Class Notes Optics Lec03

Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

! "

March 08, 2009 Dated, the………………………….

Ref. No............................

& "

'

" # # →

'

&

E(

"

)

1 uE = ε 0 E 2 2 →

B(

'

)

1 1 2 B 2 µ0 & ) E = cB 1 E= B

uB = *

ε 0µ0

1

E=

2

(2u E / E )( B 2 / 2u B )

uE = uB " "

' +

B

"

"

&

$

# "

u = uE + uB

&

)

= ε0E2 =

1

µ0

B2

"$ " "

& '

" & &

& " ,

# &

"

#, # %

#

) u.c.∆t. A ∆t. A = uc 1 2E = B µ0 B

S=

=

1

µ0

EB

& )

(-.

(-/

!

" #

$ # "%

Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

! "

March 08, 2009 Dated, the………………………….

Ref. No............................ →

S=

1

µ0

→

→

E× B →

→

= c 2 ε 0 E× B

1

c=

µ 0ε 0 →

0

"

&

→

→

→ →

→

→

→ →

k#

&

E = E0 cos k . r − ωt

B = B0 cos k . r − ωt →

r = xiˆ + yˆj + zkˆ

&

# "

→

→

→

)

→ →

S = c 2 ε 0 E 0 × B0 cos 2 k . r − ωt →

'

" ( &

&

'1 1 →

S

T

→

→ →

&

S

)

→ →

= T

S

%

= c 2 ε 0 E 0 × B0 cos 2 k . r − ωt

cos 2 k . r − ωt

2

"

1 2

'1 1

1 2 → → c ε 0 E 0 × B0 2 1 I ≡ S T = cε 0 E 02 2 T

=

'

$

" →

ψ1 r,t

&

" →

ψ 2 r ,t

$

"

&

#

→

# # # ψ n r,t

&

#

∂ 2ψ n ∂ 2ψ 1 1 ∂ 2ψ 1 ∂ 2ψ 2 1 ∂ 2ψ 2 1 ∂ 2ψ n = = # # # = ∂x 2 v 2 ∂t 2 ∂x 2 v 2 ∂t 2 ∂x 2 v 2 ∂t 2 "$ " #' ) 2 2 ∂ψ 1 ∂ψ = 2 2 2 ∂x v ∂t →

ψ r ,t =

n i =1

35

(-.

#! 6

(-7

→

C iψ i r , t

+

3

"

$

4

4

!

" #

$ # "%