Electricity

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Chapter 7

Electricity

Electric charge  Electric charge is an inherent physical

property of certain subatomic particles that is responsible for electrical and magnetic phenomena. Charge is represented by the symbol q.  The SI units of charge is the coulomb (C). 

 Like mass, electric charge is a fundamental

property of matter. 

Unlike mass, there are two types of charge: 

Positive and Negative. 2

Electric charge, cont’d  Recall that every atom is composed of

electrons surrounding a nucleus. 

The nucleus contains:  



protons — positive charge. neutrons — no charge.

Electrons — negative charge.

 An atom’s atomic

number is the number of protons in the nucleus. 3

Electric charge, cont’d  An atom’s charge is

neutral if it has the same number of protons and electrons.  An atom is said to be

ionized if the number of electrons and protons is different. 4

Electric charge, cont’d  If the protons outnumber the electrons, there

is more positive charge. 

We call such an atom a positive ion.

 If the electrons outnumber the protons, there

is more negative charge. 

We call such an atom a negative ion.

5

Electric force and Coulomb’s law  When we bring electric charges together, they

exert a force on each other. Positive charges attract negative charges.  Positive charges repel positive charges.  Negative charges attract positive charges.  Negative charges repel negative charges. 

 We paraphrase this as:

Like charges repel, unlike charges attract. 6

Electric force and Coulomb’s law, cont’d  The law that describes the forces between

electric charges is called Coulomb’s law.  Coulomb’s Law states that the force acting on each of two charged objects is directly proportional to the net charges on the object and inversely proportional to the square of the distance between them:

q1q2 F∝ 2 d

7

Electric force and Coulomb’s law, cont’d  The force on q1 is equal and opposite to the

force on q2. If the charges increase, the force increases.  If the distance increases, the force decreases. 

8

Electric force and Coulomb’s law, cont’d  The proportionality constant has a value of

9×109 N-m2/C2.  Coulomb’s law is then:

 9 N ⋅ m  q1q2 F =  9 ×10  2 2 C  d  2

  

F is in newtons, q1 & q2 are in coulmbs, and d is in meters. 9

Electric field  The electrostatic force is similar to gravity. 

The force can act through a distance without the two charges having to touch.

 Just as we talk about the gravitational field,

we can also define an electric field. force on a charged object electric field strength = charge on the object  The electric field lines indicate the direction

that a positive charge would move. 10

Electric field, cont’d  Here are some illustrations of electric field

lines surrounding a positive and a negative charge. The field lines point away from the positive charge.  The field lines point toward the negative charge. 

11

Electric field, cont’d  If the field points to the right: 

A positive charge would also travel to the right. 



The positive charge “thinks” there is a negative charge at the end of the line.

A negative charge would travel to the left. 

The negative charge “thinks” there is a positive charge at the start of the line.

12

Electric field, cont’d  An electrostatic precipitator is an example of

using electrostatics. Negatively charged wire charge the soot passing between the plates.  The now negative soot particles are attracted to the positively charged plates. 

13

Electric currents  An electric current is a flow of charged

particles. It is the rate of flow of electric charge.  The amount of charge that flows by per second: 

charge current = time



q → I = t

The SI unit is the ampere (A or amp): 

1 amp is 1 coulomb per second. 14

Electric currents  Here are some

examples of electric current.  Positive current is in the direction of positive charge flow.

15

Resistance  Resistance is a measure of the opposite to

current flow. Resistance is represented by R.  The SI units of resistance is the ohm (Ο ).  A conductor is any substance that readily allows charge to flow through it.  An insulator is any substance through which charge does not readily flow.  A semiconductor are substances that fall between the two extremes. 

16

Resistance, cont’d  Resistance of a wire depends on:

Composition. The particular substance from which the object is made.  Length. The longer the wire, the higher the resistance.  Diameter. The thinner the wire, the higher the resistance.  Temperature. The higher the temperature, the higher the resistance. 

17

Resistance, cont’d  Resistance is similar to friction.

Resistance inhibits the flow of electric charge.  Electrons typically produce the current in metals.  The electrons collide with the atoms of the metal.  This slows them down.  They also lose some energy to the atoms. 



The metal gets hotter. 18

Resistance, cont’d  Superconductivity is a phenomenon in which

a substance provides zero resistance to the flow of electric charge. 

It typically only occurs at rather low temperatures. 



The temperature below which a substance superconducts is called is critical temperature.

The latest superconductors require temperatures around 140 K (-207ºF). 19

Electric current and Ohm’s law  An electric current will flow through a wire

only if an electric field is present to exert a force on the charges. We typically use a “power supply” to provide the electric field and therefore the force.  The power supply forces charges out one terminal, through the wire, and back into the second terminal. 

20

Electric current and Ohm’s law, cont’d  Voltage is the work that a charged particle can

do divided by the size of the charge. 

It is the energy per unit charge given to charged particles by a power supply.

work V= q 

E ⇒ V= q

The SI unit is the volt (V). 

One volt equals one joule per coulomb.

21

Electric current and Ohm’s law, cont’d  The flow of charge in an electric circuit is

similar to the flow of water through a closed path. 

The power supply acts like the water pump. 

It adds energy to make the current flow.

The resistance corresponds to the narrow section of pipe.  The current is like the flow of water. 

22

Electric current and Ohm’s law, cont’d  Ohm’s law specifies that the current in a

conductor is equal to the voltage applied to it divided by the resistance:

V I= R  



or V = IR

V is the voltage through the conductor, I is the current passing through the conductor, and R is the conductor’s resistance. 23

Example Example 7.1 A light bulb used in a 3-volt flashlight has a resistance equal to 6 ohms. What is the current in the bulb when it is switched on?

24

Example Example 7.1 ANSWER: The problem gives us:

V =3V R=6Ω

The current through the bulb is

V 3V I= = = 0.5 A. R 6Ω

25

Example Example 7.2 A small electric heater has a resistance of 15 ohms when the current in it is 2 amperes. What voltage is required to produce this current?

26

Example Example 7.2 ANSWER: The problem gives us:

R = 15 Ω I =2A

The necessary voltage is

V = IR = ( 2 A ) ( 15 Ω ) = 30 V. 27

Electric current and Ohm’s law, cont’d  A series circuit has only one path for the

current to flow. The voltage across the first bulb, plus the voltage across the second, etc., must equal the battery’s voltage.  The current through each bulb is the same as the current passing through the battery. 

28

Electric current and Ohm’s law, cont’d  If the circuit is interrupted, then current no

longer flows through the circuit. 

If one bulb goes bad, then all the bulbs go dim.

29

Electric current and Ohm’s law, cont’d  A parallel circuit has multiple paths for the

current to flow. The current through the first bulb, plus the current through the second, etc., must equal the current through the battery.  The battery voltage is the same voltage on each bulb. 

30

Electric current and Ohm’s law, cont’d  If one bulb goes out, the other bulbs remain

lit. 

There is still a closed path for the electricity to flow through the circuit.

31

Example Example 7.3 Three light bulbs are connected in a parallel circuit with a 12-volt battery. The resistance of each bulb is 24 ohms. What is the current produce by the battery?

32

Example Example 7.3 ANSWER: The problem gives us:

V = 12 V R = 24 Ω

Since the bulbs are connected in parallel, they each have the same voltage. So the current through each bulb is:

V 12 V I= = = 0.5 A. R 24 Ω 33

Example Example 7.3 ANSWER: The total current necessary is the sum of the currents through each bulb. There are three bulbs, so:

I battery = 0.5 A = I bulb + I bulb + I bulb = 3I bulb I bulb = 13 (0.5 A) = 0.17 A

34

Power and energy in electric circuits  The power output of a circuit is the rate at

which energy is delivered to the circuit.  The power equals: 

the energy given to each coulomb of charge, multiplied by the number of coulombs that pass per second. 



The energy given to each coulomb of charge is the voltage. The number of coulombs that pass per second is the current. 35

Power and energy in electric circuits, cont’d

 This means the power through a circuit can

be written as

power = voltage × current P = VI

 The electrical resistance of many substances

causes them to get hot.  This type of heating is called ohmic heating. 36

Example Example 7.4 In Example 7.1, we computed the current that flows in a flashlight bulb. What is the power output of the batteries?

37

Example Example 7.4 ANSWER: The problem gives us: So the power consumed is

V =3V R=6Ω I = 0.5 A

P = IV = ( 0.5 A ) ( 3 V ) = 1.5 W

38

Example Example 7.4 DISCUSSION: This means the batteries supply 1.5 joules of energy each second.

39

Power and energy in electric circuits, cont’d

 The current through the

filament causes it to get very hot. 

The filament is a very thin wire. 

It is a coil wrapped into a coil.

 The thicker supporting

wires do not get as hot. 40

Power and energy in electric circuits, cont’d

 A fuse uses ohmic heating to monitor the

current through the circuit. If too much current flows, the fuse gets too hot.  It essentially melts and breaks the circuit. 

41

Example Example 7.5 An electric hair dryer is rated at 1,875 watts when operating on 120 volts. What is the current flowing through it?

42

Example Example 7.5 ANSWER: The problem gives us:

V = 120 V P = 1,875 W

The power is given by

P = IV .

Since we want the current, we divide by V:

P 1,875 W I= = = 15.6 A. V 120 V

43

Example Example 7.5 DISCUSSION: The wiring in the house and the hair dryer’s cord must be large enough to handle 15.6 A without overheating.

44

Power and energy in electric circuits, cont’d

 It is more efficient for the power company to

use very high voltage and low current to transmit power. Cross-country power lines use several hundred-thousand volts.  This allows smaller currents to be used.  With smaller current, smaller wires can be used without fear of excessive ohmic heating. 



This saves money of cable, the supporting structures, etc. 45

Power and energy in electric circuits, cont’d

 Recall our definition of power: 

The change in energy per unit time.

 This means we can write energy as the power

multiplied with the elapsed time. 

The energy change equals the rate at which energy is transferred time how long it is transferred. 

This is similar to the change in distance equaling the rate at which position changes multiplied with the time over which the position changes. 46

Power and energy in electric circuits, cont’d

 So we can write the energy in terms of the

power:



E P = ⇒ E = Pt t

So if we know the power a circuit uses and how long the circuit operates, we can determine the energy used by the circuit.

47

Power and energy in electric circuits, cont’d

 Power companies do not actually charge you

for power.  They charge you for energy. 1 kWh = 1 kW × 1 h = 1, 000 W × 3600 s = 3, 600, 000 J

 So a kilowatt-hour

is really energy. 48

Example Example 7.6 If the hair dryer discussed in Example 7.5 is used for 3 minutes, how much energy does it use?

49

Example Example 7.6 ANSWER: The problem gives us:

t = 180 s P = 1,875 W

The energy is given in terms of power as:

E = Pt = ( 1,875 W ) ( 180 s ) = 337,500 J.

50

Example Example 7.6 DISCUSSION: This is about the energy: required to melt 2 lb of ice, or  of a small car traveling at 60 mph, or  of a 150 lb person falling 170 floors. 

51

AC and DC  There are two types of current flow: 

direct current (DC) represents current flow that is always in the same direction. 



Batteries provide DC.

alternating current (AC) represents current flow that alters direction periodically. 

Wall outlets provide AC.

 A power adapter converts the AC from the

outlet to DC to charge a battery or power some device. 52

AC and DC, cont’d  Here is an example of DC provided by a

battery to a light bulb. The current always passes from the positive battery terminal, through the bulb, and then to the negative terminal.  The current is constant in time. 

53

AC and DC, cont’d  Here is an example of AC provided by a wall

outlet to a light bulb. The current always passes from the positive terminal, through the bulb, and then to the negative terminal.  But the terminals swap position over time. 

54

AC and DC, cont’d  So the current passing through the bulb

changes direction. Our wall outlets operate at 60 Hz.  So the current changes direction 120 times each second. 

55

AC and DC, cont’d  Here is one advantage of AC over DC.

A transformer is a device that can increase or decrease AC voltage.  If the transformer increases the voltage, it is called a “step up” transformer.  If the transformer decreases the voltage, it is called a “step down” transformer. 

 But there is an important consideration. 56

AC and DC, cont’d  The power into the transformer must (ideally)

equal the power out. 

Recall that electrical power is P = IV.

If the voltage is increased (stepped-up), the current must be decreased by the same factor.  If the voltage is decreased (stepped-down), the current must be increased by the same factor. 



Basically, energy must be conserved.

57

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