Pr4.pdf
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PROBLEMATICAL RECRETIONS Age Problem A man passed one sixth of his life in childhood, one twelfth in youth and one seventh more as a bachelor. Five years after his marriage, a son was born who dies four years before his father at half his father’s final age. What is the man’s final age? Solution: Let x be the final age of the man. 1 Childhood: x Youth:
6 1
x
12 1
Bachelor: x 7 Marriage: 5 (no son) Son’s age: x/2 After son’s death: 4 1 6
x+
1 12
x+
1 7
x+ 5+
x 2
+4=x
x = 84
-----------ONDEREAL-----------
6 1
x
12 1
Bachelor: x 7 Marriage: 5 (no son) Son’s age: x/2 After son’s death: 4 1 6
x+
1 12
x+
1 7
x+ 5+
x 2
+4=x
x = 84
-----------ONDEREAL-----------
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