Runga Kutta
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- Words: 125
- Pages: 3
Er.puneet kumar tyagi
AIM :- Write a program for RUNGA KUTTA METHOD #include<stdio.h> #include #include<math.h> float f(float x,float y) { return(y); } void main() { clrscr(); float x0,y0,h,xg,yg,k1,k2,k3,k4,k,i,n; printf("\ enter the initial value of x0"); scanf("%f", & x0); printf("\ enter the initial value of y0"); scanf("%f", & y0); printf("\ enter the given value of xg"); scanf("%f", & xg); printf("\ enter the value of step size h"); scanf("%f", & h); n=(xg-x0)/h; for(i=1;i<=n;i++) { k1=h*f(x0,y0);
Er.puneet kumar tyagi
k2=h*f(x0+(h/2),y0+(k1/2)); k3=h*f(x0+(h/2),y0+(k2/2)); k4=h*f(x0+h,y0+k3); k=(k1+2*k2+2*k3+k4)/6; yg=y0+k; y0=y0; } printf("the final value of yg=%f", y0); getch(); }
Er.puneet kumar tyagi
OUTPUT: Enter the initial value of x0=0 Enter the initial value of y0=2 Enter the given value of xg=0.2 Enter the value of step size h=0.1 The final value of yg=2.000000
AIM :- Write a program for RUNGA KUTTA METHOD #include<stdio.h> #include
Er.puneet kumar tyagi
k2=h*f(x0+(h/2),y0+(k1/2)); k3=h*f(x0+(h/2),y0+(k2/2)); k4=h*f(x0+h,y0+k3); k=(k1+2*k2+2*k3+k4)/6; yg=y0+k; y0=y0; } printf("the final value of yg=%f", y0); getch(); }
Er.puneet kumar tyagi
OUTPUT: Enter the initial value of x0=0 Enter the initial value of y0=2 Enter the given value of xg=0.2 Enter the value of step size h=0.1 The final value of yg=2.000000
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