Additional Heat Loads of Apple: Insulation of Door:
Metaflex MAK Chiller; 3.15β Polyutherane 1 1 π₯1 1 + + ππ π1 ππ 1 ππ«πππ = 1 3.15 1 6 + 2.9 + 1.65 π΅ππ ππ·πππ = 0.5379 βπ β ππ‘ 2 β β Area of Door: π΄ππππ = πΏππππ ππ·πππ = 13β x 9.84β = 127.92 ππ‘ 2 ππ·πππ =
ππ·πππ = ππ΄βπ‘ = (π. ππππ
π©π»πΌ π΅ππ ) (πππ. ππ ππ‘ 2 )(68 β 30 β) = 2,614.7104 π ππ β ππ β β βπ
Insulation of Walls of the Apple Room : 4β concrete (sand and gravel) + 7β cork board (dense) + 4β concrete (sand and gravel) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 4 7 4 1 6 + 12 + 0.32 + 12 + 1.65 π΅ππ = 0.04289 βπ β ππ‘ 2 β β
πππππ = πππππ πππππ
ππππ‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 15β² = 196.8 ππ‘ 2 πππ = ππ΄βπ‘ =(196.8 ππ‘ 2 ) (0.04289
π΅ππ ) (68 β βπβππ‘ 2 ββ
30 β) = 320. 7486
π΅ππ βπ
πππ’π‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 2β² = 26.24 ππ‘ 2 πππ = ππ΄βπ‘ =(26.24 ππ‘ 2 ) (0.04289
π΅ππ ) (73.4 β βπβππ‘ 2 ββ
30 β) = 48.8438
π΅ππ βπ
πΈππ π‘ ππππ: π΄πΈπ = πΏπΈπ ππΈπ = 13.12β² π₯ 32β² = 419.84 ππ‘ 2 ππΈπ = ππ΄βπ‘ =(419.84 ππ‘ 2 ) (0.04289
π΅ππ ) (73.4 β βπβππ‘ 2 ββ
30 β) = 781.5011
π΅ππ βπ
πππ π‘ ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 32β² = 419.84 ππ‘ 2 πππ = ππ΄βπ‘ =(419.84 ππ‘ 2 ) (0.04289
π΅ππ ) (40 βπβππ‘ 2 ββ
πππ = πππππ + πππ + ππΈπ + πππ + πππ π΅ππ π΅ππ πππ = 320. 7486 + 48.8438 + 781.5011 βπ
πππ = 3,945.8733
βπ
β 30 β) = 180.0694
π΅ππ βπ
+ 180.0694
π΅ππ βπ
π΅ππ βπ
+ 2,614.7104
π΅ππ βπ
Insulation of Floors of the Apple Room : Hollow clay 4β + 3β concrete + 6β cork board (dense) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 1 4 6 1 6 + 1 + 12 + 0.32 + 1.65 π΅ππ = 0.04795 βπ β ππ‘ 2 β β
ππΉππππ = ππΉππππ ππΉππππ
π΄πΉππππ = πΏπΉππππ ππΉππππ = 32β² π₯ 15β² = 480 ππ‘2 ππΉππππ = ππ΄βπ‘ =(480 ππ‘ 2 ) (0.04795
π΅ππ ) (68 β βπβππ‘ 2 ββ
30 β) = 874.608
Insulation of Roof of the Apple Room : Wood 25/32β fiber boards + 6β cork board (dense) 1 1 π₯1 π₯2 1 + + + ππ π1 π2 ππ 1 = 25 1 6 1 32 6 + 0.33 + 0.32 + 1.65
ππ
πππ = ππ
πππ
π΅ππ βπ
π΅ππ βπ
π΅ππ βπ = πΏπ
πππ ππ
πππ = 32β² π₯ 15β² = 480 ππ‘2
ππ
πππ = 0.04568
π΄π
πππ
ππ
πππ = ππ΄βπ‘ =(480 ππ‘ 2 ) (0.04568
π΅ππ ) (68 β βπβππ‘ 2 ββ
30 β) = 833.2032
π΅ππ βπ
Amount of lights in a Room: Average amount of lights in a room 20 fc (footcandles): Amount of illumination of an average 10 watt LED cold storage room bulb: 1040 lm No. of lights required: ππΏππβπ‘π =
(π΄πππ ππ π
πππ)(π΄π£π. πΉπππ‘πππππππ ) (πΏπ’ππππ ππ π΅π’ππ) β² 2
π΄πΉππππ = πΏπΉππππ ππΉππππ = 32β² π₯ 15 = 480 ππ‘
(480 ππ‘ 2 )(20ππ) = 9.2308 β 10 ππ’πππ ππ (1040 ) ππ’ππ ππ πΈπππππππππ¦ ππ ππ’ππ: π = 303 π ππΏππβπ‘π =
ππΏππβπ‘π ππΏππβπ‘π
ππ π΅ππ 3.412142 (ππππβπ‘π )(πΏπ’ππππ ππ ππ’ππ) 10 ππ’πππ π₯ 1040 ππ’ππ βπ = = = 34. 3234 π π₯ ππ ππππππππππ¦ ππ ππ’ππ 1π 303 π π΅ππ = 117. 1163 βπ
π΄πππ’ππ‘ ππ π»πππ‘ π·ππ π ππππ‘ππ ππ πΉπππππππ‘: πΉπππππππ‘ πππ πππππ’ππ 36920 πΎπ½ πππ‘ππ π€ππππππ πππ 8 βππ’ππ . π΄π π π’ππππ π‘βππ‘ π‘βπ ππππππππ‘ ππ π€ππππππ 12 βππ’ππ . πβπ’π ππ‘ πππππ’πππ 55380 πΎπ½ ππ βπππ‘ ππ£πππ¦ 12 βππ’ππ ππ π€ππππππ. 55380 πΎπ½ 1 π΅ππ ππΈππ’ππππππ‘ = π₯ 12 βππ’ππ β ππππππππ‘ππ 1.055 πΎπ½ π΅ππ ππΈππ’ππππππ‘ = 26246.4 βπ
Total Heat Gain of Apple: πππ‘ππ π»πππ‘ π·ππ π ππππ‘ππ ππ¦ π ππππ ππ: πππππ ππ = 246.5013
π΅ππ βπ
ππ΄ππππ = πππ + ππΉππππ + ππ
πππ + ππππππ + ππΏππβπ‘π + πππππ ππ + ππΈππ’ππππππ‘ ππ΄ππππ = 3,945.8733 + 874.608 + 833.2032 + 318,328.5417 + 117. 1163 + 246.5013 + 26,246.4 ππ΄ππππ = 350, 592.2438
π΅ππ ππππ π₯ = 29.2160 Tons π΅ππ βπ 12,000 βπ
Additional Heat Loads of Orange: Insulation of Door:
Metaflex MAK Chiller; 3.15β Polyutherane 1 1 π₯1 1 + + ππ π1 ππ 1 ππ«πππ = 1 3.15 1 6 + 2.9 + 1.65 π΅ππ ππ·πππ = 0.5379 βπ β ππ‘ 2 β β Area of Door: π΄ππππ = πΏππππ ππ·πππ = 13β x 9.84β = 127.92 ππ‘ 2 ππ·πππ =
ππ·πππ = ππ΄βπ‘ = (π. ππππ
π©π»πΌ ) (πππ. ππ ππ‘ 2 )(68 β ππβπππ ββ
30 β) = 2,614.7104
π΅ππ βπ
Insulation of Walls of the Orange Room : 4β concrete (sand and gravel) + 7β cork board (dense) + 4β concrete (sand and gravel) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 4 7 4 1 + + + + 6 12 0.32 12 1.65 π΅ππ = 0.04289 βπ β ππ‘ 2 β β
πππππ = πππππ πππππ
ππππ‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 15β² = 196.8 ππ‘ 2
πππ = ππ΄βπ‘ =(196.8 ππ‘ 2 ) (0.04289
π΅ππ ) (68 β βπβππ‘ 2 ββ
30 β) = 320. 7486
π΅ππ βπ
πππ’π‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 2β² = 26.24 ππ‘ 2 πππ = ππ΄βπ‘ =(26.24 ππ‘ 2 ) (0.04289
π΅ππ ) (73.4 β βπβππ‘ 2 ββ
30 β) = 48.8438
π΅ππ βπ
πΈππ π‘ ππππ: π΄πΈπ = πΏπΈπ ππΈπ = 13.12β² π₯ 32β² = 419.84 ππ‘ 2 ππΈπ = ππ΄βπ‘ =(419.84 ππ‘ 2 ) (0.04289
π΅ππ ) (40 βπβππ‘ 2 ββ
β 40 β) = 0
π΅ππ βπ
πππ π‘ ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 32β² = 419.84 ππ‘ 2 πππ = ππ΄βπ‘ =(419.84 ππ‘ 2 ) (0.04289
π΅ππ ) (40 βπβππ‘ 2 ββ
β 30 β) = 180.0694
πππ = πππππ + πππ + ππΈπ + πππ + πππ π΅ππ π΅ππ π΅ππ πππ = 320. 7486 βπ + 48.8438 βπ + 0 βπ + 180.0694 πππ = 3,164.3722
π΅ππ βπ
π΅ππ βπ
+ 2,614.7104
π΅ππ βπ
Insulation of Floors of the Orange Room : Hollow clay 4β + 3β concrete + 6β cork board (dense) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 1 4 6 1 6 + 1 + 12 + 0.32 + 1.65 π΅ππ = 0.04795 βπ β ππ‘ 2 β β
ππΉππππ = ππΉππππ ππΉππππ
π΄πΉππππ = πΏπΉππππ ππΉππππ = 32β² π₯ 15β² = 480 ππ‘2 ππΉππππ = ππ΄βπ‘ =(480 ππ‘ 2 ) (0.04795
π΅ππ ) (68 β βπβππ‘ 2 ββ
30 β) = 874.608
π΅ππ βπ
Insulation of Roof of the Orange Room : Wood 25/32β fiber boards + 6β cork board (dense) 1 1 π₯1 π₯2 1 + + + ππ π1 π2 ππ 1 ππ
πππ = 25 1 6 1 + 32 + + 6 0.33 0.32 1.65 π΅ππ ππ
πππ = 0.04568 βπ π΄π
πππ = πΏπ
πππ ππ
πππ = 32β² π₯ 15β² = 480 ππ‘2 ππ
πππ =
ππ
πππ = ππ΄βπ‘ =(480 ππ‘ 2 ) (0.04568
π΅ππ ) (68 β βπβππ‘ 2 ββ
30 β) = 833.2032
π΅ππ βπ
π΅ππ βπ
Amount of lights in a Room: Average amount of lights in a room 20 fc (footcandles): Amount of illumination of an average 10 watt LED cold storage room bulb: 1040 lm No. of lights required: ππΏππβπ‘π =
(π΄πππ ππ π
πππ)(π΄π£π. πΉπππ‘πππππππ ) (πΏπ’ππππ ππ π΅π’ππ) β² 2
π΄πΉππππ = πΏπΉππππ ππΉππππ = 32β² π₯ 15 = 480 ππ‘
(480 ππ‘ 2 )(20ππ) = 9.2308 β 10 ππ’πππ ππ (1040 ) ππ’ππ ππ πΈπππππππππ¦ ππ ππ’ππ: π = 303 π ππΏππβπ‘π =
ππΏππβπ‘π ππΏππβπ‘π
ππ π΅ππ 3.412142 (ππππβπ‘π )(πΏπ’ππππ ππ ππ’ππ) 10 ππ’πππ π₯ 1040 ππ’ππ βπ = = = 34. 3234 π π₯ ππ ππππππππππ¦ ππ ππ’ππ 1π 303 π π΅ππ = 117. 1163 βπ
π΄πππ’ππ‘ ππ π»πππ‘ π·ππ π ππππ‘ππ ππ πΉπππππππ‘: πΉπππππππ‘ πππ πππππ’ππ 36920 πΎπ½ πππ‘ππ π€ππππππ πππ 8 βππ’ππ . π΄π π π’ππππ π‘βππ‘ π‘βπ ππππππππ‘ ππ π€ππππππ 12 βππ’ππ . πβπ’π ππ‘ πππππ’πππ 55380 πΎπ½ ππ βπππ‘ ππ£πππ¦ 12 βππ’ππ ππ π€ππππππ. 55380 πΎπ½ 1 π΅ππ ππΈππ’ππππππ‘ = π₯ 12 βππ’ππ β ππππππππ‘ππ 1.055 πΎπ½ ππΈππ’ππππππ‘ = 26,246.4
π΅ππ βπ
Total Heat Gain of Orange: πππ‘ππ π»πππ‘ π·ππ π ππππ‘ππ ππ¦ π ππππ ππ: πππππ ππ = 246.5013
π΅ππ βπ
πππππππ = πππ + ππΉππππ + ππ
πππ + πππππππ + ππΏππβπ‘π + πππππ π + ππΈππ’ππππππ‘ πππππππ = 3,945.8733 + 874.608 + 833.2032 + 52,500 + 117. 1163 + 246.5013 + 26,246.4 πππππππ = 85, 600.3101
π΅ππ βπ
π₯
ππππ π΅ππ βπ
12,000
= 7.1334 Tons
Additional Heat Loads of Avocado: Insulation of Door:
Metaflex MAK Chiller; 3.15β Polyutherane 1 1 π₯1 1 + + ππ π1 ππ 1 ππ«πππ = 1 3.15 1 + + 6 2.9 1.65 π΅ππ ππ·πππ = 0.5379 βπ β ππ‘ 2 β β Area of Door: π΄ππππ = πΏππππ ππ·πππ = 13β x 9.84β = 127.92 ππ‘ 2 ππ·πππ =
ππ·πππ = ππ΄βπ‘ = (0.5379
π΅ππ ) (127.92 ππ‘ 2 )(68 β βπβππ‘ 2 ββ
30 β) = 2,614.7104
π΅ππ βπ
Insulation of Walls of the Avocado Room : 4β concrete (sand and gravel) + 7β cork board (dense) + 4β concrete (sand and gravel) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 4 7 4 1 6 + 12 + 0.32 + 12 + 1.65 π΅ππ = 0.04289 βπ β ππ‘ 2 β β
πππππ = πππππ πππππ
ππππ‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 28β² = 367.36 ππ‘ 2 πππ = ππ΄βπ‘ =(367.36 ππ‘ 2 ) (0.04289
π΅ππ ) (68 βπβππ‘ 2 ββ
β 30 β) = 598.7307
πππ’π‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 15β² = 196.8 ππ‘ 2
π΅ππ βπ
πππ = ππ΄βπ‘ =(196.8 ππ‘ 2 ) (0.04289
π΅ππ ) (73.4 β βπβππ‘ 2 ββ
30 β) = 366.3286
π΅ππ βπ
πΈππ π‘ ππππ: π΄πΈπ = πΏπΈπ ππΈπ = 13.12β² π₯ 32β² = 419.84 ππ‘ 2 ππΈπ = ππ΄βπ‘ =(419.84 ππ‘ 2 ) (0.04289
π΅ππ ) (40 βπβππ‘ 2 ββ
β 39.93 β) = 1.2605
π΅ππ βπ
πππ π‘ ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 32β² = 419.84 ππ‘ 2 πππ = ππ΄βπ‘ =(419.84 ππ‘ 2 ) (0.04289
π΅ππ ) (40 βπβππ‘ 2 ββ
πππ = πππ + πππ + πππ + ππΈπ + ππ·πππ πππ = 598.7307 πππ
π΅ππ βπ
+ 366.3286 π΅ππ = 3,581.0302 βπ
π΅ππ βπ
+ 1.2605
π΅ππ βπ
β 40β) = 0
+ 0
π΅ππ βπ
π΅ππ βπ
+ 2,614.7104
π΅ππ βπ
Insulation of Floors of the Avocado Room : Hollow clay 4β + 3β concrete + 6β cork board (dense) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 1 4 6 1 6 + 1 + 12 + 0.32 + 1.65 π΅ππ = 0.04795 βπ β ππ‘ 2 β β
ππΉππππ = ππΉππππ ππΉππππ
π΄πΉππππ = πΏπΉππππ ππΉππππ = 32β² π₯ 28β² = 896 ππ‘2 ππΉππππ = ππ΄βπ‘ =(896 ππ‘ 2 ) (0.04795
π΅ππ ) (68 β βπβππ‘ 2 ββ
40 β) = 1,202.9696
π΅ππ βπ
Insulation of Roof of the Avocado Room : Wood 25/32β fiber boards + 6β cork board (dense) ππ
πππ =
1
1 π₯1 π₯2 1 + + + ππ π1 π2 ππ 1 ππ
πππ = 25 1 6 1 32 6 + 0.33 + 0.32 + 1.65 π΅ππ ππ
πππ = 0.04568 βπ π΄π
πππ = πΏπ
πππ ππ
πππ = 32β² π₯ 28β² = 896 ππ‘2 ππ
πππ = ππ΄βπ‘ =(896 ππ‘ 2 ) (0.04568
π΅ππ ) (68 β βπβππ‘ 2 ββ
40 β) = 1,146.0198
π΅ππ βπ
Amount of lights in a Room: Average amount of lights in a room 20 fc (footcandles): Amount of illumination of an average 10 watt LED cold storage room bulb: 1040 lm No. of lights required: ππΏππβπ‘π =
(π΄πππ ππ π
πππ)(π΄π£π. πΉπππ‘πππππππ ) (πΏπ’ππππ ππ π΅π’ππ) 2 β²
π΄πΉππππ = πΏπΉππππ ππΉππππ = 32β² π₯ 28 = 896 ππ‘
(896 ππ‘ 2 )(20ππ) = 17.2308 β 18 ππ’πππ ππ (1040 ) ππ’ππ ππ πΈπππππππππ¦ ππ ππ’ππ: π = 303 π ππΏππβπ‘π =
ππΏππβπ‘π ππΏππβπ‘π
ππ π΅ππ 3.412142 (ππππβπ‘π )(πΏπ’ππππ ππ ππ’ππ) 18 ππ’πππ π₯ 1040 ππ’ππ βπ = = = 61.7822 π π₯ ππ ππππππππππ¦ ππ ππ’ππ 1π 303 π π΅ππ = 210.8096 βπ
π΄πππ’ππ‘ ππ π»πππ‘ π·ππ π ππππ‘ππ ππ πΉπππππππ‘: πΉπππππππ‘ πππ πππππ’ππ 36920 πΎπ½ πππ‘ππ π€ππππππ πππ 8 βππ’ππ . π΄π π π’ππππ π‘βππ‘ π‘βπ ππππππππ‘ ππ π€ππππππ 12 βππ’ππ . πβπ’π ππ‘ πππππ’πππ 55380 πΎπ½ ππ βπππ‘ ππ£πππ¦ 12 βππ’ππ ππ π€ππππππ. 55380 πΎπ½ 1 π΅ππ ππΈππ’ππππππ‘ = π₯ 12 βππ’ππ β ππππππππ‘ππ 1.055 πΎπ½ π΅ππ ππΈππ’ππππππ‘ = 26,246.4 βπ
Total Heat Gain of Avocado: πππ‘ππ π»πππ‘ π·ππ π ππππ‘ππ ππ¦ π ππππ ππ: πππππ ππ = 246.5013
π΅ππ βπ
ππ΄π£πππππ = πππ + ππΉππππ + ππ
πππ + ππ΄π£πππππ + ππΏππβπ‘π + πππππ ππ + ππΈππ’ππππππ‘ ππ΄π£πππππ = 3,581.0302 + 1,202.9696 + 1,146.0198 + 33,600 + 210.8096 + 246.5013 + 26,246.4 ππ΄π£πππππ = 66,233.7305
π΅ππ βπ
π₯
ππππ
12,000
π΅ππ βπ
= = 5.5195 Tons
Additional Heat Loads of Chicken: Insulation of Door:
Metaflex MAK Chiller; 3.15β Polyutherane 1 1 π₯1 1 + + ππ π1 ππ 1 ππ«πππ = 1 3.15 1 6 + 2.9 + 1.65 π΅ππ ππ·πππ = 0.5379 βπ β ππ‘ 2 β β Area of Door: π΄ππππ = πΏππππ ππ·πππ = 13β x 9.84β = 127.92 ππ‘ 2 ππ·πππ =
ππ·πππ = ππ΄βπ‘ = (0.5379
π΅ππ π΅ππ ) (127.92 ππ‘ 2 )(68 β 30 β) = 2,614.7104 2 βπ β ππ‘ β β βπ
Insulation of Walls of the Chicken Room : 4β concrete (sand and gravel) + 7β cork board (dense) + 4β concrete (sand and gravel) 4β concrete (sand and gravel) + 7β cork board (dense) + 4β concrete (sand and gravel) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 4 7 4 1 6 + 12 + 0.32 + 12 + 1.65
πππππ = πππππ
πππππ = 0.04289
π΅ππ βπ β ππ‘ 2 β β
ππππ‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 47β² = 616.64ππ‘ 2 πππ = ππ΄βπ‘ =(616.64 ππ‘ 2 ) (0.04289
π΅ππ ) (68 βπβππ‘ 2 ββ
π΅ππ βπ
β 30 β) = 1,005.0122
πππ’π‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 34β² = 446.08 ππ‘ 2 πππ = ππ΄βπ‘ =(446.08 ππ‘ 2 ) (0.04289
π΅ππ ) (73.4 β βπβππ‘ 2 ββ
30 β) = 830.3449
π΅ππ βπ
πΈππ π‘ ππππ: π΄πΈπ = πΏπΈπ ππΈπ = 13.12β² π₯ 51 = 669.12ππ‘ 2 ππΈπ = ππ΄βπ‘ =(669.12ππ‘ 2 ) (0.04289
π΅ππ ) (32 βπβππ‘ 2 ββ
β 30 β) = 57.3971
π΅ππ βπ
πππ π‘ ππππ: π΄ππ2 = πΏππ2 πππ2 = 13.12β² π₯ 32β² = 419.84 ππ‘ 2 π΄ππ1 = πΏππ1 πππ1 13.12β² π₯ 19β² = 249.28 ππ‘ 2 πππ = ππ΄βπ‘ πππ =(419.84 ππ‘ 2 ) (0.04289 (249.28 ππ‘ 2 ) (0.04289
π΅ππ ) (39.93 β 40 β) + βπβππ‘ 2 ββ π΅ππ ) (39.93 β 32 β) = βπβππ‘ 2 ββ
πππ = πππππ + πππ + ππΈπ + πππ + πππ πππ = 1,005.0122 πππ
π΅ππ βπ
+ 830.3449 π΅ππ = 4,590.9887 βπ
π΅ππ βπ
+ 57.3971
π΅ππ βπ
83.5241
+ 83.5241
π΅ππ βπ π΅ππ βπ
+ 2,614.7104
Insulation of Floors of the ChickenRoom : Hollow clay 4β + 3β concrete + 6β cork board (dense) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 1 4 6 1 6 + 1 + 12 + 0.32 + 1.65 π΅ππ = 0.04795 βπ β ππ‘ 2 β β
ππΉππππ = ππΉππππ ππΉππππ
π΄πΉππππ = πΏπΉππππ ππΉππππ = 47β² π₯ 51β² = 2397 ππ‘2 ππΉππππ = ππ΄βπ‘ =(2397 ππ‘ 2 ) (0.04795
π΅ππ ) (68 β βπβππ‘ 2 ββ
39.93 β) = 3226.2577
Insulation of Roof of the Chicken Room : Wood 25/32β fiber boards + 6β cork board (dense) ππ
πππ =
1 1 π₯1 π₯2 1 + + + ππ π1 π2 ππ
π΅ππ βπ
π΅ππ βπ
1 25 1 6 1 32 6 + 0.33 + 0.32 + 1.65 π΅ππ ππ
πππ = 0.04568 βπ π΄π
πππ = πΏπ
πππ ππ
πππ = 47β² π₯ 51β² = 2397 ππ‘2 ππ
πππ =
ππ
πππ = ππ΄βπ‘ =(2397 ππ‘ 2 ) (0.04568
π΅ππ ) (68 βπβππ‘ 2 ββ
β 39.93 β) = 3073.5235
π΅ππ βπ
Amount of lights in a Room: Average amount of lights in a room 20 fc (footcandles): Amount of illumination of an average 10 watt LED cold storage room bulb: 1040 lm No. of lights required: ππΏππβπ‘π =
(π΄πππ ππ π
πππ)(π΄π£π. πΉπππ‘πππππππ ) (πΏπ’ππππ ππ π΅π’ππ) β² 2
π΄πΉππππ = πΏπΉππππ ππΉππππ = 47β² π₯ 51 = 2397 ππ‘
(2397 ππ‘ 2 )(20ππ) ππΏππβπ‘π = = 46.0961 β 47 ππ’πππ ππ (1040 ) ππ’ππ ππ πΈπππππππππ¦ ππ ππ’ππ: π = 303 π ππΏππβπ‘π ππΏππβπ‘π
ππ π΅ππ 3.412142 (ππππβπ‘π )(πΏπ’ππππ ππ ππ’ππ) 47π’πππ π₯ 1040 ππ’ππ βπ = = = 161.3201 π π₯ ππ ππππππππππ¦ ππ ππ’ππ 1π 303 π π΅ππ = 550.4472 βπ
π΄πππ’ππ‘ ππ π»πππ‘ π·ππ π ππππ‘ππ ππ πΉπππππππ‘: πΉπππππππ‘ πππ πππππ’ππ 36920 πΎπ½ πππ‘ππ π€ππππππ πππ 8 βππ’ππ . π΄π π π’ππππ π‘βππ‘ π‘βπ ππππππππ‘ ππ π€ππππππ 12 βππ’ππ . πβπ’π ππ‘ πππππ’πππ 55380 πΎπ½ ππ βπππ‘ ππ£πππ¦ 12 βππ’ππ ππ π€ππππππ. 55380 πΎπ½ 1 π΅ππ ππΈππ’ππππππ‘ = π₯ 12 βππ’ππ β ππππππππ‘ππ 1.055 πΎπ½ π΅ππ ππΈππ’ππππππ‘ = 26,246.4 βπ
Total Heat Gain of Chicken: πππ‘ππ π»πππ‘ π·ππ π ππππ‘ππ ππ¦ π ππππ ππ: πππππ ππ = 246.5013
π΅ππ βπ
ππΆβπππππ = πππ + ππΉππππ + ππ
πππ + ππΆβπππππ + ππΏππβπ‘π + πππππ ππ + ππΈππ’ππππππ‘ ππΆβπππππ = 4,590.9887 + 3226.2577 + 3073.5235 + 45,045 + 550.4472 + 246.5013 + 26,246.4 π΅ππ ππππ ππΆβπππππ = 82, 979.1184 π₯ = = 6.9149 Tons π΅ππ βπ 12,000 βπ
Additional Heat Loads of Pork: Insulation of Door:
Metaflex MAK Chiller; 3.15β Polyutherane 1 1 π₯1 1 + + ππ π1 ππ 1 ππ«πππ = 1 3.15 1 6 + 2.9 + 1.65 π΅ππ ππ·πππ = 0.5379 βπ β ππ‘ 2 β β Area of Door: π΄ππππ = πΏππππ ππ·πππ = 13β x 9.84β = 127.92 ππ‘ 2 ππ·πππ =
ππ·πππ = ππ΄βπ‘ = (π. ππππ
π©π»πΌ π΅ππ ) (πππ. ππ ππ‘ 2 )(68 β 30 β) = 2,614.7104 π ππ β ππ β β βπ
Insulation of Walls of the Pork Room : 4β concrete (sand and gravel) + 7β cork board (dense) + 4β concrete (sand and gravel) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 4 7 4 1 6 + 12 + 0.32 + 12 + 1.65 π΅ππ = 0.04289 βπ β ππ‘ 2 β β
πππππ = πππππ πππππ
ππππ‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 51β² = 669.12ππ‘ 2 πππ = ππ΄βπ‘ =(669.12 ππ‘ 2 ) (0.04289
π΅ππ ) (68 βπβππ‘ 2 ββ
β 32 β) = 1,033.1480
π΅ππ βπ
πππ’π‘β ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 51β² = 669.12ππ‘ 2 πππ = ππ΄βπ‘ =(669.12 ππ‘ 2 ) (0.04289
π΅ππ ) (73.4 β βπβππ‘ 2 ββ
32 β) = 1,188.1203
π΅ππ βπ
πΈππ π‘ ππππ: π΄πΈπ = πΏπΈπ ππΈπ = 13.12β² π₯ 32β² = 669.12 ππ‘ 2 ππΈπ = ππ΄βπ‘ =(669.12 ππ‘ 2 ) (0.04289
π΅ππ ) (68 βπβππ‘ 2 ββ
β 32 β) = 1,033.1480
π΅ππ βπ
πππ π‘ ππππ: π΄ππ = πΏππ πππ = 13.12β² π₯ 32β² = 669.12 ππ‘ 2 πππ = ππ΄βπ‘ =(669.12 ππ‘ 2 ) (0.04289
π΅ππ ) (39.93 β βπβππ‘ 2 ββ
πππ = πππππ + πππ + ππΈπ + πππ + πππ π΅ππ π΅ππ πππ = 1,033.1480 + 1,188.1203 + 1,033.1480 βπ βπ π΅ππ πππ = 6,096.7063 βπ
32 β) = 227.5796
π΅ππ βπ
+ 227.5796
π΅ππ βπ
π΅ππ βπ
+ 2,614.7104
Insulation of Floors of the Pork Room : Hollow clay 4β + 3β concrete + 6β cork board (dense) 1 1 π₯1 π₯2 π₯3 1 + + + + ππ π1 π2 π3 ππ 1 = 1 1 4 6 1 6 + 1 + 12 + 0.32 + 1.65 π΅ππ = 0.04795 βπ β ππ‘ 2 β β
ππΉππππ = ππΉππππ ππΉππππ
π΄πΉππππ = πΏπΉππππ ππΉππππ = 51β² π₯ 51β² = 2601 ππ‘2 ππΉππππ = ππ΄βπ‘ =(2601 ππ‘ 2 ) (0.04795
π΅ππ ) (68 β βπβππ‘ 2 ββ
Insulation of Roof of the Pork Room : Wood 25/32β fiber boards + 6β cork board (dense) ππ
πππ = ππ
πππ
1
1 π₯1 π₯2 1 + + + ππ π1 π2 ππ 1 = 25 1 6 1 32 6 + 0.33 + 0.32 + 1.65
32 β) = 4,489.8462
π΅ππ βπ
π΅ππ βπ
π΅ππ βπ = πΏπ
πππ ππ
πππ = 51β² π₯ 51β² = 2601 ππ‘2
ππ
πππ = 0.04568
π΄π
πππ
ππ
πππ = ππ΄βπ‘ =(2601 ππ‘ 2 ) (0.04568
π΅ππ ) (68 βπβππ‘ 2 ββ
β 32 β) = 4,489.8462
π΅ππ βπ
Amount of lights in a Room: Average amount of lights in a room 20 fc (footcandles): Amount of illumination of an average 10 watt LED cold storage room bulb: 1040 lm No. of lights required: ππΏππβπ‘π =
(π΄πππ ππ π
πππ)(π΄π£π. πΉπππ‘πππππππ ) (πΏπ’ππππ ππ π΅π’ππ) β² 2
π΄πΉππππ = πΏπΉππππ ππΉππππ = 51β² π₯ 51 = 2601 ππ‘
(2601 ππ‘ 2 )(20ππ) = 50.0192 β 50 ππ’πππ ππ (1040 ) ππ’ππ ππ πΈπππππππππ¦ ππ ππ’ππ: π = 303 π ππΏππβπ‘π =
ππΏππβπ‘π ππΏππβπ‘π
ππ π΅ππ 3.412142 (ππππβπ‘π )(πΏπ’ππππ ππ ππ’ππ) 50 ππ’πππ π₯ 1040 ππ’ππ βπ = = = 171.6172 π π₯ ππ ππππππππππ¦ ππ ππ’ππ 1π 303 π π΅ππ = 585.5821 βπ
π΄πππ’ππ‘ ππ π»πππ‘ π·ππ π ππππ‘ππ ππ πΉπππππππ‘: πΉπππππππ‘ πππ πππππ’ππ 36920 πΎπ½ πππ‘ππ π€ππππππ πππ 8 βππ’ππ . π΄π π π’ππππ π‘βππ‘ π‘βπ ππππππππ‘ ππ π€ππππππ 12 βππ’ππ . πβπ’π ππ‘ πππππ’πππ 55380 πΎπ½ ππ βπππ‘ ππ£πππ¦ 12 βππ’ππ ππ π€ππππππ. 55380 πΎπ½ 1 π΅ππ ππΈππ’ππππππ‘ = π₯ 12 βππ’ππ β ππππππππ‘ππ 1.055 πΎπ½ π΅ππ ππΈππ’ππππππ‘ = 26,246.4 βπ
Total Heat Gain of Pork: π΅ππ βπ = πππ + ππΉππππ + ππ
πππ + ππππππ + ππΏππβπ‘π + πππππ ππ + ππΈππ’ππππππ‘ = 6,096.7063 + 4,489.8462 + 4,489.8462 + 207,000 + 585.5821 + 246.5013 + 26,246.4
πππ‘ππ π»πππ‘ π·ππ π ππππ‘ππ ππ¦ π ππππ ππ: πππππ ππ = 246.5013 πππππ πππππ
πππππ = 249,154.8821
π΅ππ ππππ π₯ = 20.7629 Tons π΅ππ βπ 12,000 βπ
Power Generated: πΈπ¨ππππ + πΈπΆπππππ + πΈπ¨πππππ
π + πΈπͺππππππ + πΈπ·πππ = πΈπͺππππππ π»ππππ ππ. ππππ π»πΆπΉ + π. ππππ π»πΆπΉ + π. ππππ π»πΆπΉ + π. ππππ π»πΆπΉ + ππ. ππππ π»πΆπΉ = ππ. ππππ π»πΆπΉ
https://www.componenthardware.com/wp-content/uploads/2016/02/LED-FoodServiceBrochure_01-2016.pdf https://en.wikipedia.org/wiki/LED_lamp https://thegrid.rexel.com/en-us/forums/general-electrician/f/forum/3196/what-is-therecommended-light-levels-for-a-warehouse-storage-facility https://www.archdaily.com/897277/how-to-determine-how-many-led-lumens-youllneed-to-properly-light-your-space https://www.lightingdesignlab.com/sites/default/files/pdf/Footcandle_Lighting%20Guid e_Rev.072013.pdf