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SULIT 1449/2 Matematik Kertas2 Peraturan Pemarkahan Ogos 2008

1449/2

SEKOLAH BERASRAMA PENUH BAHAGIAN PENGURUSAN SEKOLAH BERASRAMA PENUH /KLUSTER KEMENTERIAN PELAJARAN MALAYSIA PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN MALAYSIA 2008

MATEMATIK Kertas 2

PERATURAN PEMARKAHAN

Jumlah Markah =

Kertas 1  Kertas 2  100% 140

Peraturan pemarkahan ini mengandungi 8 halaman.

1449/2

[Lihat sebelah SULIT

Section A [ 52 marks ]

No 1

Marking Scheme (i)

Marks

(ii)

P1, P2

B

A

B

A

3

C 2.

C K1

2 x 2  x  15  0 (2 x  5)( x  3)  0

K1

5 x   ,3 2

N1N1

3.

2m – n = 2 2n = 1 1 n= 2 5 m= 4 4.

or

m =1 +

1 n 2

K1

4m  5

or

K1

N1 P1

5 12

K2

 HAE  22.62o or 22o 37 ' 5.

4

N1

 HAE tan  HAE 

4

N1

(a)

False

P1

(b)

If n  2, then x n  x is a quadratic expression

P2

(c)

4n 2  7, n  1, 2, 3.......

P1, P1

2

4

5

No 6.

7.

Marking Scheme 1  (32  48)  15  16 2 22  7  7  15 7 1 22  (32  48)  15  16   7  7  15 2 7 7290 (a) x  6

P1 P1

K1

K1 N1

(b) P (0,3)

8.

Marks K1

mPQ  1

K1

y  x3

N1

x  3

P1

 4 2  1   4  (6)  3 1  1  4 2     2  3 1 

(a ) A1 

4

5

K1

N1

 1 2  r   6  (b)        3 4  s   8   r  1  4 2  6        s  2  3 1  8  r4

P1

K1

N1

s5

N1

r   4 Note:      accept for P1  s 5

3

6

No

Marking Scheme

Marks

9.

(a)

180 22 13 2  360 7 2 180 22 13  2    5  12 360 7 2 3 37 or 37.43 7

K1 K1

N1

2

(b)

180 22  13  90 22 2     or  5 360 7  2  360 7 1 1 or  5  7 or  5  12 2 2

K1

2

180 22  13  1 90 22 2 1       5  12)  (   5   5  7) 360 7  2  2 360 7 2 1  59 or 59.25 4 (

10

(a)

6

N1

K2 N1

5

P1

(a)

1 12

(b)

1 2 3 1 1 1      6 5 4 10 12 2

K2

11 * 60

(c) 1 

N1

K1

18  0 .5 T T  36

1 (b)  ( x  80)  18  855 2 x  15

11

K1

N1 11 * 60

K1 N1

49 60

6

4

No 12

1.5 10

x y

(a)

Marking Scheme 2.5 6

(b) Uniform scales  4.5  x  4.5 and  30  y  30 All 10 points plotted correctly . Smooth curve and passed all 10 correct points .

Marks K1K1

P1 K2 N1

y

y=3x+

5

x

y=-15/x

y = –

(c)

15 : x Intercept (0, 0) x

P1 P1

x = 2.1  0.1 y = 10.3  0.5

(d) y = 3x + 5 Straight line y = 3x +5 drawn x = 1.6  0.1 , 3.2  0.1 13

(a) (i) (ii)

(1 , 6) (6 , 1)

K1 K1 N1N1 12 P1 P2

(b) (i) K : rotation 90o anticlockwise by the centre (3,4) (ii) J :enlargement at centre P or (6,3) and scale factor 2

P3 P3

(c) A +78 = 2 2  A A = 26 cm2

K2 N1 12

5

No 14

Marking Scheme (a) Time(minutes) Frequency (i) (ii) 35 – 39 2 40 – 44 3 45 – 49 4 50 – 54 7 55 – 59 6 60 -64 4 65 – 69 3 70 - 74 1 (i) (ii) (iii) (b).

Marks

Midpoints (iii) 37 42 47 52 57 62 67 72 P1 P1 P1

all class interval correct all frequencies correct all midpoints correct

(i) 50 – 54 2(37)  3(42)  4(47)  7(52)  6(57)  4(62)  3(67)  1(72) (ii) 2  3  4  7  6  4  3 1 53.83

P1 K2 N1

(c)     

Uniform scale on the x-axis and on the y – axis Mid - points on horizontal axis 8 points plotted corecctly points (32,0) and (76,0) plotted correctly frequency polygon pass through all 8 points correctly, (32,0) and (76,0)

K1 K1 K1 K1 N1

frequency

7 6 5 4 3 2 1 32 37 42 47 52 57 62 67 72 77

midpoint

12

6

No 15

Marking Scheme I

Marks

J

4cm L H/E

K G/F

4cm D/A

C/B

6cm

Correct shape with two rectangle IJLK and LKAB. Dotted line HG. Correct mesurement  0.2. (b) F/B

J/G

K/C

I/H

L/D

P1 P1 Q2

6cm E/A Correct shape with rectangle ABCD and semicircle CD. Straight line GH and semicircle CD by using compasses. Correct mesurement  0.2.

P1 P1 Q2

(c) I/J 5cm L/K E/F

H/G 4cm

3cm A/B

D/C 3cm

8cm

Coreect shape with hexagon AEHILD and a rectangle. The length of the sides must be in correct proportion Correct mesurement  0.2

7

P1 P1 Q2

12

No 16

Marking Scheme

Marks

(a) K

N

P1P1

O L

J J S o

P2 K1 K1 N1

o

(b) (77 N , 110 W) (c) (90  77)  2 (90  77)  2  60 1560 n.m.

(d) (i)

(e) T 

cos 77o 180  60  cos 77o 2429.47*

K1 K1 N1

2429.47 * 154  60 1500

K1

7.78 hours or 7 hr 47 min

N1 12

8

9