Lq Unit 3 Indices, Surds And Number Systems Sol
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Math/CE LQ Ex.3
Unit 3 Indices, Surds and Number Systems Solution 1.
2.
3.
4 3
… 1A
1
Math/CE LQ Ex.3
4.
(a 4 b −2 ) 2 ab
=
a 8 b −4 ab
… 1M
=
a8 ab1+ 4
… 1M
=
a7 b5
… 1A
5.
6.
7.
8.
27 − 12
= =
3 3−2 3
3
… 1A … 1A
2
Math/CE LQ Ex.3
9.
10.
11.
12.
x3 y 2 x −3 y
a 3a 4 b −2
(a −3 ) 2 a
x −3 y x2
=
x3–(–3)y2–1
… 1M
=
x6y
… 1A
=
a 3+4 b– (– 2)
… 1M + 1M
=
a7b2
… 1A
=
a −6 a
… 1M
=
1 a6a
… 1M
=
1 a7
… 1A
= =
13.
m3 (mn) 2
y x x3 y 2+ 3 x 2
=
y x5
=
m3 m2n2
= =
m 3− 2 n2 m n2
… 1M … 1M … 1A
… 1M … 1M … 1A
3
Math/CE LQ Ex.3
14.
15.
16.
17.
( x 3 y) 2 y5
=
x6 y 2 y5
= x6y–3
… 1M … 1M
6
=
x y3
… 1A
~ End of Unit 3 LQ Solution ~ 4
Unit 3 Indices, Surds and Number Systems Solution 1.
2.
3.
4 3
… 1A
1
Math/CE LQ Ex.3
4.
(a 4 b −2 ) 2 ab
=
a 8 b −4 ab
… 1M
=
a8 ab1+ 4
… 1M
=
a7 b5
… 1A
5.
6.
7.
8.
27 − 12
= =
3 3−2 3
3
… 1A … 1A
2
Math/CE LQ Ex.3
9.
10.
11.
12.
x3 y 2 x −3 y
a 3a 4 b −2
(a −3 ) 2 a
x −3 y x2
=
x3–(–3)y2–1
… 1M
=
x6y
… 1A
=
a 3+4 b– (– 2)
… 1M + 1M
=
a7b2
… 1A
=
a −6 a
… 1M
=
1 a6a
… 1M
=
1 a7
… 1A
= =
13.
m3 (mn) 2
y x x3 y 2+ 3 x 2
=
y x5
=
m3 m2n2
= =
m 3− 2 n2 m n2
… 1M … 1M … 1A
… 1M … 1M … 1A
3
Math/CE LQ Ex.3
14.
15.
16.
17.
( x 3 y) 2 y5
=
x6 y 2 y5
= x6y–3
… 1M … 1M
6
=
x y3
… 1A
~ End of Unit 3 LQ Solution ~ 4
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