IM
Finite Automata Q E go F S 8 axe g sgai.net agdmingo Bae
M
WE
setae
1 M accepts
2
w
g
QxE p
reading
a
string
Eo
Icq
Icq
C F
w
q f
E na
q
n
a
NEE AGE
qin a
5
Is
if
we
f Cq ay qEQ
q proof put
E
in
start
AEE
S
exhaust input then
we
end in
I agree
p
proff
Icq
ny
ICE Cohn
a
on
By applying induction on length g of ly l e
g my
n
would
single symbol
PE
9
in stale
c
qEg
ly I
for
ye
2
j Cq
g Icahn y
ny
1829 n y
b n
for
LE ay
Assume
for
L yr
g e
e
l
to prove
By
Sican y yn
yn
nti
Cd my
Icahn
Ynyne
Ye
using
Covey
n
Ynet
sitting
g na
yn
Ynet
5 I 8 can Y Bede
CECE let
n
y 3 8 stem g
E
ICE
syn
yntD
a
a
Silsila Misa 8C stain 3
SC FC2 mg
a a
I
8C 8 CE 3 8 q nza y E Anny
9
find
for
FA WE
a
Lo
1
13
o
w
easy
µ very determinism Non helps
NO Is
0
E
ends in 01
determinism In case DFA
Non
of
has
SLE
9
Deterministic FA
exactly
a
is
each state q
i.e
for
out
arrow
one
unique a
symbol SC 9
NFA
a
ofNoslates arrow out
set
a
is
empty multipleStates
Input
00 I O
to
w
W
01090
K
q
stuck 90
9
0
g
qoµ
f
90
q
shine
O
90
000
to
i
q
9
Sm
O
I
oh
O
A
9q
Gr
Steele
Here ills is not exhausted
1
O
O
q
Yet he itis not accepted
Acceptance
8
when
execution path
there
ends
that
atleast
is
in
one
final
stale
accepting stele i e
final
tip fussibre exhausted execution palles either get stuck or state end in a non accepting not fond State or final stale t iffs not when
Rejection
all
exhausted
Cmo
Every string atleast n
f
one
L
NE L
have
should
L
in
acceptance
ballet All paths
are
Allease one fratt
rejecting is
accepag
NFA
Q 2
an
o
F S
Q
Jinx
S
SC q
as
Is
i
Stuck
stude
9
29 Ed
Q XE
reading w Base
case
19
i
Cq
Eca
E
a
nay
Is kz
Sp f u
Pi WE 2
slow
f
ice
n
z
WAEL
f
US bi
Cana
LCN
s
q
a
S Cpp
from E by
reachable
states
co
E
a
Sica
n
w NF 1 1 IcaoOne 0 the
of is find Skle State accepting
gray tree El 2,33 such is at last symbol W appears previously without any intervening larger symbol
WE
Sf µ eesthymdfs
last symbol I a
test symbols
31214423
gg
a
NFA is more powerful than DFA to DFA 2 How took'trwansforbm NFA
power
set
in