Elliptical Effect Final Chapter

In order to explain my articles I will reference this chart motion and gravity relationship formula motion and g... Also I will refer to an interactive chart on this site: http://www.mathopenref.com/ellipse.html I look at the electron orbit in quadrants. At any given placement of the electron the neutron will have a relative position. The neutrons position is one of vibrancy. The neutron due to the force of the electrons magnetic charge (-) will travel along the line of point S to point S’. in the interactive chart the position of the neutron can be determined in reference to the electron by drawing a parallel line (parallel to the k, k’ point line) and intersecting with the S, S’ point line in reference to the electron position. That intersect is the given position of the neutron in regards to the electrons position. In the interactive chart the position of the neutron changes in reference to the electron position through magnetic attraction. This, I believe, is the reason for atom vibration or frequency. If the electron is in the position of point H, then the neutron assumes its position at point S. the attraction between the neutron and electron in this position is strong due their close proximity. The electron will begin its motion to point K, this position would represent the position of the electron at its highest velocity as it is in an + attract position in a positive way with respect to the electrons velocity in relation to the neutron as it travels from point H to point K. From point K to the point H’ the electron is in - attract position with the neutron attracting the electron in a negative way in respect to its velocity. Until the electron returns to the H’ position where it will assume its slowest velocity in the elliptical orbit. The electron’s change in velocity is relative to its sustained velocity which is a constant change of state relationship with regards to the speed of light. A blending of mass and energy. At point H and H’, the electron attains its maximum mass. At point K and K’, the electron attains its maximum energy. Between point H and K the electron velocity is increasing, due to + positive attraction during which time mass is being converted to an increased energy state. Between point K and point H’ the electron’s velocity, due to the - negative attraction, is decreasing. At which time energy is being converted to mass. This electron orbital cycle will repeat itself for each ½ orbit of the electron. The second half of the orbit is when the dynamics become incomprehensible. This electron is traveling near the speed of light. Sometimes exceeding this speed where the photon electric effect is at 100%… at lower speed than the speed of light, mass is introduced. The percentage of which would be relative to its velocity. The energy does not change its quantity only its characteristics. The frequency of the hydrogen atom is 1420.40575 MHz, when taken into account and multiplied by the speed of light, this result should be able to give an approximate distance that the hydrogen electron has traveled in its orbit. The hydrogen atom has a diameter of 37 pm. Using c=pi r2 it will give an approximation of distance traveled in the orbital path.

Being that 37 pm is the diameter then 18.5 pm multiplied by pi equals 58.09 pm. In a standard circle the orbital path would be 58.09 pm multiplied by its frequency 1420.40575 mega hertz ( the frequency I believe is directly related to the neutron/proton vibration in relation to the electron position) would result in 82511.37002 pm, an approximation. 1 pm is equal to 1 trillionth of one meter. In another view, if the electron is traveling at the speed of light for one second it has traveled a distance of 299792458 meters. So my question is how can this be? I

divided these two numbers: the speed of light/ orbital path distance

Seconds cancel and the ratio is 3633.347226 to 1 or 1/ 3633.347226.. Not an exact science but an approximate one. It would seem as if there is more than one effect occurring. And we know that mass and energy are constantly changing near the speed of light. I have to think as in any change of state that there is a latent heat, there is an addition and subtraction of heat energy. So when I say we are looking at two seemingly contradictory processes, it would seem it is the confusion of the same substance changing state where the heat (radiation) would be continually given off and absorbed. For example: an electrical wire will heat up during the passage of electricity a direct result of the resistance of the wire, the heat is not impeding the flow of electricity in a way that the electricity can’t perform its function. But it does impede the energy somewhat and gives itself off as heat. The electron is traveling at a velocity so great there has got to be some heat exchanged in some way and it has to be re-absorbed in some way to explain this effect. Obviously in the atom this effect is highly likely to be 100% efficient.

The following is my attempt to explain this effect: a model An interesting change Light and its relationship to the electron. The cubed root of gravity multiplied by the speed of light squared. The cube root of ( gravity times the speed of light squared) C = 186,000 miles per second G= .00625 miles per second squared 186,000 x 186,000 x .00625 = 216225000 miles per second cubed Take the cubed root of the answer it is equal to 600miles per second Take three vectors a, b, c, triangulate the vectors (Like an anarchy sign a triangle that transcends the circle)(the neutron is situated in the center of the triangle) Each vector represents 600miles per second inside the triangle Each time vector a, b, c enters the triangle it travels 600 miles per second and every time a vector’s exit’s the triangle it squares its motion and likewise with vector b and c. They are in a reflective position. I mean they are all at the same point relative to each other. At exit each motion along the vector squares its momentum ( wave released)to 360,000 miles per second. This number cannot be exceeded. It is the point of velocity where gravity and light will bend (wave release maximum at position of

bend). Each vector motion leaving its position in the triangle curving to re-enter the triangle at the next closest vectors entrance point. Changing its vector position, upon re-entry(wave absorbed) to the triangle its slows its motion to 600 miles per second. I apologize for the English measurements. With the triangulation of the vectors, an interior and an exterior definition of the of the electron path is established. This interior is representative of the most dense areas of the electron path. The most likely place of mass existence. The exterior path is representative of the electron path in its least dense areas. The most likely place of full energy existence. These areas of the interior and exterior electron path also are directly related to velocity and frequency. The interior inside the triangulated vectors, at the closet positions in relation to the neutron, would have the strongest attraction. The slower velocities, which is to say, in relation to the speed of light. The exterior, outside the triangulated vectors, would be in relation to the neutron, at the weakest point of attraction. The higher velocities in relation to the speed of light. Velocities that are not measurable or accepted to exist. The bending of the energy is not defined in a motion of velocity. It is defined in its wave nature. As it leaves the attraction of the neutron, it sustained independent existence is affected by the release of energy waves. the variations in the release of wave energy determines the distance from the neutron that the electron can travel from it. The electrons orbital path is effected by its previous positions of its past electrical (-) negative signatures altering the electron into angular orbital paths. This effect will change the mass/energy ratios and orbital paths in such a way to explain the random nature of the electron orbital path. john henry 2/14/09