0.6 % ; 3 marks

(d)

1. Disruption of membrane by bile salts increases its permeability ; 2. Bile salts may emulsify lipids (within membrane) ; 3. Proteins (in membrane) may be affected ; 4. Pigment leaks through (plasma) membrane ; 5. Pigment leaks through vacuole membrane ; 6. By diffusion ; 7. More bile salts, {more cells break down / more membrane disrupted} ; 8. Reference to plateau as all cells have lost pigment / all membranes disrupted ; 9. Reference to plateau as there is no longer a diffusion gradient ; 4 marks

Page 8

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 6 continued (e)

Maximum mark

Any ONE of the following regarding Beetroot 2: was different age was stored under warmer conditions was stored in different conditions had more cells damaged during preparation had discs with skin still on them had discs taken from a different region of the beetroot was different species contained different concentrations of pigment was grown in different conditions 1 marks Total 11 marks

Page 9

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 7

Maximum mark

(a)

Ring drawn around one phosphate, one sugar and one base (linked together) ; 1 mark

(b)

1. Part of the DNA molecule unwinds ; 2. DNA strands {separate / unzips / H-bonds break} ; 3. (Mono)nucleotides line up against their complementary bases ; 4. Against {sense / one} strand ; 5. Reference to RNA polymerase ; 6. Individual mononucleotides join up by {condensation reactions / (phosphodi)ester bonds} ; 7. mRNA strands separate from DNA molecule ; 8. mRNA migrates into cytoplasm / eq ; 5 marks

(c) (i)

Ribosomes / rough endoplasmic reticulum ; 1 mark

(ii)

Ring drawn around U C G ; 1 mark Total 8 marks

Page 10

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 8

Maximum mark

(a)

Clarifying {wines / vinegar / fruit juices} / improves colour extraction from fruit skins / peeling fruit skins ; 1 mark

(b) (i)

Same concentration of enzyme ; Same pH ; Same time for incubation ; Same {type / age} apple ; Same temperature for filtering ; Standardisation of apple chopping ; 2 marks

(ii)

The line goes up / rate increases ; Because of increase in {kinetic energy / collisions} ; Reference to optimum at 40 ˚C ; 2 marks

(iii)

{Rate of production / line} decreases ; Because bonds break ; Therefore the active site changes shape / reference to denaturing of enzyme ; Substrate will not fit / enzyme-substrate complex will not form ; Enzyme is denatured at 60 °C ; Reference to optimum at 40 °C ; [only allow once, either here or in (b)(ii)] 3 marks

Page 11

6101 January 2005

January 2005

GCE Biology / Biology (Human) Unit 1 - 6101

Question 8 continued (c) (i)

Mixture D

Maximum mark Line drawn between A and B ; Line levels out at the same maximum as curves A, B and C ; 2 marks

(ii) 1. The results show that the rate of reaction depends on the relative concentrations of inhibitor and substrate / {B / C} have similar shape curve to A ; 2. Faster intial rate at lower concentration of inhibitor ; 3. {B / C} give the same yield {as A / when no inhibitor present} ; 4. This shows the inhibitor must be competitive ; 5. Will be binding to active site ; 6. Doesn’t stop the reaction completely ; 2 marks Total 12 marks

Page 12

6101 January 2005

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