Ahorro

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  • October 2019
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cuenta de ahorro 1 P= F= TEA= n= F=

2 P= F= TEA= n= F=

3 P= F= TEA= n= F=

50.000 ? 0.50% 360 dias 50000*(1+0.005)^1 =

50250 anual

20.000 ? 0.50% 360 dias 20000*(1+0.005)^1

20100 anual

40.000 ? 0.50% 360 dias 40000*(1+0.005)^1

40200 anual

plazo fijo 1 P= A= TEA= n=

30.000 ? 0.03 1 año

A=

2 P= A= TEA= n=

30000* 0.03(1+0.03)^1 = (1+0.03)^1-1)

30.900

25.000 ? 0.03 2 años

A=

25000* 0.03(1+0.03)^1 = (1+0.03)^1

25.750

25.750* 0.03(1+0.03)^1 = (1+0.03)^1

26.522

3 P= A= TEA= n=

35.000 ? 0.03 1 año

A=

0.03(1+0.03)^1 = 35000*

(1+0.03)^1

36.050

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