/* Write A C Program To Accept A Decimal Number

/* Write a C program to accept a decimal number and conert it binary * and count the number of 1's in the binary number #include <stdio.h> void main() { long num, dnum, rem, base = 1, bin = 0, no_of_1s = 0; printf("Enter a decimal integer\n"); scanf("%ld", &num); dnum = num; while( num > 0 ) { rem = num % 2; if ( rem == 1 ) /*To count no.of { no_of_1s++; } bin = bin + rem * base; num = num / 2 ; base = base * 10; } printf("Input number is = printf("Its Binary equivalent is = printf("No.of 1's in the binary number is = }

1s*/

%d\n", dnum); %ld\n", bin); %d\n", no_of_1s);

/* End of main() */

/*-------------------------------------------------Output Enter a decimal integer 75 Input number is = 75 Its Binary equivalent is = 1001011 No.of 1's in the binary number is = 4 RUN2 Enter a decimal integer 128 Input number is = 128 Its Binary equivalent is = 10000000 No.of 1's in the binary number is = 1 -----------------------------------------------------*/

* */