Soal Subnetting !!
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SOAL NETWORKING !! -----------------------------------------------------------------------------------------------Buatlah menjadi empat subnet dlm satu network untuk IP address 192.168.0.1 dari kelas C berikut! ------------------------------------------------------------------------------------------------
JWB = UTK CR NETMASK = 256 : JML SUBNET YG MO DBG = 256 : 4 = 64 JWB = UNTUK CR PATOKAN AWAL SUBNET = 256(RUMUSNA) - 2 DIKALI JML SUBNET YG MO DBG : JML SUBNET YG MO DBG = (256-(2*4)) : 4 = 62 JD...
NETMASK 255.255.255.64 SUBNET 1 NETADDRESS 192.168.0.0 192.168.0.1 - 62 ------------>SELISIHNA 61 BROADCAST 192.168.0.63 SUBNET2 NETADDRESS 192.168.0.64 192.168.0.65-126 -----------> S.D.A BROADCST 192.168.0.127 SUBNET 3 NETADDRSS 192.168.0.128 192.168.0.129-190 BRDCS 192.168.0.191 SBNT 4 NETADDRSS 192.168.0.192 192.168.0.193-254 BRADCST 192.168.0.255 JML SUBNET = 4 NETWORK JML HOST = 62 * 4 = 248
JWB = UTK CR NETMASK = 256 : JML SUBNET YG MO DBG = 256 : 4 = 64 JWB = UNTUK CR PATOKAN AWAL SUBNET = 256(RUMUSNA) - 2 DIKALI JML SUBNET YG MO DBG : JML SUBNET YG MO DBG = (256-(2*4)) : 4 = 62 JD...
NETMASK 255.255.255.64 SUBNET 1 NETADDRESS 192.168.0.0 192.168.0.1 - 62 ------------>SELISIHNA 61 BROADCAST 192.168.0.63 SUBNET2 NETADDRESS 192.168.0.64 192.168.0.65-126 -----------> S.D.A BROADCST 192.168.0.127 SUBNET 3 NETADDRSS 192.168.0.128 192.168.0.129-190 BRDCS 192.168.0.191 SBNT 4 NETADDRSS 192.168.0.192 192.168.0.193-254 BRADCST 192.168.0.255 JML SUBNET = 4 NETWORK JML HOST = 62 * 4 = 248
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