Class Notes Optics Lec04

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DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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March 09, 2009 Dated, the………………………….

Ref. No............................

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Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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March 09, 2009 Dated, the………………………….

Ref. No............................

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δ = α 2 − α1 = (kx1 + ε 1 ) − (kx 2 + ε 2 ) 2π = ( x − x ) + (ε 1 − ε 2 ) λ 1 2 *3 A

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= E 01 sin[ωt − k ( x + ∆x)] + E 02 sin(ωt − kx) = 2 E 01 sin ωt − k x +

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Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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March 09, 2009 Dated, the………………………….

Ref. No............................

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E 0i cos(α i ± ωt )

= E 01 cos(α 1 ± ωt ) + E 02 cos(α 2 ± ωt ) + E 03 cos(α 3 ± ωt ) + ... = E 01 (cos α 1 cos ωt

sin α 1 sin ωt ) + E 02 (cos α 2 cos ωt sin α 2 sin ωt ) + E 03 (cos α 3 cos ωt sin α 2 sin ωt ) + ...

= ( E 01 cos α 1 + E 02 cos α 2 + E 03 cos α 3 + ...) cos ωt = E 0 cos α cos ωt

E 0 sin α sin ωt

≅ E0 cos(α ± ωt ) + ,3 , + ,3 ,

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