Question1 and question 2 {lesson 1 - Suppose a home network consists of computers named Foo and Bar, connected to a router, and then via a cable to the Internet. The home network is configured as a subnet: address 17.76.99.1 is assigned to Foo, address 17.76.99.2 to Bar, and address 17.76.99.100 to the router. The subnet has been configured so that the first three octets of its members' addresses are all the same subnet id, 17.76.99, and this fact is expressed by the subnet mask 255.255.255.0 (binary 11111111 11111111 11111111 00000000) configured in the router. When Foo sends data to example.com at 208.77.188.166, the router performs a logical AND of the destination example.com address with the subnet mask. It also performs a logical AND of the origin address (17.76.99.1) and recognizes that these two results are different, and therefore sends the data over the Internet, via the subnet's default gateway. When Foo sends data to Bar, however, it determines that the results of the two AND operations are the same, therefore the destination lies within the subnet and the default gateway is not required. The data is transmitted directly from Foo to Bar within the home network.} +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 5 departments with own subnet + 1 subnet for servers = 6 subnets required.. You will need 3 bits make to 6 subnet (6 in decimal = 110) therefore 3 bits required for network ID therefore subnet mask – 11111111.11111111.11111111.11100000 = 255.255.255.224 This will provide a maximum of 8 subnets (000 – 111) +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ Question 3 5 bits available for hosts so no of hosts = 2^5-2 = 30 The 2 ip addresses subtracted (1st and last are for network id and broadcast addresses) 30 hosts (subtract 1 for router address mean 29 available) Question 7 (I left out the 205.1.1. on some in the table – You shouldn’t do the same) Range 205.1.1.1 to 205.1.1.30 205.1.1.33 to 205.1.1.62 205.1.1.65 to 205.1.1.94 97 to 126 129 to 158
Subnet Address 205.1.1.0 205.1.1.32 205.1.1.64 96 128
Broadcast Address 205.1.1.31 205.1.1.63 205.1.1.95 127 159
161 to 190 193 to 221 224 to 254 Question 8 on next page… Box with R = router Box with W = workstation Box with S = Server….
160 192 223
191 222 255