Lec 3.pdf

  • Uploaded by: muskan agarwal
  • 0
  • 0
  • November 2019
  • PDF

This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA


Overview

Download & View Lec 3.pdf as PDF for free.

More details

  • Words: 497
  • Pages: 6
IM

Finite Automata Q E go F S 8 axe g sgai.net agdmingo Bae

M

WE

setae

1 M accepts

2

w

g

QxE p

reading

a

string

Eo

Icq

Icq

C F

w

q f

E na

q

n

a

NEE AGE

qin a

5

Is

if

we

f Cq ay qEQ

q proof put

E

in

start

AEE

S

exhaust input then

we

end in

I agree

p

proff

Icq

ny

ICE Cohn

a

on

By applying induction on length g of ly l e

g my

n

would

single symbol

PE

9

in stale

c

qEg

ly I

for

ye

2

j Cq

g Icahn y

ny

1829 n y

b n

for

LE ay

Assume

for

L yr

g e

e

l

to prove

By

Sican y yn

yn

nti

Cd my

Icahn

Ynyne

Ye

using

Covey

n

Ynet

sitting

g na

yn

Ynet

5 I 8 can Y Bede

CECE let

n

y 3 8 stem g

E

ICE

syn

yntD

a

a

Silsila Misa 8C stain 3

SC FC2 mg

a a

I

8C 8 CE 3 8 q nza y E Anny

9

find

for

FA WE

a

Lo

1

13

o

w

easy

µ very determinism Non helps

NO Is

0

E

ends in 01

determinism In case DFA

Non

of

has

SLE

9

Deterministic FA

exactly

a

is

each state q

i.e

for

out

arrow

one

unique a

symbol SC 9

NFA

a

ofNoslates arrow out

set

a

is

empty multipleStates

Input

00 I O

to

w

W

01090

K

q

stuck 90

9

0

g

qoµ

f

90

q

shine

O

90

000

to

i

q

9

Sm

O

I

oh

O

A

9q

Gr

Steele

Here ills is not exhausted

1

O

O

q

Yet he itis not accepted

Acceptance

8

when

execution path

there

ends

that

atleast

is

in

one

final

stale

accepting stele i e

final

tip fussibre exhausted execution palles either get stuck or state end in a non accepting not fond State or final stale t iffs not when

Rejection

all

exhausted

Cmo

Every string atleast n

f

one

L

NE L

have

should

L

in

acceptance

ballet All paths

are

Allease one fratt

rejecting is

accepag

NFA

Q 2

an

o

F S

Q

Jinx

S

SC q

as

Is

i

Stuck

stude

9

29 Ed

Q XE

reading w Base

case

19

i

Cq

Eca

E

a

nay

Is kz

Sp f u

Pi WE 2

slow

f

ice

n

z

WAEL

f

US bi

Cana

LCN

s

q

a

S Cpp

from E by

reachable

states

co

E

a

Sica

n

w NF 1 1 IcaoOne 0 the

of is find Skle State accepting

gray tree El 2,33 such is at last symbol W appears previously without any intervening larger symbol

WE

Sf µ eesthymdfs

last symbol I a

test symbols

31214423

gg

a

NFA is more powerful than DFA to DFA 2 How took'trwansforbm NFA

power

set

in

Related Documents

Lec
November 2019 52
Lec
May 2020 32
Lec
May 2020 28
Lec
November 2019 41
Lec
November 2019 38
Lec
November 2019 49

More Documents from ""

Lec 18.pdf
November 2019 17
Lec 15.pdf
November 2019 14
Lec 14.pdf
November 2019 8
Lec 4.pdf
November 2019 11
Lec 2.pdf
November 2019 9