Pneumatic & Hydraulic For Intermediate

  • July 2020
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Pneumatic & Hydraulic :Suthirak Sumran

     

   ก        ก  ก ก    ก      ! กก"  ก    #ก   ก  ก $ก %ก&'"()* ก  ก

ก  (fluid power)  + ก*  "() ( ,-) # ก ก ก.#  " "() "   (fluids)  + ก/0   (liquids and gases)

ก*ก    (=  - ก ' >#  ก? ก%ก กก@ก() ,-*. ก% #  ก-) -) - - %ก&' % -)  ก%.A&B'    ก") กCD   !" #$%ก (Sarcos, Inc.)

Control valve Diaphram Springs Actuator Valve stem movement Valve plug Valve

-)  Hydraulic

-)  AMADA

-) , AMADA

PC'C'

-)  ก '

DQ 

56!%7689:8 "PP (" ก    ก##)  -) R 1650 ก,กW  0+) %#

Pressure is transmitted undiminished in a confined body of fluid. “ก ! "#$%&'()*+กกก,-./,(ก+0$(1”

$ % @

ก;<7

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ก  >?$!8ก;<7

กก@

กก@

<65กA5AAก  5AA #$%ก

   

*%ก (Air Service Unit) %ก&'-)  (Air Actuators) ' (Valves) %ก&' (Accessories)

*%ก (Air Service Unit)

ก  (Air Filter) ก  ) กก ก= - =  #

  (Air Regulator) ก]  

 # -)=  (Air Lubricator)  =  # -)

%ก&'-) (Air Actuators) " "()ก() ,

  .ก + 

-  *#ก ก  ' ``

%ก&' -)a 

  -  (Angular gripper)



%  (Air bellow)





 ' (Air motor)

 ก (Rotary vane actuator)

=% "?" (Directional Control Valves) 

  "?" ก   "()

- กก %ก&'

"#  

"#  " "()ก ก,     %ก&'ก" # a

ก@( (Silencer) 

" "()(  &  "= $# ก?

' ก  (Flow control valve) 

" "()%  @ ก ก

 ' (Ball valve) 

" "()% กf-f 

-)  ก? (Compressor) -)  ก? ( "()# ก?"()    ก# %ก&'ก ก#  ก?*  ( ก% A, ก?P กก ก     ก ก *-= ก ก@   ( receiver)

     

ก #hก]&' %ก&' กaก    %&  ก?

#     ก ก ก' ก   ก ก ก' ก   ก ก ก'

%68!%ก (pneumatics) 8Bก7CD?"EFกGก 9$%8 8 HI 8 >ก  JB 98>K8GกDL8JMNJ E7!< ก8BI9GK 768 8 J N 8 HI ก8$$ JMNกA97>K8>กJ E7!< ก8

Bก9: 3 59E? ก 7> 2.1 %68!%ก$!K (low pressure pneumatics) A % ก ,i * ก%    (fluidics - fluid logic)  "() *  #ก 150 กP (kPa) - "() 1.5 ' - "() 21  '#  = (psig) 2.2 %68!%ก$ก!% (normal pressure pneumatics) A % ก ,i * ก% ก"   -) - %ก&'"() ? ก-) ก ก  "()*  $# # 1501,600 กP - "() # 1.5-16 ' - "() 16-132  '#  = 2.3%68!%ก$< (high pressure pneumatics) A % ก ,i * ก% ก"  -) - ,?]  $ %ก&'"() ? ก-) ก ก  % ก  "()* กก#1,600 กP - "()กก# 16 ' - กก# 132  '#  = (psig)

'  %ก&'"   %ก&'A, ก? 

ก #hก]&'' 



*() () %ก  # *# () ( ) % 2 $  + 2  # , () () % 3 $  + 3  #

!(ก"  '"()ก  A () () % - "+() () %  + ก# P ( $ก?"() ก"?" ก    #"+"( ) ( ( - กfก="?" ก   

ก #hก]&'' (# ) 

ก# % กก() () %  # ก() () %,( $( 

 # ก '

ก( ก*-) '

ก( ก*-) ' (# )

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ก"  '

ก"  '

ก"  '

ก"  '

ก"  '

ก"  '

ก"  '

ก"  '

ก"  '

ก"  '

P   ' , ,, (popet valve)

12

1 2

12 12

1 1

2

P   ' (# ) $ (Spool valve)



This 5/2 valve has a spool fitted with disc seals

4

2

14

12 1 5

14

12 5

4

1

2

3

3



This 5/2 valve has a spool fitted with disc seals

4

2

14

12 1

5

14

12 5

4

1

2

3

3

ก%=% "?"

*ก"  '

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%ก&'() $,



$ %ก&'A, ก?

$*% FRL

$ก ก$

$=%  ก 

$=% "?"

  Pabs = Patm + Pg

  Gauge Bars

0

1

2

3

4

5

6

7

8

Absolute Bars

1

2

3

4

5

6

7

8

9

PISG

0

14.5

29.0

43.5

58.0

72.5

87.0

PSI

14.5

29.0

43.5

58.0

72.5

87.0

101.5 116.0 130.5

101.5 116.0

#  

t Pascal : Pa : N/m2 10 kg = ~ 100 N t Bar : Kg/cm2 10 Bar = 10 kg/cm2 t PSI : Pound per Square inches. 1 Bar = ~ 14.5 PSI

ก #

1 Bar 1 Bar 1 Bar 1 Bar 1 Bar

= ~ 14.5 PSI = ~ 401.46 in.wg = 105 Pa = 100 kPa = 0.1 MPa = 0.1 N/mm2 = 1 ATM

%&  ก?

t 1. %& A$ (Temperature), T t 2.  (Pressure), P t 3.  (Volume), V 

กW ก/ ! +   ,!' %& "= 3 

ก  ก?   $&' ก/ .ก   -) %   %& A$  "()  ก  ก?   ก   ก+= 

%&  ก/(Boyleus Law)

%& A$  "()

   

  ก ก$  

   +

  ก ก$

 =   × ,-="()   ก ก =   × ,-="() ก ก

,-="() 

D>b?GK = 3.14 x D 2 = 3.14 x R2 4 D

D>b?GK = 3.14 x (D 2- d2) = 3.14 x(R2-r2) 4 d

 ,   ,-="() 4 Bars

Area = 3.14 xR2 = 3.14 x(1 cm)2 = 3.14 cm2 D= 2 cm.

 = 4 bars x 3.14 cm2 = 12.56 kg

12.56 kg

,-="()  ก ก$ $ก5Aก<A(%b6)

D>b?GK N!$ก5Aก<A ()

1

0.785

1 1/2

1.77

2

3.14

2 1/2

4.91

3

7.07

3 1/2

9.62

4

12.6

4 1/2

15.9

5

19.6

5 1/2

23.8

6

28.3

6 1/2

33.2

 #   

 @ ก ก$ 

 @ก ก$+=ก:

t ก ก$ t $"() ก ก$ t ' ก t   ก? t     t  "()ก"กก ก$

  ก ก$ 

234(6ก&&# ) = 9:; '()% -4x/1/1: / 231

(1)

A1'()  

  

9:; '()ก/B#ก+B (4 3;) /1/1: ( 3;)

1 in (inch) = 25.4 mm = 2.54 cm = 0.0254 m = 0.08333 ft 1 in2 = 6.452 cm2 = 6.452x10-4 m2 = 6.944x10-3 ft2 1 gal (US) = 3.785x10-3 m3 = 3.785 dm3 (liter) = 0.13368 ft3





!6  ก ก$ 4" ,-="()  12.57  =   - ก ก$ 30 =  *  "#   = ,-= "()  x   - / 231 = 12.6 x 30 / 231 = 1.63 ก 

 *ก ก ก$ "()  





 *# *ก(Stroke) t Stoke = => ก % &-) "() t => = ก ก ก$ .#?$ 'ก ก ก$(Diameter) t .#?$ 'ก @ก =>  *  กก# - )  ก "#ก t => = กก ก$ ก#  (Pressure) t   =>  *ก ก$ h#+= ก ก+= t => (P กก) ก#

!$ก5Aก<A A%F? Festo

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