Solutions Ta2 Chapter 8 & 9

  • April 2020
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Topics in Algebra 2 Chapters 8 & 9 Even Answers 54:

#48 : -5/3 , 4, 5/2

58:

# 38 : 0, 3, -3

64:

#2 : f(x) = (x+1)² - 6 ; vertex : (-1, -6) ; l.o.s. : x = -1 ; minimum : -6 #4 : f(x) = -(x+2)² + 7 ; vertex : (-2, 7) ; l.o.s. : x = -2 ; maximum : 7 #6 : f(x) = (x+5/2)² - 9/4 ; vertex : (-5/2, -9/4) ; l.o.s. : x = -5/2 ; minimum : -9/4 #8 : f(x) = (x+1/2)² - 1/4 ; vertex : (-1/2, -1/4) ; l.o.s. : x = -1/2 ; minimum : -1/4 #10 : f(x) = 4(x+1)² - 7 ; vertex : (-1, -7) ; l.o.s. : x = -1 ; minimum : -7

66:

#2 : none #12 : none

67:

# 2: #6: #8: #10:

69:

#6 : 4, -1

#8 : none

f(x) = -9/4x² + 9x a. f(x)=2500x² - 6500x + 5000 a. f(x)=0.1875x² - 18x + 670 a. 1176m at 15s b. 30.5s

#10 : -3/2

b. $19,000 b. about 568.75

#20 : vertex : (0, 0) ; l.o.s. : x = 0 #22 : vertex : (-1, 0) ; l.o.s. : x = -1 #24 : vertex : (-1, -2) ; l.o.s. : x = -1 ; maximum : -6 #26 : vertex : (-2, 1) ; l.o.s. : x = -2 ; maximum : 1 # 32 :

2  10 2

#34 : 3, 1

#36 : f(x)= 3x²- 6x + 5

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