Flow through Pipes Flow through pipes is mostly associated with Head loss, which makes it important to know several factors that contribute to it. Basic Concepts one must know to determine head loss in pipes, Type of flow Ideal fluid flow: A flow is Ideal if the viscosity is zero. Hence these fluids do not have head loss. Ex: Air, gases are mostly ideal. Equations for Ideal flow: Bernoulli Equation, Continuity Equation. Real fluid flow: The fluids that have viscosity are real. These fluids have: Friction among their layers, head loss, shear stress Note: From the definition of Newtonian Fluids
τ =µ
du dy
Even if µ=0, τ≠0. τ =0 only if
i.e. when the fluid is hydrostatic ==at rest. du =0 dy
Conduits: Open Conduit: In open conduits, the flow is open to atmosphere. Pressure ≠f(x) Where x= distance Closed Conduit: In closed conduits, pressure varies with the pump used and friction. Pressure=f(x) if the pipe is full. Pressure ≠f(x) if the pipe is not full. Circular and Non Circular pipes: Circular pipes: Most of the water carrying pipes.
Non Circular pipes: Air ducts are generally rectangular. The flow is also categorized based on the Reynolds No. If the Reynolds No <2000, the flow is laminar. If the Reynolds No>4000, the flow is turbulent. If 2000
Figure 1.Velocity distribution for Laminar and Turbulent flows Laminar Flow: The velocity distribution in laminar flow conditions along the cross-section of the pipe will be parabolic (Figure 1) due to the following reasons: •
•
The friction between layers of the fluid and the wall of the pipe. The fluid being in motion and the pipe being at rest, the velocity at junction of fluid and wall will be equal to zero. Also the friction between the layers of the fluid also causes a change in the velocity distribution.
Turbulent Flow: The velocity distribution turbulent flow conditions along the cross-section of the pipe do not vary much (Figure 1) except for the junctions of the conduit wall with fluid due to the following reasons: • •
The particles in the turbulent flow regime are very well mixed, so the velocity remains the almost uniform towards the centre of the pipe. Due to the friction between the pipe conduit and fluid layers, the velocity at the interface of conduit and the fluid is almost==0.
Pressure drop derivation for Laminar flow conditions: Consider a pipe cross-section in which laminar flow conditions exist. Let us take a small element of fluid (Figure 2). Applying Newton’s second law of motion to the laminar fluid flow, Under stead flow conditions, Net force=ΣF=m x a =m
=0 dv dt
Figure 2.Laminar fluid flow –Cross-section of the pipe. Consider an element of length ‘l’. Applying second law of Newton, Sum of the forces on the fluid element=Force@1-Force@2-Shear force at the element.
ΣF = p1 A − p 2 A − τ .2πrl Where
pressure force acting on section 1-1
p1 =
pressure force acting on section 2-2
p2 = A=area of the section
τ=
Shear stress on the element
Under steady state conditions, ΣF=0
Σ F = p1π r 2 − ( p1 − ∆ p)π r 2 − τ 2π r l = 0
∆p =
2τl 4τl = −−−−−−−−−1 r D
From the definition of Newtonian Fluids,
τ =µ
du − − − − − − − − − − − − − − − −2 dr
Combining 1 and 2,
∆ p =
4µ l du D dr
Substituting D=2r and rearranging the above,
∆p du = − r dr 2 µ l 0
∆p R ∫ rdr du = − ∫ 2 µ l 0 u max
Integrating and substituting the limits, we get
u max
∆pR 2 = 4 µl
u max
∆pD 2 = 16 µl
But in case of laminar flow, u avg=umax/2
uavg
∆pD2 = 32µl
Therefore pressure drop per unit length, ∆p 32µV = − − − − − − − − − −3 l D2
To calculate the loss due to friction a dimensionless factor f called Darcy’s friction factor defined as f =
∆p
D ρV l 2 2
Hence
for laminar, viscous flow.
fl ρ V ∆ p= 2D
2
For laminar flow conditions, substituting 3 for Δp, 32µlν 2 f = D 2 ρV 2
D = l
64 64 = ρ νD Re µ
Energy loss due to head,
------Darcy -Weisbach Equation
hL =
∆p 1 flρV 2 flV 2 = = γ γ 2D 2 gD
( ) γ = ρg References: 1. Inspired by class (CE 331) of Dr. Nirmala Khandan