Flow Of Fluids
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Flow of Fluids
Aniline is to be cooled from 200 to 150 degrees Fahrenheit in a double-pipe heat exchanger having a total outside are For cooling a stream of toluene amounting to 8600 lb/h at a temperature of 100 degrees Fahrenheit is available. The exchanger consists of Schedule 40 ,1 and ¼ inches pipe and Schedule 40,2-inches pipe. The aniline flow rate is10 if flow is countercurrent, what are the toluene outlet temperature, the LMTD and the overall heat transfer coefficient? Cp of Aniline=0.545 BTU/lb-°F and Cp for toluene= 0.438 BTU/lb-°F. Solution:
10,000 200 °F
Aniline: q= mCP(T1-T2) q1= 150 °F 8600 100 °F
Toluene: q2 = mCp(T-100) T= ΔTLM =
Over-all heat transfer coeffi 103.17
anger having a total outside area of 70 ft². es Fahrenheit is available. s pipe. The aniline flow rate is10,000 lb/h. overall heat transfer coefficient?
q= mCP(T1-T2) 272500
q2 = mCp(T-100) 172.34 37.73
Over-all heat transfer coefficient:
Flow of Fluids
A simple U-tube manometer is installed across an orifice meter. The manometer is filled with mercury( specific gravity= 13.6), and the liquid above the mercury is carbon tetrachloride
(specific gravity of 1.6). The manometer reads 200mm. What is the pressure difference over the mano Solution:
Pa-Pb= (g/gc)Rm (ρA-ρB) 1 kg wt. = 9.8 N ΔP= 2400
g/gc= 1 Rm= 0.2 ρA= 13600 ρB= 1600
difference over the manometer in Newton per meter square?
Crude oil,specific gravity 60°F/60°F = 0.887, flows through the piping with Pipe A (2-in Schedule 40), Pipe B (3-in S and Pipe C (1 and ½ in Schedule 40). An equal quantity of liquid flows through pipe C. The flow through pipe A and Calculate the mass flow rate in each pipe. The dimension and cross-sectional areas of standard pipes pipes needed are 0.0233 ft² for a 2-in pipe, 0.0513 ft² for a 3-in pipe and 0.01414 ft² for a 1 and 1/2 pipe. Solution: Density of the fluid= 55.32 q= 240.64 Mass flowrate of A and B= ### Mass flowrate in pipe C = ###
chedule 40), Pipe B (3-in Schedule 40) e flow through pipe A and B is 30 gal/min and 1/2 pipe.
Aniline is to be cooled from 200 to 150 degrees Fahrenheit in a double-pipe heat exchanger having a total outside are For cooling a stream of toluene amounting to 8600 lb/h at a temperature of 100 degrees Fahrenheit is available. The exchanger consists of Schedule 40 ,1 and ¼ inches pipe and Schedule 40,2-inches pipe. The aniline flow rate is10 if flow is countercurrent, what are the toluene outlet temperature, the LMTD and the overall heat transfer coefficient? Cp of Aniline=0.545 BTU/lb-°F and Cp for toluene= 0.438 BTU/lb-°F. Solution:
10,000 200 °F
Aniline: q= mCP(T1-T2) q1= 150 °F 8600 100 °F
Toluene: q2 = mCp(T-100) T= ΔTLM =
Over-all heat transfer coeffi 103.17
anger having a total outside area of 70 ft². es Fahrenheit is available. s pipe. The aniline flow rate is10,000 lb/h. overall heat transfer coefficient?
q= mCP(T1-T2) 272500
q2 = mCp(T-100) 172.34 37.73
Over-all heat transfer coefficient:
Flow of Fluids
A simple U-tube manometer is installed across an orifice meter. The manometer is filled with mercury( specific gravity= 13.6), and the liquid above the mercury is carbon tetrachloride
(specific gravity of 1.6). The manometer reads 200mm. What is the pressure difference over the mano Solution:
Pa-Pb= (g/gc)Rm (ρA-ρB) 1 kg wt. = 9.8 N ΔP= 2400
g/gc= 1 Rm= 0.2 ρA= 13600 ρB= 1600
difference over the manometer in Newton per meter square?
Crude oil,specific gravity 60°F/60°F = 0.887, flows through the piping with Pipe A (2-in Schedule 40), Pipe B (3-in S and Pipe C (1 and ½ in Schedule 40). An equal quantity of liquid flows through pipe C. The flow through pipe A and Calculate the mass flow rate in each pipe. The dimension and cross-sectional areas of standard pipes pipes needed are 0.0233 ft² for a 2-in pipe, 0.0513 ft² for a 3-in pipe and 0.01414 ft² for a 1 and 1/2 pipe. Solution: Density of the fluid= 55.32 q= 240.64 Mass flowrate of A and B= ### Mass flowrate in pipe C = ###
chedule 40), Pipe B (3-in Schedule 40) e flow through pipe A and B is 30 gal/min and 1/2 pipe.
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